hong kong programming the
The 2022 ICPC Asia Hangzhou Regional Programming Contest
The 2022 ICPC Asia Hangzhou Regional Programming Contest No Bug No Game #include<bits/stdc++.h> using namespace std; #define endl "\n" #define int lon ......
The 2022 ICPC Asia Nanjing Regional Contest
链接：[https://codeforces.com/gym/104128](https://codeforces.com/gym/104128) ## A. Stop, Yesterday Please No More ```cpp #include "bits/stdc++.h" using n ......
The 18th Heilongjiang Provincial Collegiate Programming Contest
链接：[https://codeforces.com/gym/104363](https://codeforces.com/gym/104363) ## A. Magic Computer ```cpp #include "bits/stdc++.h" using namespace std; us ......
The 10th Shandong Provincial Collegiate Programming Contest
链接：[https://codeforces.com/gym/104459](https://codeforces.com/gym/104459) ## A ```cpp #include "bits/stdc++.h" using namespace std; using i64 = long l ......
The 17th Chinese Northeast Collegiate Programming Contest
链接：[https://codeforces.com/gym/104366](https://codeforces.com/gym/104366) ## A. Cask Effect ```cpp #include "bits/stdc++.h" using namespace std; using ......
安装cocoapods: Error installing cocoapods: The last version of activesupport (>= 5.0, < 8) to support your Ruby & RubyGems was 6.1.7.6. Try installing it with `gem install activesupport -v 6.1.7.6`问题解决
问题描述: 在终端命令行安装cocoapods时,可能出现如下问题: Error installing cocoapods: The last version of activesupport (>= 5.0, < 8) to support your Ruby & RubyGems was 6.1 ......
[LeetCode] 2433. Find The Original Array of Prefix Xor
You are given an integer array pref of size n. Find and return the array arr of size n that satisfies: pref[i] = arr[0] ^ arr[1] ^ ... ^ arr[i]. Note ......
大模型时代的推荐系统Recommender Systems in the Era of Large Language Models (LLMs)
文章地址：https://arxiv.org/abs/2307.02046 笔记中的一些小实验中的模型都是基于GPT-3.5架构的ChatGPT模型。 本文主要讲述了比较具有代表性的方法利用LLM去学习user和item的表示，从预训练、微调和提示三个范式回顾了近期用于增强推荐系统的LLM先进技术， ......
error: The following untracked working tree files would be overwritten by merge
错误内容如下： error: The following untracked working tree files would be overwritten by merge: xxx/xxx/xxx/xxx/xxx/xxx/xxx.java Please move or remove them b ......
The 2nd Universal Cup. Stage 1: Qingdao
### G #### Description 给定一个数列，每次ban一个位置，在每次ban之前，求连续子序列逆序对数的最大值，强制在线。（6s）$n\leq10^5, \sum n \leq10^6$ #### Solution 先考虑用权值线段树来维护区间逆序对数，不难支持在原数列前后加或删除一 ......
The colossus
BY SYLVIA PLATH I shall never get you put together entirely, Pieced, glued, and properly jointed. Mule-bray, pig-grunt and bawdy cackles Protected fro ......
2023-2024 ICPC German Collegiate Programming Contest (GCPC 2023)
# Preface 好久没队里一起训练了就周末约了队友去机房VP了一场，同时终于学会了撬机房门这一核心技术 这场总体打的还行，但主要是B全队集体想复杂导致最后没调出来，J徐神写的维护啥的都没问题就是算答案的时候没想清楚，本来可以出11题的 # A. Adolescent Architecture 2 ......
E. Ina of the Mountain 优先队列
题意：给你一个长度为n的序列。问你最少进行多少次操作，使得最终整个序列的值都为k 操作：选一段区间，然后把这段区间的数全减一。 这个序列还有一个特性，就是当一个数为0时，这个数会变成k。 解法：一眼丁真P1969 [NOIP2013 提高组] 积木大赛 - 洛谷 | 计算机科学教育新生态 (luog ......
The native HTML dialog tag All In One
The native HTML dialog tag All In One
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What's the best approach for generating a new API key?
https://stackoverflow.com/questions/14412132/whats-the-best-approach-for-generating-a-new-api-key Edit: I've spoke to a few friends (email/twitter) an ......
