JAVA——两个List集合求交集、并集和差集(去重)

发布时间 2023-09-20 17:08:44作者: csjoz11
public static void main(String[] args) { List<String> stringList = new ArrayList<>(); stringList.add("a"); stringList.add("b"); stringList.add("c"); stringList.add("i"); stringList.add("j"); stringList.add("a"); //一、求交集 //方法1:直接通过retainAll直接过滤 List<String> stringList1 = new ArrayList<>(Arrays.asList("a,b,c,d,e,f,g,h".split(","))); stringList1.retainAll(stringList); System.out.println("交集1: " + stringList1); //方法2:通过过滤掉存在于stringList的数据 List<String> stringList1_2 = new ArrayList<>(Arrays.asList("a,b,c,d,e,f,g,h".split(","))); List<String> strings = stringList1_2.stream() .filter(item -> stringList.contains(item)) .collect(toList()); System.out.println("交集2:" + strings); //二、并集 //有重并集 List<String> stringList2 = new ArrayList<>(Arrays.asList("a,b,c,d,e,f,g,h".split(","))); stringList2.addAll(stringList); System.out.println("并集: " + stringList2); //无重并集 List<String> stringList2_2 = new ArrayList<>(Arrays.asList("a,b,c,d,e,f,g,h".split(","))); List<String> stringList_1 = new ArrayList<>(Arrays.asList("a,b,c,i,j,a".split(","))); stringList2_2.removeAll(stringList_1); stringList_1.addAll(stringList2_2); System.out.println("无重并集: " + stringList_1); //三、求差集 //方法1:直接使用removeAll()方法 List<String> stringList3 = new ArrayList<>(Arrays.asList("a,b,c,d,e,f,g,h".split(","))); stringList3.removeAll(stringList); System.out.println("差集1: " + stringList3); //方法2:通过过滤掉不存在于stringList的数据,然后和本数组进行交集处理 List<String> stringList3_2 = new ArrayList<>(Arrays.asList("a,b,c,d,e,f,g,h".split(","))); stringList3_2.retainAll(stringList3_2.stream() .filter(item -> !stringList.contains(item)) .collect(toList())); System.out.println("差集2:" + stringList3_2); SpringApplication.run(DemoApplication.class, args); }

作者:Andya
链接:https://juejin.cn/post/6899000526613151752
来源:稀土掘金
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