项目中遇到使用多个相同spine的问题：
我们需要获取骨骼位置的时候，要拿下面这个类的信息
spine工具给的更新方案是：每个spine在Update中每帧更新，根据当前spine更新骨骼信息。
这样比较费，比如我们项目场景中有五个角色，每个角色有五个编制，那光友方单位就是25个spine，很难蚌。
优化方案：每个角色设置一个主体spine，主体spine在Update中更新数据，剩下的4个相同spine在获取骨骼接口的时候同步一下主体spine的位置就可以（反正都是相对坐标，都是一致的）。
public void CopyMainframeSkeletonData()
{
//主体spine
if (mainframeSkeletonAnimation.skeleton == null) return;
if (skeleton == mainframeSkeletonAnimation.skeleton) return;
for (int i = 0, j = skeleton.bones.Count; i < j; i++)
{
Bone thisBone = skeleton.bones[i];
Bone sharedBone = mainframeSkeletonAnimation.skeleton.bones[i];
thisBone.x = sharedBone.x;
thisBone.y = sharedBone.y;
thisBone.rotation = sharedBone.rotation;
thisBone.rotationIK = sharedBone.rotationIK;
thisBone.scaleX = sharedBone.scaleX;
thisBone.scaleY = sharedBone.scaleY;
thisBone.flipX = sharedBone.flipX;
thisBone.flipY = sharedBone.flipY;
thisBone.m00 = sharedBone.m00;
thisBone.m01 = sharedBone.m01;
thisBone.m10 = sharedBone.m10;
thisBone.m11 = sharedBone.m11;
thisBone.worldX = sharedBone.worldX;
thisBone.worldY = sharedBone.worldY;
thisBone.worldRotation = sharedBone.worldRotation;
thisBone.worldScaleX = sharedBone.worldScaleX;
thisBone.worldScaleY = sharedBone.worldScaleY;
thisBone.worldFlipX = sharedBone.worldFlipX;
thisBone.worldFlipY = sharedBone.worldFlipY;
}
// 复制slot信息
for (int i = 0, j = skeleton.slots.Count; i < j; i++)
{
Slot thisSlot = skeleton.slots[i];
Slot sharedSlot = mainframeSkeletonAnimation.skeleton.slots[i];
thisSlot.Attachment = sharedSlot.Attachment == null ? null : skeleton.GetAttachment(i, sharedSlot.Attachment.Name);
}
// 复制order信息
if (mainframeSkeletonAnimation.skeleton.drawOrderToSetupIndex == null)
{
skeleton.drawOrder.Clear();
skeleton.drawOrder.AddRange(skeleton.slots);
}
else
{
for (int k = 0, n = mainframeSkeletonAnimation.skeleton.drawOrderToSetupIndex.Length; k < n; k++)
skeleton.drawOrder[k] = skeleton.slots[mainframeSkeletonAnimation.skeleton.drawOrderToSetupIndex[k]];
}
}
在获取骨骼位置的时候调用一下这个函数刷新就可以了。