函数连续,原函数连续且可导

发布时间 2023-03-30 22:09:18作者: __yomi

函数连续,原函数连续且可导

\(\phi(x + \bigtriangleup x)\) = \(\int_{a}^{x + \bigtriangleup x}\)dt

  • $\bigtriangleup \phi = \phi(x + \bigtriangleup x) - \phi (x) $
  • = $\int_{a}^{x + \bigtriangleup x} f(x)dt - \int_{a}^{x}f(x) dt $
  • = $\int_{a}^{x + \bigtriangleup x} f(x)dt + \int_{x}^{a}f(x) dt $
  • = \(\int_{x}^{x + \bigtriangleup x} f(x)dt\)
    根据牛顿-莱布尼兹公式:\(\int_{x}^{x + \bigtriangleup x} f(x)dt = \phi(x + \bigtriangleup x) - \phi (x)\)
    根据拉格朗日中值定理
    \(\phi(x + \bigtriangleup x) - \phi (x) = \phi(\xi) * \bigtriangleup x\)

    =>\(\bigtriangleup \phi = f(\xi) \bigtriangleup x\)
    => \(\frac {\bigtriangleup \phi}{\bigtriangleup x} = f(\xi)\)