hyperbolic

inverse hyperbolic functions

Differentiation $$y=\sinh^{-1}x\quad\Longrightarrow\quad x=\sinh y\\\frac{{\rm d}x}{{\rm d}y}=\cosh y=\sqrt{(\sinh y)^2+1}=\sqrt{x^2+1}\\[6pt]y=\cosh^ ......
hyperbolic functions inverse
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