java stream 操作map根据key或者value排序的实现
public class Test02 {
public static void main(String[] args) {
List<FundBenchMarkInfo> fundBenchMarkList = new ArrayList<>();
fundBenchMarkList.add(new FundBenchMarkInfo("2", new BigDecimal("123"), null));
fundBenchMarkList.add(new FundBenchMarkInfo("5", new BigDecimal("12"), null));
fundBenchMarkList.add(new FundBenchMarkInfo("1", new BigDecimal("8"), null));
fundBenchMarkList.add(new FundBenchMarkInfo("7", new BigDecimal("8"), new BigDecimal("123345")));
fundBenchMarkList.add(new FundBenchMarkInfo("8", new BigDecimal("3"), new BigDecimal("90")));
fundBenchMarkList.add(new FundBenchMarkInfo("8", new BigDecimal("8"), null));
// 把list 转成 map
Map<String, FundBenchMarkInfo> collect = fundBenchMarkList.stream().collect(Collectors.toMap(t -> t.getIndexScod(), o -> o, (k1, k2) -> k1));
// map 根据 key 排序
LinkedHashMap<String, FundBenchMarkInfo> collect1 = collect.entrySet().stream()
.sorted(Map.Entry.comparingByKey())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (oldValue, newValue) -> oldValue,
LinkedHashMap::new));
Map<String, Integer> unsortMap = new HashMap<>();
unsortMap.put("z", 10);
unsortMap.put("b", 5);
unsortMap.put("a", 6);
unsortMap.put("c", 20);
unsortMap.put("d", 1);
unsortMap.put("e", 7);
unsortMap.put("y", 8);
unsortMap.put("n", 99);
unsortMap.put("g", 50);
unsortMap.put("m", 2);
// 根据key 排序
//Alternative way to sort a Map by keys, and put it into the "result" map
Map<String, Integer> result2 = new LinkedHashMap<>();
unsortMap.entrySet().stream()
.sorted(Map.Entry.comparingByKey())
.forEachOrdered(x -> result2.put(x.getKey(), x.getValue()));
// map 根据value 排序 根据value 进行降序排列
LinkedHashMap<String, Integer> collect2 = unsortMap.entrySet().stream()
.sorted(Map.Entry.comparingByValue(Comparator.reverseOrder()))
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue,
(oldV, newV) -> oldV, LinkedHashMap::new));
//Alternative way
Map<String, Integer> result3 = new LinkedHashMap<>();
unsortMap.entrySet().stream()
.sorted(Map.Entry.<String, Integer>comparingByValue().reversed())
.forEachOrdered(x -> result3.put(x.getKey(), x.getValue()));
}
}