单词覆盖还原(luogu水题)

#include<iostream>
#include<cstring>
using namespace std;
int main(){
    char c[256];
    cin>>c;
    int l=strlen(c),m=0,g=0;
    for(int i=0;i<l;i++){
        if(c[i]=='b')m++;
        if(c[i]=='o'&&c[i-1]!='b')m++;
        if(c[i]=='y'&&c[i-1]!='o'&&c[i-2]!='b')m++;

        if (c[i]=='g') g++;
        if (c[i]=='i'&&c[i-1]!='g') g++;
        if (c[i]=='r'&&c[i-1]!='i'&&c[i-2]!='g') g++;
        if (c[i]=='l'&&c[i-1]!='r'&&c[i-2]!='i'&&c[i-3]!='g') g++;
    }
    cout<<m<<'\n'<<g<<endl;
    return 0;
}