\(4\) 个骰子同时扔出,\(2\) 面同时朝上的概率为:
个人思路(不保证正确):
\(1st\) 为 \(6\) 的概率是:\(\frac{1}{6}\)
\(2st\) 为 \(6\) 的概率是:\(\frac{1}{6}\)
\(3st\) 不为 \(6\) 的概率是:\(\frac{5}{6}\)
\(4st\) 不为 \(6\) 的概率是:\(\frac{5}{6}\)
\[\frac{1}{6}\times\frac{1}{6}\times\frac{5}{6}\times\frac{5}{6}=\frac{25}{1296}
\]
但据说正解是\(\frac{5}{9}\),疑惑,求解