Arcgis 与 Pixi.js 可视化 glsl 特效篇(三十)

发布时间 2023-09-22 17:24:56作者: haibalai

这次我们用pixi.js和arcgis js结合

我们先定义一下 传入数据结构 symbol 暂时不做

  • let option = {
  • renderer: {
  • type: "simple",
  • symbol: {
  • }
  • },
  • data: [
  • {
  • geometry: [12956152.73135875, 4855356.473704897],
  • attributes: {
  • name: "北京"
  • }
  • },
  • {
  • geometry: [12697872.012783196, 2577456.5937789795],
  • attributes: {
  • name: "深圳"
  • }
  • }
  • ]
  • };

 

对于data 数据 ,
toScreen 方法参考链接提示
app 的构建参考 链接提示

  • let data = this.options.data;
  • for(let item of data){
  • //转换屏幕坐标,获取颜色,半径和线条粗细样式
  • let geo = item.geometry
  • let XY1 = toScreen(geo);
  • const geometry = new PIXI.Geometry()
  • .addAttribute("position", [100, 100, -100, 100, -100, -100, 100, -100, 200, 200], 2)
  • .addAttribute('uv', // the attribute name
  • [0, 0, // u, v
  • 1, 0, // u, v
  • 1, 1,
  • 0, 1], // u, v
  • 2)
  • .addIndex([0, 1, 2, 0, 2, 3]);
  • const fragmentShader = `
  • uniform float iTime;
  • const vec2 iResolution = vec2(1.0,1.0);
  • varying vec2 vUv;
  • #define POINT_COUNT 8
  • vec2 points[POINT_COUNT];
  • const float speed = -0.5;
  • const float len = 0.25;
  • const float scale = 0.012;
  • float intensity = 1.3;
  • float radius = 0.015;
  • //
  • //Signed distance to a quadratic bezier
  • float sdBezier(vec2 pos, vec2 A, vec2 B, vec2 C){
  • vec2 a = B - A;
  • vec2 b = A - 2.0*B + C;
  • vec2 c = a * 2.0;
  • vec2 d = A - pos;
  • float kk = 1.0 / dot(b,b);
  • float kx = kk * dot(a,b);
  • float ky = kk * (2.0*dot(a,a)+dot(d,b)) / 3.0;
  • float kz = kk * dot(d,a);
  • float res = 0.0;
  • float p = ky - kx*kx;
  • float p3 = p*p*p;
  • float q = kx*(2.0*kx*kx - 3.0*ky) + kz;
  • float h = q*q + 4.0*p3;
  • if(h >= 0.0){
  • h = sqrt(h);

Arcgis 与 Pixi.js 可视化 glsl 特效篇(三十) - 小专栏