struct typedef and
CF868E Policeman and a Tree
感觉，好自然啊！ 想法 dp，想办法分解这个博弈的过程。发现警察会从一片叶子到另一片叶子，在叶子抓住小偷时所有小偷可以全树乱走。因此 dp：\(f_{u, i}\) 表示警察位于 \(u\)，全树剩余 \(i\) 个小偷时的答案。 因为两边都绝对理性，小偷在警察离开叶子后不会移动并位于多片叶子上。考 ......
QOJ # 4424. Babushka and her pierogi
有 $n$ 个数 $a_i$，要换成 $b_i$，保证 $a$ 中数互不相同且 $a,b$ 数集相同。交换 $a_x,a_y$ 的费用是 $|a_x-a_y|+C$，$C$ 是常数。求将 $a$ 变换成 $b$ 的最小费用。$n\leq 2\times 10^5$。 ......
Practice Assessment for Exam AZ-400: Designing and Implementing Microsoft DevOps Solution
https://learn.microsoft.com/en-us/credentials/certifications/exams/az-400/practice/assessment?assessment-type=practice&assessmentId=56 The most secure ......
kernel function: the difference beween cdev_add and device_create
To use a character driver, first you should register it with the system. Then you should expose it to the user space. 1. cdev_init and cdev_add functi ......
A piece of code for loading and caching Skeleton Animation in IO task [Cocos2dx.3.17.2]
/**************************************************************************** Copyright (c) 2017-2018 Xiamen Yaji Software Co., Ltd. http://www.cocos2 ......
GraphPrompt: Unifying Pre-Training and Downstream Tasks for Graph Neural Networks
目录概符号说明GraphPrompt代码 Liu Z., Yu X., Fang Y. and Zhang X. GraphPrompt: Unifying pre-training and downstream tasks for graph neural networks. WWW, 2023. ......
[925] GDA2020_MGA and change the spatial reference in ArcGIS Pro
ZONE50: 114.0 120.0 - arcpy.mp.spatialReference("GDA2020_MGA_Zone_50") ZONE51: 120.0 126.0 - arcpy.mp.spatialReference("GDA2020_MGA_Zone_51") ZONE52: ......
How To Clear Quick Access And Recent File And Folders In Windows 10
How To Clear Quick Access And Recent File And Folders In Windows 10 Here are the instructions to clear the Quick Access and Recent Files and Folders c ......
Go - Print struct with one filed in one line
package main import ( "encoding/json" "fmt" ) type Person struct { Name string Age int Email string } func main() { p := Person{ Name: "Drake", Age: 3 ......
10月23日粘包、struct模块以及json模块
目录粘包如何解决粘包问题呢？struct模块json模块 粘包 粘包:tcp会把数据量较小，时间间隔较短的数据，当做同一个包发送 粘包问题图 粘包问题说白了就是客户端传给服务器的数据到服务器的时候有部分数据粘在了一块，而不是一条条的显示 粘包产生情况大致图 如何解决粘包问题呢？ 简单的方式就是加大s ......
10月23日粘包学习以及struct模块和json模块
目录粘包如何解决粘包问题呢？struct模块json模块 粘包 粘包:tcp会把数据量较小，时间间隔较短的数据，当做同一个包发送 粘包问题图 粘包问题说白了就是客户端传给服务器的数据到服务器的时候有部分数据粘在了一块，而不是一条条的显示 粘包产生情况大致图 如何解决粘包问题呢？ 简单的方式就是加大s ......
CF1886D Monocarp and the Set
Link 此题目可以从两个方向考虑，正着和倒着，倒着考虑比较容易，首先把所有的数放到一块，如果是'<'或者'>'，就是去掉最左边或者最右边的数，这样显然只有一种可能,答案不变。 如果是'?'，那么显然可以去掉中间的任意一个，所以答案就是\(\times l-2\)，那么对于\(s_n-i\)位置的\ ......
UniKGQA Unified Retrieval and Reasoning for Solving Multi-hop Question Answering Over Knowledge Graph
目录概主要内容代码 Jiang J., Zhou K., Zhao W. and Wen J. UniKGQA: Unified retrieval and reasoning for solving multi-hop question answering over knowledge graph ......
Open Domain Question Answering Using Early Fusion of Knowledge Bases and Text
目录概主要内容代码 Sun H., Dhingra B., Zaheer M., Mazaitis K., Salakhutdinov R. and Cohen W. W. Open domain question answering using early fusion of knowledge ......
