the
The chromedriver.exe file does not exist in the current directory
The chromedriver.exe file does not exist in the current directory or in a directory on the PATH environment variable. The driver can be downloaded at ......
CF724G Xor-matic Number of the Graph
[题目链接](https://codeforces.com/problemset/problem/724/G) 不妨先看一道更为基础的题:[CF845G](https://codeforces.com/problemset/problem/845/G)以及[它的题解](https://www.cnb ......
Codeforces Round 843 (Div. 2) A2. Gardener and the Capybaras (hard version)
有三个字符串 $s_1, s_2, s_3$ ,每个字符串只有 $a, b$ 组成。三个字符串顺序连接在了一起。满足以下条件之一: * $s1 \leq s_2, s_3\leq s_2$ * $s1 \geq s_2, s_3\geq s_2$ 以上为字典序比较。 给出连接的三个字符串,输出一组可 ......
Codeforces Round 874 (Div. 3) B. Restore the Weather
给一个长为 $n$ 的数组 $a$ ,给一个长为 $n$ 的乱序数组 $b$ ,给一个正整数 $k$ 。要求重排 $b$ 使得 $\forall i, |a_i - b_i| \leq k$ 。输出其中一种 $b$ 的排列方式。 一个性质题。(div2 前几题很喜欢有序数组的经典性质) 总结一下有序 ......
【题解】CF1852C Ina of the Mountain
我们先从题目的一部分入手。 如果说,我们没有当一个数为 $0$ 时,让这个数变成 $k$ 的性质,我们如何求答案呢? 很简单,在图上就是: 绿色线段的长度加起来即为答案(本图中是 $6$) 我们考虑很显然地,将一个数从 $0$ 变为 $k$ 即为将一个数一开始加上 $k$ 我们如果要让第 $i$ 列 ......
It is strongly discouraged to install anything else in the base envionment
For both mamba and conda, the base environment is meant to hold their dependencies. It is strongly discouraged to install anything else in the base en ......
The Riordan Group and Applications 第1章 笔记
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The 2022 ICPC Asia Hangzhou Regional Programming Contest
The 2022 ICPC Asia Hangzhou Regional Programming Contest No Bug No Game #include<bits/stdc++.h> using namespace std; #define endl "\n" #define int lon ......
The 2022 ICPC Asia Nanjing Regional Contest
链接:[https://codeforces.com/gym/104128](https://codeforces.com/gym/104128) ## A. Stop, Yesterday Please No More ```cpp #include "bits/stdc++.h" using n ......
The 18th Heilongjiang Provincial Collegiate Programming Contest
链接:[https://codeforces.com/gym/104363](https://codeforces.com/gym/104363) ## A. Magic Computer ```cpp #include "bits/stdc++.h" using namespace std; us ......
The 10th Shandong Provincial Collegiate Programming Contest
链接:[https://codeforces.com/gym/104459](https://codeforces.com/gym/104459) ## A ```cpp #include "bits/stdc++.h" using namespace std; using i64 = long l ......
The 17th Chinese Northeast Collegiate Programming Contest
链接:[https://codeforces.com/gym/104366](https://codeforces.com/gym/104366) ## A. Cask Effect ```cpp #include "bits/stdc++.h" using namespace std; using ......
安装cocoapods: Error installing cocoapods: The last version of activesupport (>= 5.0, < 8) to support your Ruby & RubyGems was 6.1.7.6. Try installing it with `gem install activesupport -v 6.1.7.6`问题解决
问题描述: 在终端命令行安装cocoapods时,可能出现如下问题: Error installing cocoapods: The last version of activesupport (>= 5.0, < 8) to support your Ruby & RubyGems was 6.1 ......
[LeetCode] 2433. Find The Original Array of Prefix Xor
You are given an integer array pref of size n. Find and return the array arr of size n that satisfies: pref[i] = arr[0] ^ arr[1] ^ ... ^ arr[i]. Note ......
