1、实验1
运行结果
2、实验2
源代码
1 #include <stdio.h> 2 #include <string.h> 3 #define N 10 4 #define M 80 5 6 typedef struct { 7 char name[M]; // 书名 8 char author[M]; // 作者 9 } Book; 10 11 int main() { 12 Book x[N] = { {"《一九八四》", "乔治.奥威尔"}, 13 {"《美丽新世界》", "赫胥黎"}, 14 {"《昨日的世界》", "斯蒂芬.茨威格"}, 15 {"《万历十五年》", "黄仁宇"}, 16 {"《一只特立独行的猪》", "王小波"}, 17 {"《百年孤独》", "马尔克斯"}, 18 {"《查令十字街84号》", "海莲.汉芙"}, 19 {"《只是孩子》", "帕蒂.史密斯"}, 20 {"《刀锋》", "毛姆"}, 21 {"《沉默的大多数》", "王小波"} }; 22 Book *ptr; 23 int i; 24 char author[M]; 25 26 printf("所有图书信息:\n"); 27 for(ptr = x;ptr < x + N;++ptr) 28 printf("%-30s%-30s\n",ptr->name,ptr->author); 29 30 printf("\n输入作者名："); 31 gets(author); 32 for(ptr = x;ptr < x + N;++ptr) 33 if(strcmp(ptr -> author, author)==0){ 34 printf("%-30s%-30s\n",ptr->name,ptr->author); 35 } 36 return 0; 37 }
运行结果
3、实验3.1
源代码
1 #include<stdio.h> 2 #include<stdlib.h> 3 #define N 80 4 5 typedef struct Filminfo{ 6 char name[N]; 7 char director[N]; 8 char region[N]; 9 int year; 10 struct Filminfo *next; 11 }Film; 12 13 void output(Film *head); 14 Film *insert(Film *head,int n); 15 16 int main() 17 { 18 int n; 19 Film *head; 20 21 head = NULL; 22 printf("输入影片数目："); 23 scanf("%d",&n); 24 head = insert(head,n); 25 26 printf("\n所有影片信息如下：\n"); 27 output(head); 28 29 return 0; 30 } 31 32 Film *insert(Film *head,int n) 33 { 34 int i; 35 Film *p; 36 for(i = 1;i<= n;++i){ 37 p = (Film*)malloc(sizeof(Film)); 38 printf("请输入第%d部影片信息：",i); 39 scanf("%s %s %s %d",p->name,p->director,p->region,&p->year); 40 41 p->next = head; 42 head = p; 43 } 44 45 return head; 46 47 } 48 void output(Film *head) 49 { 50 Film *p; 51 52 p = head; 53 while(p != NULL){ 54 printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year); 55 p = p->next; 56 } 57 }
运行结果
实验3.2
源代码
1 #include<stdio.h> 2 #include<stdlib.h> 3 #define N 80 4 5 typedef struct Filminfo{ 6 char name[N]; 7 char director[N]; 8 char region[N]; 9 int year; 10 struct Filminfo *next; 11 }Film; 12 13 void output(Film *head); 14 Film *insert(Film *head,int n); 15 16 int main() 17 { 18 int n; 19 Film *head; 20 Film *p; 21 22 p = (Film*)malloc(sizeof(Film)); 23 p->next = NULL; 24 head = p; 25 printf("输入影片数目："); 26 scanf("%d",&n); 27 28 head = insert(head,n); 29 30 printf("\n所有影片信息如下：\n"); 31 output(head); 32 33 return 0; 34 } 35 36 Film *insert(Film *head,int n) 37 { 38 int i; 39 Film *p; 40 for(i = 1;i<= n;++i){ 41 p = (Film*)malloc(sizeof(Film)); 42 printf("请输入第%d部影片信息：",i); 43 scanf("%s %s %s %d",p->name,p->director,p->region,&p->year); 44 45 p->next = head->next; 46 head->next = p; 47 } 48 49 return head; 50 51 } 52 void output(Film *head) 53 { 54 Film *p; 55 56 p = head; 57 while(p != NULL){ 58 printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year); 59 p = p->next; 60 } 61 }
运行结果
4、实验4
源代码
1 #include <stdio.h> 2 #define N 10 3 4 typedef struct { 5 char isbn[20]; // isbn号 6 char name[80]; // 书名 7 char author[80]; // 作者 8 double sales_price; // 售价 9 int sales_count; // 销售册数 10 } Book; 11 12 void output(Book x[], int n); 13 void sort(Book x[], int n); 14 double sales_amount(Book x[], int n); 15 16 int main() { 17 Book x[N] = {{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}, 18 {"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16}, 19 {"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27}, 20 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, 21 {"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42}, 22 {"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39}, 23 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, 24 {"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31}, 25 