prompt-based specifically programming promptlang
2017 China Collegiate Programming Contest Final (CCPC-Final 2017)
Preface 今天打学校统一要求的这场CCPC2017Final,直接被打爆了,各种数学题搞得人生活不能自理 主要是H徐神开场就秒出了正确的思路,然后一心认准高斯消元然后一直想+写+调到结束都没卡过去 比赛最后20min的时候祁神想到了更好写的基于施密特正交化的方法,可以碍于时间有限没调出来 不过 ......
2022 China Collegiate Programming Contest (CCPC) Weihai Site
Preface VP到自己学校出的题了可海星,不得不说学长们出的题比起昨天VP的CCPC2022广州做起来要舒服地多 这场前面写题都很顺基本都是一发过,中期的medium也没怎么卡思路和卡机子,一道一道地慢慢出 最后一个小时徐神RushF可惜没Rush出来,然后我和祁神坐在下面把B的做法给搞出来了, ......
2022 China Collegiate Programming Contest (CCPC) Guangzhou Onsite
Preface 好难啊这场广州站,不愧是5题金4题铜的超恶劣站,中档题普遍难度较高 但我感觉主要原因还是题目出的太偏向于DP了,AI是本质差不多的树上换根DP,M又是个数位DP,导致像我这种不擅长DP的人直接中期坐牢 但好在祁神大力切出了medium~hard的K题,然后最后一小时我把一直在想的A题 ......
2022 China Collegiate Programming Contest (CCPC) Mianyang Onsite
Preface 久违地VP一场,由于CCPC桂林在即因此最近就自主VP一下去年的CCPC 这场打的时候全队不在状态,签完到后我就因为A题一个corner case没考虑到卡了快两个小时 然后好不容易搞过去徐神上来有狂WA E题,最后也是喜提+11 后面写的D题也是需要特判,好家伙又是快到比赛结束才看 ......
Gym 104270 The 2018 ICPC Asia Qingdao Regional Programming Contest (The 1st Universal Cup, Stage 9: Qingdao)
A. Sequence and Sequence B. Kawa Exam 可以发现,对答案会产生影响的只有割边,把所有边双缩起来,然后就是一个森林。 考虑一个树的时候怎么做,就是对于每条边求出这条边两端的众数个数,考虑线段树合并,每次动态维护子树内的众数和子树外的众数。 #include<iost ......
Windows: run all program as administrator
pgedit.msc secpol.msc 当然如果如果是家庭版用户没有组策略是无法像上述一样操作的,我们可以打开注册表编辑器(运行regedit),展开注册表到 HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Policie ......
2022 China Collegiate Programming Contest (CCPC) Mianyang Onsite GCHMAD
2022 China Collegiate Programming Contest (CCPC) Mianyang Onsite 目录2022 China Collegiate Programming Contest (CCPC) Mianyang OnsiteVP 情况G - Let Them E ......
The 2021 China Collegiate Programming Contest (Harbin) JBEIDG
The 2021 China Collegiate Programming Contest (Harbin) 目录The 2021 China Collegiate Programming Contest (Harbin)VP概况J - Local MinimumB - Magical Subseq ......
Gym 104172 The 2023 ICPC Asia Hong Kong Regional Programming Contest (The 1st Universal Cup, Stage 2Hong Kong)
A. TreeScript 令 \(f_u\) 表示 \(u\) 及 \(u\) 子树中的节点都创建的最小数量。 如果 \(u\) 只有一个儿子,那么可以将子树最后一个节点存储在当前的 \(u\) 中,答案就是 \(f_v\)。 若 \(u\) 有多个儿子: 令 \(t=\max\limits_{v ......
KEYENCE Programming Contest 2019
A - Beginning 排序以后判断一下是否为 \(1,4,7,9\) 即可。 #include<iostream> #include<cstdio> #include<algorithm> using namespace std; const int N=10; int a[N]; int m ......
NIKKEI Programming Contest 2019
A - Subscribers 最小值为 \(\min(A,B)\),最大值为 \(\max(A+B-n,0)\)。 #include<iostream> #include<cstdio> using namespace std; int n,A,B; int main() { scanf("%d% ......
NOMURA Programming Competition 2020
A - Study Scheduling 先算出总时间,然后在减去 \(K\) 就好了。 代码: #include<iostream> #include<cstdio> using namespace std; int h1,m1,h2,m2,k; int main() { scanf("%d%d% ......
Yahoo Programming Contest 2019
A - Anti-Adjacency 合法的条件即为 \(k\leq \lceil \frac{n}{2} \rceil\)。 #include<iostream> #include<cstdio> using namespace std; int n,k; int main() { scanf(" ......
