秦疆的Java课程笔记:59 数组 稀疏数组

发布时间 2023-12-05 15:45:49作者: Acolyte_9527
  • 当一个数组中大部分元素都是0,或者为同一值的数组时,可以使用稀疏数组来保存该数组。
  • 稀疏数组的处理方式是:
    • 记录数组一共有几行几列,有多少个不同值
    • 把具有不同值的元素和行列及值记录在一个小规模的数组中,从而缩小程序的规模
public class ArrayDemo1 {  
    public static void main(String[] args) {  
        //创建一个11*11的棋盘。0:没有棋子;1:黑棋;2,白棋;  
        int[][] a = new int[11][11];  
        a[1][2]=1;  
        a[2][3]=2;  
        //输出原始数组  
        System.out.println("输出原始数组:");  
        for (int[] ints:a) {  
            for (int anint : ints) {  
                System.out.print(anint + "\t");  
            }  
            System.out.println();  
        }  
        //转换为稀疏数组  
        //获取有效值个数  
        int sum = 0;  
        for (int i = 0; i < 11; i++) {  
            for (int j = 0; j < 11; j++) {  
                if (a[i][j] != 0) {  
                    sum ++;  
                }  
            }  
        }  
        System.out.println("有效值个数:" + sum);  
        //创建一个稀疏数组  
        int[][] b = new int[sum+1][3];  
        b[0][0] = 11;  
        b[0][1] = 11;  
        b[0][2] = sum;  
        //遍历二维数组,将非零的值,存放到稀疏数组中  
        int count = 0;  
        for (int i = 0; i < a.length; i++) {  
            for (int j = 0; j < a[i].length; j++) {  
                if (a[i][j] != 0) {  
                    count ++;  
                    b[count][0] = i;  
                    b[count][1] = j;  
                    b[count][2] = a[i][j];  
                }  
            }  
        }  
        //输出稀疏数组  
        System.out.println("输出稀疏数组:");  
        for (int i = 0; i < b.length; i++) {  
            System.out.println(b[i][0] + "\t"  
                    + b[i][1] + "\t"  
                    + b[i][2] + "\t");  
        }  
        //稀疏数组还原  
        System.out.println("还原:");  
        //读取稀疏数组  
        int[][] c = new int[b[0][0]][b[0][1]];  
        //给其中的元素还原值  
        for (int i = 1; i < b.length; i++) {  
            c[b[i][0]][b[i][1]] = b[i][2];  
        }  
        //打印还原数组:  
        System.out.println("输出还原数组:");  
        for (int[] ints:c) {  
            for (int anint : ints) {  
                System.out.print(anint + "\t");  
            }  
            System.out.println();  
        }  
    }  
}
====效果如下====
输出原始数组:
0	0	0	0	0	0	0	0	0	0	0	
0	0	1	0	0	0	0	0	0	0	0	
0	0	0	2	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
有效值个数:2
输出稀疏数组:
11	11	2	
1	2	1	
2	3	2	
还原:
输出还原数组:
0	0	0	0	0	0	0	0	0	0	0	
0	0	1	0	0	0	0	0	0	0	0	
0	0	0	2	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0