maximum prefix 1810 the

The 2nd Universal Cup. Stage 1: Qingdao

### G #### Description 给定一个数列,每次ban一个位置,在每次ban之前,求连续子序列逆序对数的最大值,强制在线。(6s)$n\leq10^5, \sum n \leq10^6$ #### Solution 先考虑用权值线段树来维护区间逆序对数,不难支持在原数列前后加或删除一 ......
Universal Qingdao Stage The 2nd

The colossus

BY SYLVIA PLATH I shall never get you put together entirely, Pieced, glued, and properly jointed. Mule-bray, pig-grunt and bawdy cackles Protected fro ......
colossus The

Caused by: java.sql.SQLSyntaxErrorException: ORA-00923: 未找到要求的 FROM 关键字 和 ORA-01000 maximum open cursors exceeded

最终是,查询条件,入参为null,所导致。 JDBC getParameterType call failed - using fallback method instead RA-00923: FROM keyword not found where expected 进一步,这个错误,在job执 ......

什么是MTU(Maximum Transmission Unit)?

IP知识百科 > MTU 什么是MTU(Maximum Transmission Unit)? 最大传输单元MTU(Maximum Transmission Unit,MTU),是指网络能够传输的最大数据包大小,以字节为单位。MTU的大小决定了发送端一次能够发送报文的最大字节数。如果MTU超过了接收 ......
Transmission Maximum Unit MTU

E. Ina of the Mountain 优先队列

题意:给你一个长度为n的序列。问你最少进行多少次操作,使得最终整个序列的值都为k 操作:选一段区间,然后把这段区间的数全减一。 这个序列还有一个特性,就是当一个数为0时,这个数会变成k。 解法:一眼丁真P1969 [NOIP2013 提高组] 积木大赛 - 洛谷 | 计算机科学教育新生态 (luog ......
队列 Mountain Ina the of

The native HTML dialog tag All In One

The native HTML dialog tag All In One ......
native dialog HTML The All

What's the best approach for generating a new API key?

https://stackoverflow.com/questions/14412132/whats-the-best-approach-for-generating-a-new-api-key Edit: I've spoke to a few friends (email/twitter) an ......
generating approach What best API

CF1848B Vika and the Bridge 题解

# CF1848B Vika and the Bridge 题解 ## 题目大意 ~~给个题目传送门吧,感觉题意已经很清楚了~~ [题目传送门](https://www.luogu.com.cn/problem/CF1848B) ## 分析 (~~我不会告诉你我第一眼看过去是二分~~) 因为我们只能 ......
题解 Bridge 1848B 1848 Vika

[LeetCode] 1921. Eliminate Maximum Number of Monsters

You are playing a video game where you are defending your city from a group of n monsters. You are given a 0-indexed integer array dist of size n, whe ......
Eliminate LeetCode Monsters Maximum Number

1335B - Construct the String

## B. Construct the String https://codeforces.com/problemset/problem/1335/B #### 分析: 首先不要被他的示例迷惑掉,这个问题可以看作若干个小问题 Q: 1. 如何简单的构造a个长度里有b个不同的值 2. 如何是n里的所有 ......
Construct String 1335B 1335 the

Implementing Domain Driven Design (A practical guide for implementing the Domain Driven Design with the ABP Framework)

##CONTENTS **Introduction**.................................................. * **Goal**...................................................... * **Sim ......

266B - Queue at the School

## A. Team [https://codeforces.com/problemset/problem/266/B](https://codeforces.com/problemset/problem/266/B) ##### During the break the schoolchildre ......
School Queue 266B 266 the

C. The Football Season 数学exgcd

题意: 给你四个数,n,p,d,w。让你求出任意一组x,y,z,要满足下面的条件 做法: 对于第一个式子,我们可以先用exgcd求出合法的解,在他的整个解系中进行mod(k)+k再mod(k)的操作,判断x和y能否同时非负。 对于第二个式子,我们要让z非负,那么x+y要尽可能小。而还要满足第一个式子 ......
Football 数学 Season exgcd The

[LeetCode] 2511. Maximum Enemy Forts That Can Be Captured

You are given a 0-indexed integer array forts of length n representing the positions of several forts. forts[i] can be -1, 0, or 1 where: -1 represent ......
LeetCode Captured Maximum Enemy Forts

Maximum Diameter 题解

[Maximum Diameter](https://www.luogu.com.cn/problem/AT_abc290_f) ### 题目大意 定义长度为 $n$ 的序列 $a$ 的权值为: - 所有的 $n$ 个点的第 $i$ 个点的度数为 $a_i$ 的树的直径最大值,如果不存在这样的树,其 ......
题解 Diameter Maximum

