1、问题的由来
在平时开发中多多少少肯定会遇到一些例如status...等特殊含义的字段值,虽然传递10:ADMIN,20:NORMAL可以解决业务需求,但是不是很直观
2、使用MP自定义枚举解决
User
package com.ly.plugins.mybatisplus;
import com.baomidou.mybatisplus.annotation.TableId;
import com.baomidou.mybatisplus.annotation.TableName;
import lombok.Data;
import lombok.experimental.Accessors;
/**
* @author : ly
*/
@Accessors(chain = true)
@TableName("user")
@Data
public class User {
@TableId
private Integer id;
private String username;
private String password;
// 自定义枚举类型
private UserType userType;
}
UserType
package com.ly.plugins.mybatisplus;
import com.baomidou.mybatisplus.annotation.IEnum;
import lombok.AllArgsConstructor;
import lombok.Getter;
/**
* @author : ly
*/
@Getter
@AllArgsConstructor
public enum UserType implements IEnum<Integer> {
ADMIN(1, "admin"),
NORMAL(2, "normal");
private Integer code;
private String val;
@Override
public Integer getValue() {
return this.code;
}
}
测试
package com.ly.plugins;
import com.ly.plugins.mybatisplus.User;
import com.ly.plugins.mybatisplus.UserMapper;
import com.ly.plugins.mybatisplus.UserType;
import org.junit.jupiter.api.Test;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.test.context.SpringBootTest;
/**
* @author : ly
*/
@SpringBootTest
public class UserMapperTest {
@Autowired
private UserMapper userMapper;
@Test
public void test01(){
User user = new User().setId(2).setUsername("lisi").setPassword("321").setUserType(UserType.NORMAL);
userMapper.insert(user);
}
@Test
public void test02(){
User user = userMapper.selectById(1);
System.out.println("user = " + user);
}
}
结果