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argparse-dict 相互转换

发布时间 2023-04-07 09:14:11作者: 贝壳里的星海

argparse转dict

思路：在Python程序中定义好参数列表，然后从终端读取参数列表得到argparse对象，然后将该对象转化为dict对象。

import argparse
 
# define arguments
def parse_args(args=None):
    parser = argparse.ArgumentParser()
    parser.add_argument('--Name', type=str)
    parser.add_argument('--ID', type=int)
    parser.add_argument('--At_School', type=bool)
    parser.add_argument('--Math_Score', type=float)
    return parser.parse_args(args)
 
# program entrance
if __name__ == '__main__':
    # read args from the terminal
    an_args = parse_args()
 
    # transfer the args to a dict
    args_dict = vars(an_args)
    print(args_dict)
    # use the dict
    for k in args_dict.keys():
        print(k, args_dict[k], type(args_dict[k]))

输出如下

{'Name': None, 'ID': None, 'At_School': None, 'Math_Score': None}
Name None <class 'NoneType'>
ID None <class 'NoneType'>
At_School None <class 'NoneType'>
Math_Score None <class 'NoneType'>

dict转argparse

思路：调用argparse的静态方法Namespace，自动将dict的键值对转化为argparse对象

import argparse
 
# create a dict object
a_student = {'Name': 'JACK Williams',
             'ID': 391568,
             'At_School': True,
             'Math_Score': 92.3}
 
# transfer the dict object to an ArgumentParser object
args = argparse.Namespace(**a_student)
 
print(args)
# use the ArgumentParser object
print(args.Name, type(args.Name))
print(args.ID, type(args.ID))
print(args.At_School, type(args.At_School))
print(args.Math_Score, type(args.Math_Score))

输出如下

JACK Williams <class 'str'>
391568 <class 'int'>
True <class 'bool'>
92.3 <class 'float'>