A. Two Vessels
简单题。先计算杯子a和杯子b里水的差值,在计算需要用c杯子舀几次水就行
\[Ans=ceil(|a-b|/2c)
\]
代码
#include <bits/stdc++.h>
#define endl '\n'
using namespace std;
int t;
int a, b, c;
signed main()
{
std::ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
cin >> t;
while(t--)
{
cin >> a >> b >> c;
cout << ceil(abs(a - b) * 1.0 / 2 / c) << endl;
}
return 0;
}