Social Infrastructure Information Systems Division, Hitachi Programming Contest 2020
A - Hitachi String 满足条件的串即为串长为偶数且相邻两个均为为 hi,直接判断即可。 代码: #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int N=15; int ......
Tokio Marine & Nichido Fire Insurance Programming Contest 2020
A - Nickname 直接输出前三个字符。 代码: #include<iostream> #include<cstdio> using namespace std; const int N=25; char s[N]; int main() { scanf("%s",s+1); printf(" ......
Keyence Programming Contest 2020
A - Painting 每次取 \(H,W\) 中较大者涂就是了,输出 \(\lceil \frac{n}{\max(H,W)}\rceil\)。 代码: #include<iostream> #include<cstdio> using namespace std; int h,w,n; int ......
diverta 2019 Programming Contest 2
A - Ball Distribution \(k=1\) 时答案为 \(0\),否则答案为 \(n-k\)。 #include<iostream> #include<cstdio> using namespace std; int n,k; int main() { scanf("%d%d",&n ......
Dwango Programming Contest V
A - Thumbnail 直接按照题意模拟。。。 #include<iostream> #include<cstdio> #include<cmath> using namespace std; const int N=105; int n; int a[N]; int main() { scan ......
NIKKEI Programming Contest 2019-2
A - Sum of Two Integers 分奇偶讨论一下就好了,答案为 \(\lfloor \frac{n-1}\{2\}\rfloor\)。 #include<iostream> #include<cstdio> using namespace std; int n; int main() ......
Dwango Programming Contest 6th
A - Falling Asleep 找到第一个相等的位置,然后暴力往后加就是了。 #include<iostream> #include<cstdio> using namespace std; const int N=55; int n; string s[N]; string t; int a ......
M-SOLUTIONS Programming Contest
A - Sum of Interior Angles 答案为 \(180(n-2)\)。 #include<iostream> #include<cstdio> using namespace std; int n; int main() { scanf("%d",&n); printf("%d", ......
diverta 2019 Programming Contest
A - Consecutive Integers 答案为 \(n-k+1\)。 #include<iostream> #include<cstdio> using namespace std; int n,k; int main() { scanf("%d%d",&n,&k); printf("%d ......
CS61A: Structure and Interpretation of Computer Programs 笔记
Functions Environment Diagrams:左侧为 Frames,右侧为 Objects。 Name 类似变量名,它们存储在 Frame 中,指向各种各样的 Objects,比如值或函数。一个 Name 同时只能指向一个 Object,但可以改变自身指向,不受“类型”影响(Name ......
Go - Using channels to receive interrupts in a program
Within the Kubernetes deployment environment, applications will actually be sent the SIGTERM signal first if it has been decided the pod holding the a ......
2021-2022 ICPC Northwestern European Regional Programming Contest (NWERC 2021)
A. Access Denied 先问若干次,问出长度,然后再一位一位的问即可。 #include <bits/stdc++.h> using namespace std; int input() { string s; getline(cin, s); if (s == "ACCESS GRANT ......
The 2021 China Collegiate Programming Contest (Harbin) JBEID
The 2021 China Collegiate Programming Contest (Harbin) JBEID J. Local Minimum 模拟 题意:一个数当且仅当它是当前列最小值同时也是当且行的最小值它才算入贡献。 思路:直接\(for\),预处理出每一行每一列的最小值,然后去\ ......
更新wsl,docker无法启动wrong fs type, bad option, bad superblock on cgroup, missing codepage or helper program, or other error.解决方案
PS C:\Users\xxxx> wsl -vWSL 版本: 2.0.0.0内核版本: 5.15.123.1-1WSLg 版本: 1.0.57MSRDC 版本: 1.2.4485Direct3D 版本: 1.608.2-61064218DXCore 版本: 10.0.25880.1000-2306 ......
2019, XII Samara Regional Intercollegiate Programming Contest
\(Problem A. Rooms and Passages\) 倒着处理每个位置正数的最前部的位置。 如果是正数,显然答案为后一个位置的答案 \(+1\) 。 如果是负数且前面出现过相应的正数,答案要对这个区间长度 \(-1\) 的取 \(min\) 。 void solve(){ int n= ......
Parallel Programming Basic
Learn about the difference between time-efficiency(more important) and work-efficiency parallel loop Relative instruction set SSE(Streaming SIMD Exten ......
2022-2023 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2022)
F. Foreign Football 一共有\(n\)支队伍,每支队伍的名称为\(s_i\),给定一个\(n \times n\)的矩阵,\(a_{i,j}\)代表第\(i\)支队伍和第\(j\)支队伍名字的拼接,即\(a_{i,j}=s_i+s_j\),请你通过该矩阵推断出所有队伍的名称,如果有 ......