CF1848B Vika and the Bridge 题解
# CF1848B Vika and the Bridge 题解 ## 题目大意 ~~给个题目传送门吧，感觉题意已经很清楚了~~ [题目传送门](https://www.luogu.com.cn/problem/CF1848B) ## 分析 （~~我不会告诉你我第一眼看过去是二分~~） 因为我们只能 ......
1335B - Construct the String
## B. Construct the String https://codeforces.com/problemset/problem/1335/B #### 分析： 首先不要被他的示例迷惑掉，这个问题可以看作若干个小问题 Q： 1. 如何简单的构造a个长度里有b个不同的值 2. 如何是n里的所有 ......
Implementing Domain Driven Design (A practical guide for implementing the Domain Driven Design with the ABP Framework)
##CONTENTS **Introduction**.................................................. * **Goal**...................................................... * **Sim ......
266B - Queue at the School
## A. Team [https://codeforces.com/problemset/problem/266/B](https://codeforces.com/problemset/problem/266/B) ##### During the break the schoolchildre ......
C. The Football Season 数学exgcd
题意： 给你四个数，n,p,d,w。让你求出任意一组x，y，z，要满足下面的条件 做法： 对于第一个式子，我们可以先用exgcd求出合法的解，在他的整个解系中进行mod(k)+k再mod(k)的操作，判断x和y能否同时非负。 对于第二个式子，我们要让z非负，那么x+y要尽可能小。而还要满足第一个式子 ......
AtCoder Beginner Contest 317 C - Remembering the Days
# C - Remembering the Days [原题链接](https://atcoder.jp/contests/abc317/tasks/abc317_c) 题意：每个点最多经过一次，求最长路 思路：数据范围很小，深搜每个点能到其他点的所有路，取最大 ```c++ #include us ......
【CF1503A】Balance the Bits（构造）
**题目大意：** *** ```cpp #include using namespace std; typedef long long ll; ll n; char s[200000+10]; char a[200000+10],b[200000+10]; int main(){ ios::syn ......
The 2022 ICPC Asia Nanjing Regional Contest
# [The 2022 ICPC Asia Nanjing Regional Contest](https://codeforces.com/gym/104128) [出题人题解](https://sua.ac/wiki/2022-icpc-nanjing/) [TOC] vp的不是很好，就不放出来 ......
What's the difference between Async Await and Promise in JavaScript All In One
# What's the difference between Async Await and Promise in JavaScript All In One > `Async` vs `Promise` ## demos --> ## (🐞 反爬虫测试！打击盗版⚠️）如果你看到这个信息, 说明 ......
The repository 'http://mirrors.163.com/debian jessie Release' does not have a Release file.
设置Debian源为国内网易源 tee /etc/apt/sources.list << EOF deb http://mirrors.163.com/debian/ jessie main non-free contrib deb http://mirrors.163.com/debian/ je ......
CF1174E Ehab and the Expected GCD Problem 题解
## 题意 对于一个排列 $p$，定义 $g$ 为 $p$ 的前缀最大公约数序列，即 $g_i = \gcd\limits_{j = 1}^{i} p_j$。定义 $f(p)$ 为 $g$ 的元素种类数。 给定 $n$，求长度为 $n$ 的且使得 $f(p)$ 取最大值的排列个数，对 $10^9 + ......
how to get the SVG document content that inside a object tag in javascript
# how to get the SVG document content that inside a object tag in javascript > object tag & SVG document content in javascript ## demos ```js ``` ![im ......
Proj CDeepFuzz Paper Reading: AutoML: A survey of the state-of-the-art
## Abstract Github: https://github.com/marsggbo/automl_a_survey_of_state_of_the_art 本文： 1. intro AutoML methods: data preparation, feature engineering ......
G. The Great Equalizer
G. The Great Equalizer 通过分析之后得知，每次询问的答案就是当前数组中的最大值和当下数组排序后相邻元素差值的最大值之和。 接下来考虑如何维护数组。这会想到用一颗二叉平衡搜索树来实现。这样的一颗树在STL里已经用multiset封装好了，直接使用即可。 创建两个辅助函数add(i ......
Programming abstractions in C阅读笔记：p139-p143
《Programming Abstractions In C》学习第55天，p139-p140，总结如下： # 一、技术总结 ## 1.文件I/O操作 文件I/O操作可以分为一下这些步骤： (1)声明文件指针对象。 ```c File *infile; ``` (2)打开文件 fopen()。打开文 ......