python加减法无重复-526互联

import random


def add():
    '''
    获取随机的加法
    :return:
    '''
    a = random.randint(0, 19)
    b = random.randint(0, 19 - a)
    return a, b, a + b


def sub():
    '''
    获取随机的减法
    :return:
    '''
    a = random.randint(0, 19)
    b = random.randint(0, a)
    return a, b, a - b


def test(n):
    '''
    获取n道20以内的加减法题目，无重复
    :param n:
    :return:
    '''
    res_d = {0: [], 1: []}
    sig_d = {0: add, 1: sub}
    i = 0
    while i < n:
        sig = random.randint(0, 1)
        method = sig_d[sig]
        a, b, r = method()
        while [a, b, r] in res_d[sig] or [b, a, r] in res_d[sig]:
            a, b, r = method()
        res_d[sig].append([a, b, r])
        i += 1
    return res_d


if __name__ == '__main__':
    res_d = test(30)
    for key, value in res_d.items():
        sign = '-'
        if key == 0:
            sign = '+'
        for a, b, r in value:
            print(a, sign, b, '=')