Struct
package com.chen.struct; public class ForDemo02 { public static void main(String[] args) { //练习一：计算0到100之间奇数和偶数的和 int oddsum = 0; int evensum = 0; for ......
Struct ForDemo01
package com.chen.struct; import java.util.Scanner; public class ForDemo01 { public static void main(String[] args) { int a = 1;//初始化条件 while (a<100){/ ......
Struct ForDemo03
package com.chen.struct; public class ForDemo03 { public static void main(String[] args) { //练习2:用while或for循环输出1-1000之间能被5整除的数,并且每行输出3个 for (int i = 0 ......
Struct ForDemo04
package com.chen.struct; public class ForDemo04 { public static void main(String[] args) { //打印九九乘法表 //1.先打印第一列 //2.把固定的1在用一个循环包起来 //3.去掉重复项，i = j; // ......
Struct ForDemo05
package com.chen.struct; public class ForDemo05 { public static void main(String[] args) { int[] numbers = {10,20,30,40,50}; for (int i =0;i<5;i++){ S ......
论文阅读：Unifying Large Language Model and Knowledge Graph：A RoadMap
1 Introduction 大模型和知识图谱结合的综述。 简单介绍一下大模型和知识图谱的优缺点： 如上所示。 本文主要划分为三个模块，分别为： KG-enhanced LLMs LLM-augmented KGs Synergized LLM + KG 2 Background 主要介绍了LLM和 ......
The JSON value of length n is too large and not supported
https://github.com/dotnet/runtime/issues/39953 I'm referring to this issue #30746 that was closed with limit of 125MB staying fixed opposed to being c ......
Diagnostic Port on Electronic Engine and Transmission
Diagnostic ConnectorTest the Connection to the ECM using cat et diagnostic kit ToolkitDeutsch Connectors (6/9-Pin)NOTE: On the Deutsch 9-pin SAE Stand ......
npm ERROR. node-sass and python
当前 install package 出现以下错误时 node-sass check python checking for Python executable "python2" in the PATH 建议安装 python@2 和 node@14 后再 install package. 下载 ......
CF1100E Andrew and Taxi
套路题又来咯，最大值最小先直接上个二分答案\(lim\) 对于图中的边，若它的权值\(>lim\)的话这条边的方向就确定了，那么直接把这些边连出来跑个拓扑排序看看有没有环即可 如果有环则当前答案一定不合法，否则我们总存在如下的构造方法： 先把权值\(>lim\)的边得到的图的拓扑序搞出来，对于所有权 ......
[915] Implementation of zooming to layer and exporting to PDF in arcpy
ref: Camera - ArcGIS Pro ref: Introduction to arcpy.mp # Set the path to your project file (.aprx) project_file = r"Map 1.3 Heritage.aprx" # Reference ......
Paper Reading: Sample and feature selecting based ensemble learning for imbalanced problems
为了克服现有集成方法的缺点，本文提出一种新的混合集成策略——样本和特征选择混合集成学习 SFSHEL。SFSHEL 考虑基于聚类的分层对大多数样本进行欠采样，并采用滑动窗口机制同时生成多样性的特征子集。然后将经过验证训练的权重分配给不同的基学习器，最后 SFSHEL 通过加权投票进行预测。SFSHE... ......
Codeforces Round 872 (Div. 2) B. LuoTianyi and the Table
给一个 \(n \times m\) 的矩阵和 \(n \times m\) 个数，你需要把这些数填入矩阵。保证 \[\sum_{i=1}^n \sum_{j=1}^m \left ( \mathop{max}\limits_{1 \leq x \leq i, 1 \leq y \leq j} a_ ......
Struct WhileDemo03
package com.chen.struct; public class WhileDemo03 { public static void main(String[] args) { //计算1+2+3...+100=？ //高斯的故事 int i = 0; int sum = 0; while ......
Struct DoWhileDemo01
package com.chen.struct; public class DoWhileDemo01 { public static void main(String[] args) { int i = 0; int sum = 0; do { sum = sum + i; i++; }while ......
Struct DoWhileDemo02
package com.chen.struct; public class DoWhileDemo02 { public static void main(String[] args) { int a = 0 ; while (a<0){ System.out.println(a); a++; } ......