已知p,q,e(公钥),n(模数) 加密的数据c 求解密的数据
import gmpy2
p=9648423029010515676590551740010426534945737639235739800643989352039852507298491399561035009163427050370107570733633350911691280297777160200625281665378483
q=11874843837980297032092405848653656852760910154543380907650040190704283358909208578251063047732443992230647903887510065547947313543299303261986053486569407
e=65537
c=83208298995174604174773590298203639360540024871256126892889661345742403314929861939100492666605647316646576486526217457006376842280869728581726746401583705899941768214138742259689334840735633553053887641847651173776251820293087212885670180367406807406765923638973161375817392737747832762751690104423869019034
phi_n = (p-1)*(q-1)
n=p*q
d = gmpy2.invert(e,phi_n) #求出了私钥
m=pow(c,d,n)#私钥解密或者公钥加密
print(m)
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