【LBLD】东哥带你刷二叉树(纲领篇)

发布时间 2023-04-19 10:46:49作者: 杨谖之

东哥带你刷二叉树(纲领篇)

104. 二叉树的最大深度

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    int maxDepth(TreeNode* root) {
        if (!root) {
            return 0;
        }
        int left = maxDepth(root->left);
        int right = maxDepth(root->right);
        return left > right ? left + 1 : right + 1;
    }
};
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
private:
    int res = 0;
    int depth = 0;
public:
    int maxDepth(TreeNode* root) {
        if (!root) {
            return 0;
        }
        int left = maxDepth(root->left);
        int right = maxDepth(root->right);
        return left > right ? left + 1 : right + 1;
    }

    void traverse (TreeNode* root) {
        if (root == nullptr) {
            return;
        }
        depth++;
        if (root->left == nullptr && root->right == nullptr) {
            res = max(res, depth);
        }
        traverse(root->left);
        traverse(root->right);
        depth--;
    }
};

144. 二叉树的前序遍历

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
private:
    vector<int> preOrder;
public:
    vector<int> preorderTraversal(TreeNode* root) {
        traverse(root);
        return preOrder;
    }

    void traverse(TreeNode* root) {
        if (root == nullptr) return;
        preOrder.push_back(root->val);
        traverse(root->left);
        traverse(root->right);
    }
};

543. 二叉树的直径

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
private:
    int res;
public:
    int diameterOfBinaryTree(TreeNode* root) {
        res = 0;
        int traceLength = maxDepth(root->left) + maxDepth(root->right);
        return max(traceLength, res);
    }

    int maxDepth(TreeNode* root) {
        if (root == nullptr) return 0;
        int left = maxDepth(root->left);
        int right = maxDepth(root->right);
        int traceLength = left + right;
        res = max(traceLength, res);
        return max(left, right) + 1;
    }
};