objectives you for and

使用for循环修改对象某一属性的值,并加入到List集合中,最终List中结果都是最后一次for循环修改的值

最终打印的msgId都是最后一次设置的msgId,原因是for循环操作的都是同一个对象 解决方案,将对象放到另外一个对象中再加入到list ......
List for 属性 对象 结果

Signals and systems(1)

LEC 1 Introduction Signals Continuous signals EX1.Sound signals \(y = x(t)\) Continuous Time signal() One dimension signal(only have one variable time ......
Signals systems and

LuoguCF362B Petya and Staircases 题解

分析 简单排序题。 首先 Petya 可以通过跨过一个台阶和两个台阶保证不经过脏台阶,但是不可以通过跨过三个台阶来保证不经过脏台阶,所以只要看有没有连续的三个脏台阶即可。 同时,如果第一个台阶和最后一个台阶至少一个是脏台阶那么就不可以达成。 Accepted Code /*Code By Manip ......
题解 Staircases LuoguCF Petya 362B

[题解]CF1881G Anya and the Mysterious String

思路 发现如果一个字符串中有长度大于等于 \(2\) 回文子串,必定有长度为 \(2\) 的回文子串或长度为 \(3\) 的回文子串,并且形如:aa 和 aba。 所以考虑用线段树这两种情况。维护一段区间的最左、次左、最右、次右的元素,同时用两个标记变量 \(f_1,f_2\) 分别表示这个区间中是 ......
题解 Mysterious String 1881G 1881

Educational Codeforces Round 150 (Rated for Div. 2)

A题直接拆成 1 1 n-2 <=4时bob,否则alice B题直接模拟一下就行 C题开始想复杂了,我们直接枚举是哪个字符转成哪个字符即可,如果是变大,一定是放在最左,如果是变小,一定是放在最右,爆算即可。 D题,显然N^2dp,但是还是想错一些细节,假设按右端点排序后,当前考虑第i个区间,假设我 ......
Educational Codeforces Round Rated 150

vue中的for循环中,获取input输入框中的值的方法

1 <p v-for="item in list" :key="item.id"> 2 {{item.topic}}= 3 <!-- <input type="text" v-model="item.id" placeholder="请输入答案" > --> 4 <el-input type="te ......
方法 input vue for

【Azure 应用服务】App Service for Linux 环境中为Tomcat页面修改默认的Azure 404页面

问题描述 在App Service Linux环境中,如部署Tomcat 应用后,如果访问的页面找不到,应用会返回一个由Azure生成的404页面,那么是否可以修改它呢? PS: 如果是App Service for Windows,可以参考博文 [ App Service for Windows ......
页面 Azure 应用服务 Service 环境

Educational Codeforces Round 150 (Rated for Div. 2) B. Keep it Beautiful

数组 \(a = [a_1, a_2, \cdots, a_n]\) 被称为是美丽的,如果可以将 \([1, x]\) 段移到 \([x + 1, n]\) 段后面,\(x \geq 0\) ,数组可以构成非降序。 现在有一个数组 \(a\) (一开始为空)和 \(q\) 个询问,第 \(i\) 个 ......
Educational Codeforces Beautiful Round Rated

Detected non-NVML platform: could not load NVML: libnvidia-ml.so.1: cannot open shared object

前言 在 kubernetes 中配置 https://github.com/NVIDIA/k8s-device-plugin 时, 报错:Detected non-NVML platform: could not load NVML: libnvidia-ml.so.1: cannot open ......

Conditional Probability Models for Deep Image Compression

深度神经网络被训练来作为图像压缩的自动编码器是一个前沿方向,面临的挑战有两方面——量化(quantization)和权衡reconstruction error (distortion) and entropy (rate),这篇文章关注后者。 主要思想是使用上下文模型直接对潜在表示的熵建模;3D- ......

Go - Changing the Timing for Running Performance Tests

Problem: You want to run performance tests for a specific duration or a specific number of iterations. Solution: You can increase the minimum duration ......
Performance Changing Running Timing Tests

Go - Generating Random Test Inputs for Tests

Problem: You want to generate random test data for running your test functions. Solution: Use fuzzing , which is an automated testing technique to gen ......
Generating Random Inputs Tests Test

Internet-augmented language models through few-shot prompting for open-domain question answering阅读笔记

Internet-augmented language models through few-shot prompting for open-domain question answering 其实我没怎么正经读过论文,尤其是带实验的,我目前认真读过的(大部头)也就是一些LLM的综述。记录这个文档主 ......

[914] In Python's datetime library, you can format dates using the strftime() method

In Python's datetime library, you can format dates using the strftime() method. This method allows you to create a formatted string representation of ......
datetime strftime library Python format

论文阅读 Generalized Focal Loss: Learning Qualified and Distributed Bounding Boxes for Dense Object Detection

原始题目:Generalized Focal Loss: Learning Qualified and Distributed Bounding Boxes for Dense Object Detection 中文翻译:Generalized Focal Loss:学习用于密集目标检测的 Qual ......

