假设你有一个包含以下数据的集合：
1 const books = [ 2 { title: 'The Alchemist', author: 'Paulo Coelho', year: 1988, genre: 'Fiction', pages: 163 }, 3 { title: 'To Kill a Mockingbird', author: 'Harper Lee', year: 1960, genre: 'Fiction', pages: 281 }, 4 { title: '1984', author: 'George Orwell', year: 1949, genre: 'Science Fiction', pages: 328 }, 5 { title: 'Pride and Prejudice', author: 'Jane Austen', year: 1813, genre: 'Romance', pages: 435 }, 6 { title: 'The Great Gatsby', author: 'F. Scott Fitzgerald', year: 1925, genre: 'Fiction', pages: 180 } 7 ];
现在，我们想要将 year 字段改为 publicationYear。你可以使用 map 方法和对象解构来实现这个目标：
1 const booksWithPublicationYear = books.map(({ year, ...rest }) => { 2 return { publicationYear: year, ...rest }; 3 }); 4 5 console.log(booksWithPublicationYear);
这将返回以下结果：
1 [ 2 { publicationYear: 1988, title: 'The Alchemist', author: 'Paulo Coelho', genre: 'Fiction', pages: 163 }, 3 { publicationYear: 1960, title: 'To Kill a Mockingbird', author: 'Harper Lee', genre: 'Fiction', pages: 281 }, 4 { publicationYear: 1949, title: '1984', author: 'George Orwell', genre: 'Science Fiction', pages: 328 }, 5 { publicationYear: 1813, title: 'Pride and Prejudice', author: 'Jane Austen', genre: 'Romance', pages: 435 }, 6 { publicationYear: 1925, title: 'The Great Gatsby', author: 'F. Scott Fitzgerald', genre: 'Fiction', pages: 180 } 7 ]
在这个例子中，我们使用对象解构来将 year 字段赋值给变量 year，并使用剩余参数将其余的字段存储在 rest 中。然后，我们返回一个新的对象，该对象包含了重新命名的 publicationYear 字段和剩余的字段。最后，booksWithPublicationYear 数组包含了更新的信息，以满足我们的需求。