大模型时代的推荐系统Recommender Systems in the Era of Large Language Models (LLMs)
文章地址:https://arxiv.org/abs/2307.02046 笔记中的一些小实验中的模型都是基于GPT-3.5架构的ChatGPT模型。 本文主要讲述了比较具有代表性的方法利用LLM去学习user和item的表示,从预训练、微调和提示三个范式回顾了近期用于增强推荐系统的LLM先进技术, ......
error: The following untracked working tree files would be overwritten by merge
错误内容如下: error: The following untracked working tree files would be overwritten by merge: xxx/xxx/xxx/xxx/xxx/xxx/xxx.java Please move or remove them b ......
The 2nd Universal Cup. Stage 1: Qingdao
### G #### Description 给定一个数列,每次ban一个位置,在每次ban之前,求连续子序列逆序对数的最大值,强制在线。(6s)$n\leq10^5, \sum n \leq10^6$ #### Solution 先考虑用权值线段树来维护区间逆序对数,不难支持在原数列前后加或删除一 ......
The colossus
BY SYLVIA PLATH I shall never get you put together entirely, Pieced, glued, and properly jointed. Mule-bray, pig-grunt and bawdy cackles Protected fro ......
E. Ina of the Mountain 优先队列
题意:给你一个长度为n的序列。问你最少进行多少次操作,使得最终整个序列的值都为k 操作:选一段区间,然后把这段区间的数全减一。 这个序列还有一个特性,就是当一个数为0时,这个数会变成k。 解法:一眼丁真P1969 [NOIP2013 提高组] 积木大赛 - 洛谷 | 计算机科学教育新生态 (luog ......
The native HTML dialog tag All In One
The native HTML dialog tag All In One
......
What's the best approach for generating a new API key?
https://stackoverflow.com/questions/14412132/whats-the-best-approach-for-generating-a-new-api-key Edit: I've spoke to a few friends (email/twitter) an ......
CF1848B Vika and the Bridge 题解
# CF1848B Vika and the Bridge 题解 ## 题目大意 ~~给个题目传送门吧,感觉题意已经很清楚了~~ [题目传送门](https://www.luogu.com.cn/problem/CF1848B) ## 分析 (~~我不会告诉你我第一眼看过去是二分~~) 因为我们只能 ......
1335B - Construct the String
## B. Construct the String https://codeforces.com/problemset/problem/1335/B #### 分析: 首先不要被他的示例迷惑掉,这个问题可以看作若干个小问题 Q: 1. 如何简单的构造a个长度里有b个不同的值 2. 如何是n里的所有 ......
Implementing Domain Driven Design (A practical guide for implementing the Domain Driven Design with the ABP Framework)
##CONTENTS **Introduction**.................................................. * **Goal**...................................................... * **Sim ......
266B - Queue at the School
## A. Team [https://codeforces.com/problemset/problem/266/B](https://codeforces.com/problemset/problem/266/B) ##### During the break the schoolchildre ......
C. The Football Season 数学exgcd
题意: 给你四个数,n,p,d,w。让你求出任意一组x,y,z,要满足下面的条件 做法: 对于第一个式子,我们可以先用exgcd求出合法的解,在他的整个解系中进行mod(k)+k再mod(k)的操作,判断x和y能否同时非负。 对于第二个式子,我们要让z非负,那么x+y要尽可能小。而还要满足第一个式子 ......
AtCoder Beginner Contest 317 C - Remembering the Days
# C - Remembering the Days [原题链接](https://atcoder.jp/contests/abc317/tasks/abc317_c) 题意:每个点最多经过一次,求最长路 思路:数据范围很小,深搜每个点能到其他点的所有路,取最大 ```c++ #include us ......
【CF1503A】Balance the Bits(构造)
**题目大意:** *** ```cpp #include using namespace std; typedef long long ll; ll n; char s[200000+10]; char a[200000+10],b[200000+10]; int main(){ ios::syn ......
The 2022 ICPC Asia Nanjing Regional Contest
# [The 2022 ICPC Asia Nanjing Regional Contest](https://codeforces.com/gym/104128) [出题人题解](https://sua.ac/wiki/2022-icpc-nanjing/) [TOC] vp的不是很好,就不放出来 ......
What's the difference between Async Await and Promise in JavaScript All In One
# What's the difference between Async Await and Promise in JavaScript All In One > `Async` vs `Promise` ## demos --> ## (🐞 反爬虫测试!打击盗版⚠️)如果你看到这个信息, 说明 ......