CF557D D. Vitaly and Cycle

小清新分类讨论题 首先不难发现这题加边的上界就是\(3\),并且只有当图中一条边没有时才会取得,方案数就是\(C_n^3\) 而一条边不加的情况也很容易,可以先跑个染色看下有没有奇环,如果有的话就直接输出即可 而加两条边的情况也比较简单,当图中都是孤立边和孤立点时(即所有点度数均\(\le 1\)) ......
Vitaly Cycle 557D 557 and

Expression #3 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'jira.ji.ID' which is not functionally dependent on columns in GROUP BY clause;only_full_group_by

这个报错的完整信息 Expression #3 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'jira.ji.ID' which is not functionally dependent on ......

Program does not contain a static 'Main' method suitable for an entry point

http://www.kangry.net/blog/?article_id=391&type=article 修改办法,对着项目右键-》属性-》application-》output type设为Class Library即可。 ......
suitable Program contain method static

Go - Setting Up and Tearing Down Before and After Tests

Problem: You want to set up data and an environment for testing and tear it down after the test is run. Solution: You can create helper functions or u ......
and Setting Tearing Before After

3D Math for Graphics and Game笔记

这个机器人的原点在世界坐标系下的(4.5,1.5),而她右肩膀上的那个灯的模型坐标系为(-1,5),怎样计算这个灯的世界坐标呢? 开始: 获取原点,这个原点为(4.5,1.5) 向右移动一个位置,机器人的"左边"是[0.87,0.50],这样得到的位置为(4,5,1.5) + (-1)X[0.87, ......
Graphics 笔记 Math Game for

ORA-01078: failure in processing system parameters ORA-00093: pga_aggregate_limit must be between 2048M and 100000G

在启动数据库实例时报错: ORA-01078: failure in processing system parametersORA-00093: pga_aggregate_limit must be between 2048M and 100000G 原因: 该报错是由于设置的pga_aggre ......

Educational Codeforces Round 152 (Rated for Div. 2) B. Monsters

有 \(n\) 个怪物,第 \(i\) 个怪物的血量为 \(a_i\) 。英雄一次攻击可以造成 \(k\) 点伤害,但只会攻击当前生命值最高的怪物。若有多个最高血量的怪物,则选择编号最小的怪物攻击。当怪物的血量 \(\leq 0\) 时则被消灭。 输出一个排列,表示怪物被消灭的编号顺序。 容易想到, ......
Educational Codeforces Monsters Round Rated

ImportError: libcrypto.so.3: cannot open shared object file: No such file or directory

ImportError: libcrypto.so.3: cannot open shared object file: No such file or directoryBuilding wheel for pysam (pyproject.toml) ...https://github.com/ ......
file ImportError libcrypto directory cannot

Go - Using Templates for Go Web Applications

Problem: You want to use Go’s templating system to create a web application. Solution: Use the html/template package to create a web application. pack ......
Applications Templates Using Go for

Secure Code Warrior C# Basic OWASP Web Top 10 2017 8: Insecure deserialization, 9: Using Components with Known Vulnerabilities, 10: Insufficient Logging and Monitoring

Last but not least. These set challenges consist of 8: Insecure deserialization, 9: Using Components with Known Vulnerabilities, 10: Insufficient Logg ......

使用 'for' 循环遍历字典

内容来自 DOC[ https://q.houxu6.top/?s=使用 'for' 循环遍历字典](https://q.houxu6.top/?s=使用 'for' 循环遍历字典) d = {'x': 1, 'y': 2, 'z': 3} for key in d: print(key, '对应于 ......
字典 39 for

Codeforces Round 892 (Div. 2) B. Olya and Game with Arrays

一系列 \(n\) 个数组,第 \(i\) 个数组的大小 \(m_i \geq 2\) 。第 \(i\) 个数组为 \(a_{m_1}, a_{m_2}, \cdots, a_{m_i}\) 。 对于每个数组,你可以移动最多一个元素到另一个数组。 一系列 \(n\) 个数组的 \(beauty\) ......
Codeforces Arrays Round Olya Game

[CF1168C] And Reachability

And Reachability 题面翻译 题目描述 Toad Pimple 有一个整数数组 \(a_1,\dots,a_n\)。 当 \(x < y\) 且存在 \(x = p_1 < \dots < p_k = y\) 的数列 \(p\) 满足 \(a_{p_i} \& a_{p_{i+1}} ......
Reachability 1168C 1168 And CF

[题解]CF514D R2D2 and Droid Army

思路 首先,可以转化题意,找到一个极长的区间 \([l,r]\) 使得(其中 \(mx_i\) 表示 \([l,r]\) 区间中属性 \(i\) 的最大值): \[\sum_{i = 1}^{m}mx_i \leq k \]显然对于这个东西当 \(l,r\) 发生移动时,是极其好维护的,所以想到双指 ......
题解 Droid 514D Army R2D2

怎么避免v-for和v-if一起使用

背景 接手了别的项目,然后打开一个文件,看到了有个error提示信息。 大概是说不能同时使用v-for和v-if。 具体如下截图所示: 为啥不能同时使用? 其实,不能同时使用的原因,主要是会存在性能问题。 那怎么优化呢? 方法一 详情请查看: 怎么避免v-for和v-if一起使用 ......
v-for v-if for if