django返回视频流

import re
import os
import mimetypes
from wsgiref.util import FileWrapper
from django.http import StreamingHttpResponse


def file_iterator(file_name, chunk_size=8192, offset=0, length=None):
    with open(file_name, "rb") as f:
        f.seek(offset, os.SEEK_SET)
        remaining = length
        while True:
            bytes_length = chunk_size if remaining is None else min(remaining, chunk_size)
            data = f.read(bytes_length)
            if not data:
                break
            if remaining:
                remaining -= len(data)
            yield data


def stream_video(request, path):
    """将视频文件以流媒体的方式响应"""
    range_header = request.META.get('HTTP_RANGE', '').strip()
    range_re = re.compile(r'bytes\s*=\s*(\d+)\s*-\s*(\d*)', re.I)
    range_match = range_re.match(range_header)
    size = os.path.getsize(path)
    content_type, encoding = mimetypes.guess_type(path)
    content_type = content_type or 'application/octet-stream'
    if range_match:
        first_byte, last_byte = range_match.groups()
        first_byte = int(first_byte) if first_byte else 0
        last_byte = first_byte + 1024 * 1024 * 8  # 8M 每片,响应体最大体积
        if last_byte >= size:
            last_byte = size - 1
        length = last_byte - first_byte + 1
        resp = StreamingHttpResponse(file_iterator(path, offset=first_byte, length=length), status=206, content_type=content_type)
        resp['Content-Length'] = str(length)
        resp['Content-Range'] = 'bytes %s-%s/%s' % (first_byte, last_byte, size)
    else:
        # 不是以视频流方式的获取时，以生成器方式返回整个文件，节省内存
        resp = StreamingHttpResponse(FileWrapper(open(path, 'rb')), content_type=content_type)
        resp['Content-Length'] = str(size)
    resp['Accept-Ranges'] = 'bytes'
    return resp