AtCoder Beginner Contest 317 C - Remembering the Days

# C - Remembering the Days [原题链接](https://atcoder.jp/contests/abc317/tasks/abc317_c) 题意:每个点最多经过一次,求最长路 思路:数据范围很小,深搜每个点能到其他点的所有路,取最大 ```c++ #include us ......
Remembering Beginner AtCoder Contest Days

【CF1503A】Balance the Bits(构造)

**题目大意:** *** ```cpp #include using namespace std; typedef long long ll; ll n; char s[200000+10]; char a[200000+10],b[200000+10]; int main(){ ios::syn ......
Balance 1503A 1503 Bits the

The 2022 ICPC Asia Nanjing Regional Contest

# [The 2022 ICPC Asia Nanjing Regional Contest](https://codeforces.com/gym/104128) [出题人题解](https://sua.ac/wiki/2022-icpc-nanjing/) [TOC] vp的不是很好,就不放出来 ......
Regional Contest Nanjing 2022 ICPC

What's the difference between Async Await and Promise in JavaScript All In One

# What's the difference between Async Await and Promise in JavaScript All In One > `Async` vs `Promise` ## demos --> ## (🐞 反爬虫测试!打击盗版⚠️)如果你看到这个信息, 说明 ......
JavaScript difference Promise between Async

The repository 'http://mirrors.163.com/debian jessie Release' does not have a Release file.

设置Debian源为国内网易源 tee /etc/apt/sources.list << EOF deb http://mirrors.163.com/debian/ jessie main non-free contrib deb http://mirrors.163.com/debian/ je ......
Release repository mirrors debian jessie

CF1174E Ehab and the Expected GCD Problem 题解

## 题意 对于一个排列 $p$,定义 $g$ 为 $p$ 的前缀最大公约数序列,即 $g_i = \gcd\limits_{j = 1}^{i} p_j$。定义 $f(p)$ 为 $g$ 的元素种类数。 给定 $n$,求长度为 $n$ 的且使得 $f(p)$ 取最大值的排列个数,对 $10^9 + ......
题解 Expected Problem 1174E 1174

how to get the SVG document content that inside a object tag in javascript

# how to get the SVG document content that inside a object tag in javascript > object tag & SVG document content in javascript ## demos ```js ``` ![im ......
javascript document content inside object

Proj CDeepFuzz Paper Reading: AutoML: A survey of the state-of-the-art

## Abstract Github: https://github.com/marsggbo/automl_a_survey_of_state_of_the_art 本文: 1. intro AutoML methods: data preparation, feature engineering ......

G. The Great Equalizer

G. The Great Equalizer 通过分析之后得知,每次询问的答案就是当前数组中的最大值和当下数组排序后相邻元素差值的最大值之和。 接下来考虑如何维护数组。这会想到用一颗二叉平衡搜索树来实现。这样的一颗树在STL里已经用multiset封装好了,直接使用即可。 创建两个辅助函数add(i ......
Equalizer Great The

The specified target project directory xxxx does not exist 报错

检查generatorConfig.xml中targetProject属性是否为相对路径 原因:targetProject属性中的相对路径无法找到 文件路径是由启动类的Working directory + targetProject决定的 所以xml文件中的targetProject属性需要,以绝 ......
specified directory project target exist

How to reverse a string that contains the emoji in js All In One

How to reverse a string that contains the emoji in js All In One ......
contains reverse string emoji that

CF1178G The Awesomest Vertex

> 给定一棵树与两个序列 $a\set{n}$ 与 $b\set{n}$,定义 $R\left(u\right)$ 为节点 $u$ 的祖先集合,节点 $u$ 的权值定义如下: > > $$\left| \sum_{i \in R\left(u\right)} a_i \right| \times \ ......
Awesomest Vertex 1178G 1178 The

Educational Codeforces Round 150 (Rated for Div. 2)E. Fill the Matrix(数据结构,数学)

题目链接:https://codeforces.com/contest/1841/problem/E 题意: 有一个nxn的正方形网格; 现在对每一列进行约束,对第 i 列 从上往下,将 a[ i ] 个格子涂成黑色; 给正整数m,你要在网格内填上 1 ~ m 个数,有以下限制: 1: 数字只能填在 ......

Chrome Extension Develop: How to get the extension icon data in Manifest V3

## 需求 在 background 中,拿到了扩展 icon 的 URL 链接,如:chrome://extension-icon/mciiogijehkdemklbdcbfkefimifhecn/128/0,如何获取其二进制数据。 > 目的:对于记录扩展安装卸载的功能而言,能够获取扩展的 ico ......
Extension extension Manifest Develop Chrome

Android Installed Build Tools revision 34.0.0 is corrupted. Remove and install again using the SDK

前言ERROR: Installed Build Tools revision 34.0.0 is corrupted. Remove and install again using the SDK Manager.错误:已安装的生成工具修订版34.0.0已损坏。使用SDK管理器删除并重新安装。 上 ......
Installed corrupted revision Android install