以Vehicle为基类,构建出Car、Truck和Bus三个类。
Car的收费公式为: 载客数*8+重量*2
Truck的收费公式为:重量*5
Bus的收费公式为: 载客数*3
生成上述类并编写主函数
主函数根据输入的信息,相应建立Car,Truck或Bus类对象,对于Car给出载客数和重量,Truck给出重量,Bus给出载客数。假设载客数和重量均为整数
输入格式:第一行输入测试用例数。接着每个测试用例占一行,每行给出汽车的基本信息,第一个数据为当前汽车的类型:1为car,2为Truck,3为Bus。第二个数据为它的编号,接下来Car是载客数和重量,Truck要求输入重量,Bus要求输入载客数。
要求输出各车的编号和收费。
#include<iostream> #include <string> using namespace std; class Vehicle { protected: string NO;//编号 public: Vehicle(string n){ NO = n; } virtual int fee()=0;//计算应收费用 }; class Car:public Vehicle{ public: Car(string no,int g,int w):Vehicle(no) { guest=g; weight=w; } int fee(){return guest*8+weight*2;} protected: int guest; int weight; }; class Truck:public Vehicle { public: Truck(string no,int w):Vehicle(no) { weight=w; } int fee(){return weight*5;} protected: int weight; }; class Bus:public Vehicle { public: Bus(string no,int g):Vehicle(no){ guest=g; } int fee(){return guest*3;} protected: int guest; }; int main() { Car c("",0,0); Truck t("",0); Bus b("",0); int i, repeat, ty, weight, guest; string no; cin>>repeat; for(i=0;i<repeat;i++){ cin>>ty>>no; switch(ty){ case 1: cin>>guest>>weight; c=Car(no, guest, weight); cout<<no<<' '<<c.fee()<<endl; break; case 2: cin>>weight; t=Truck(no, weight); cout<<no<<' '<<t.fee()<<endl; break; case 3: cin>>guest; b=Bus(no, guest); cout<<no<<' '<<b.fee()<<endl; break; } } return 0; }