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, 26 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}}; 27 28 printf("图书销量排名: \n"); 29 sort(x, N); 30 output(x, N); 31 32 printf("\n图书销售总额: %.2f\n", sales_amount(x, N)); 33 34 return 0; 35 } 36 37 // 待补足：函数output()实现 38 // ××× 39 void output(Book x[],int n) 40 { 41 double s; 42 int i; 43 printf("ISBN号\t\t\t书名\t\t\t 作者\t\t\t售价\t\t\t销售册数\n"); 44 for(i = 0;i < n;i++){ 45 printf("%-20s %-30s%-20s% %-10g %d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count); 46 } 47 48 } 49 50 // 待补足：函数sort()实现 51 // ××× 52 void sort(Book x[],int n) 53 { 54 int i,j; 55 Book t; 56 for(i = 0;i<n-1;i++){ 57 for(j = i;j<=n-2;j++){ 58 if(x[j+1].sales_count>x[j].sales_count){ 59 t = x[j]; 60 x[j] = x[j+1]; 61 x[j+1] = t; 62 } 63 } 64 } 65 66 } 67 68 // 待补足：函数sales_count()实现 69 // ××× 70 double sales_amount(Book x[],int n) 71 { 72 int i; 73 double s=0; 74 for(i = 0;i < n;i++){ 75 s+= x[i].sales_price*x[i].sales_count*1.0; 76 } 77 return s; 78 }
运行结果
5、实验5
源代码
1 #include<stdio.h> 2 3 typedef struct{ 4 int year; 5 int month; 6 int day; 7 }Date; 8 9 void input(Date *pd); 10 int day_of_year(Date d); 11 int compare_dates(Date d1,Date d2); 12 13 void test1() 14 { 15 Date d; 16 int i; 17 18 printf("输入日期：（以形如2023-12-11这样的形式输入\n"); 19 for(i = 0;i<3;++i){ 20 input(&d); 21 printf("%d-%02d-%02d是这一年中的第%d天\n\n",d.year,d.month,d.day,day_of_year(d)); 22 } 23 } 24 25 void test2() 26 { 27 Date Alice_birth,Bob_birth; 28 int i; 29 int ans; 30 31 printf("输入Alice和Bob出生日期：（以形如2023-12-11这样的形式输入\n"); 32 for(i = 0;i<3;++i) 33 { 34 input(&Alice_birth); 35 input(&Bob_birth); 36 ans = compare_dates(Alice_birth,Bob_birth); 37 38 if(ans == 0) 39 printf("Alice和Bob一样大\n\n"); 40 else if(ans == -1) 41 printf("Alice比Bob大\n\n"); 42 else 43 printf("Alice比Bob小\n\n"); 44 45 } 46 } 47 int main() 48 { 49 printf("测试1：输入日期，打印输出这是一年中第多少天\n"); 50 test1(); 51 52 printf("\n测试2：两个人年龄大小关系\n"); 53 test2(); 54 } 55 void input(Date *pd) 56 { 57 scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day); 58 } 59 int day_of_year(Date d) 60 { 61 int s[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31}; 62 if(d.year%4 == 0&&d.year%400 == 0||d.year%4 == 0) 63 s[2] = 29; 64 int sum=0, i; 65 for(i = 1;i<=d.month-1;i++) 66 { 67 sum += s[i]; 68 } 69 sum+=d.day; 70 return sum; 71 } 72 int compare_dates(Date d1,Date d2) 73 { 74 int ans; 75 if(d1.year<d2.year){ 76 ans = -1; 77 } 78 else if(d1.year>d2.year){ 79 ans = 2; 80 } 81 else{ 82 if(d1.month<d2.month) 83 ans=-1; 84 else if(d1.month>d2.month) 85 ans=2; 86 else { 87 if(d1.day<d2.day) 88 ans = -1; 89 else if(d1.day>d2.day) 90 ans = 2; 91 else 92 ans = 0; 93 } 94 } 95 return ans; 96 }
运行结果
6、实验6
源代码
1 #include<stdio.h> 2 #include<string.h> 3 4 enum Role{admin,student,teacher}; 5 6 typedef struct{ 7 char username[20]; 8 char password[20]; 9 enum Role type; 10 }Account; 11 12 void output(Account x[],int n); 13 14 int main() 15 { 16 Account x[]={{"A1001","123456",student}, 17 {"A1002","123abcdef",student}, 18 {"A1009","xyz12121",student}, 19 {"X1009","9213071x",admin}, 20 {"C11553","129dfg32k",teacher}, 21 {"x3005","9221kfmg917",student}}; 22 int n; 23 n = sizeof(x)/sizeof(Account); 24 output(x,n); 25 26 return 0; 27 } 28 void output(Account x[],int n) 29 { 30 int i,j,k; 31 for(i = 0;i<n;i++){ 32 printf("%s\t",x[i].username); 33 j = strlen(x[i].password); 34 35 for(k = 0;k<j;k++) 36 printf("*"); 37 if(j<7){ 38 printf("\t\t"); 39 } 40 else{ 41 printf("\t"); 42 } 43 switch(x[i].type){ 44 case admin:printf("admin");break; 45 case student:printf("student");break; 46 case teacher:printf("teacher");break; 47 } 48 printf("\n"); 49 } 50 }
运行结果
