balance 1503a bits the

Codeforces Round 866 (Div. 1) C. The Fox and the Complete Tree Traversal (构造)

传送门 题目大意: ** 给定一个有n个点的树,我们可以任意选择一个点作为起点,这个点可以跳到跟自己距离为1或者距离为2的点,已经到达的点不能再到达(最终必须回到起点),询问是否存在一种方案可以从一个点出发经过所有的点最终再回到这个点来。** ** 输入一个整数n。紧接着输入n-1条边。** 大致思 ......
Codeforces Traversal Complete Round Tree

Introducing the QCN9074: A Revolutionary New Chip for the Internet of Things

The QCN9074 is a high-performance chip designed to meet the demanding needs of the Internet of Things (IoT) market. With its powerful processing capab ......

CF1699A The Third Three Number Problem

###题意简述 构造出一个三元组a,b,c使得(a ⊕ b)+(a ⊕ c)+(b ⊕ c) = n,若无解输出-1。 符号 ⊕ 的意思为异或 ###个人分析 首先要了解异或符号的性质: 1,x⊕0=x 2,x⊕x=x 根据异或符号的性质可以得到一下构造: a=b=0,c=n/2 c=0,a=b=n ......
Problem Number 1699A Third Three

How to get Linux kernel Information using the command line All In One

How to get Linux kernel Information using the command line All In One 如何使用命令行获取 Linux 内核信息 ......
Information command kernel Linux using

JPG 100 vs JPG 20: What’s The Difference?

JPG 100 vs JPG 20: What’s The Difference? So you’re into photography and while you’re showing some skill and getting a handle on camera settings for t ......
Difference JPG What 100 The

As a restaurant owner, write a professional email to the supplier to get these products every week: - Wine (x10) - Eggs (x24) - Bread (x12)

As a restaurant owner, write a professional email to the supplier to get these products every week: Wine (x10) Eggs (x24) Bread (x12) Dear Supplier, I ......

[PART 1-1] The Transaction

This chapter is talking about some affairs happened in a school speech. I perceive this as the author casually talking. But this section is still a ge ......
Transaction PART The

Correct the classpath of your application so that it contains a single, compatible version of xxx报错解决

1.背景 有时候引入包有冲突,比如在Maven项目中的不同模块多次重复引入等 这里遇到的问题是重复映入了如下包: <dependency> <groupId>com.baomidou</groupId> <artifactId>mybatis-plus-boot-starter</artifactI ......

error: Your local changes to the following files would be overwritten by merge 解决方案

拉取代码出现 error: Your local changes to the following files would be overwritten by merge 解决方案 你团队其他成员修改了某文件并已提交入库。 你在pull之前修改了本地该文件,等你修改完代码再pull时,这时会报错如下 ......

SpringBoot上传文件报错The field multiFile exceeds its maximum permitted size of 1048576 bytes

问题原因:在上传文件中文件的大小超过默认大小,所以抛出此异常。 解决办法:在SpringBoot的配置文件中修改上传文件大小的配置 1、application.properties spring.servlet.multipart.max-request-size=200MB spring.serv ......

[LeetCode] 2418. Sort the People

You are given an array of strings names, and an array heights that consists of distinct positive integers. Both arrays are of length n. For each index ......
LeetCode People 2418 Sort the

C. Restore the Array - 构造 + 思维

对于长度为n的数组a,存在长度为n-1的数组b有b[i]=max(a[i],a[i+1]),t组测试数据,给出n和b数组,构造a数组。 分析: ......
思维 Restore Array the

C# Under the Hood: async/await

https://www.markopapic.com/csharp-under-the-hood-async-await.html ......
Under async await Hood the

NC25045 [USACO 2007 Jan S]Balanced Lineup

题目链接 题目 题目描述 For the daily milking, Farmer John's N cows (1 ≤ N ≤ 100,000) always line up in the same order. One day Farmer John decides to organize a ......
Balanced Lineup 25045 USACO 2007

tracecompass mac 安装JVM shared library does not contain the JNI_CreateJavaVM symbol问题解决

最近在学习tracecompass,因为mac 系统版本有点高,直接运行发现起不来 可能的原因 jvm 版本问题 可以通过修改Info.plist 文件添加jvm 信息 依赖库签名问题 我的jvm 是正确的,但是还是提示上边的问题,结果通过直接命令行启动,发现提示签名问题 如下 ver/libjvm ......

How use the RegExp to filter IP address in js All In One

How use the RegExp to filter IP address in js All In One 如何使用 RegExp 在 js 中过滤 IP 地址 192.168.18.1 < 192.168.18.N < 192.168.18.255 ignore IPs: 192.168.1 ......
address RegExp filter How All

Access denied; you need (at least one of) the SYSTEM_USER privilege(s) for this operation

原因是由于root用户没有SYSTEM_USER权限,把权限加入后即可解决: grant system_user on *.* to 'root'; ......

The binary version of its metadata is 1.8.0, expected version is 1.5.1.

C:/Users/sdt16354/.gradle/caches/transforms-3/b92f389f516aa233b37ae70b7a7c1337/transformed/jetified-annotation-jvm-1.6.0.jar!/META-INF/annotation.kotl ......
version expected metadata binary is

Introducing the QCN9074: A Revolutionary New Chip for the Internet of Things

The QCN9074 is a high-performance chip designed to meet the demanding needs of the Internet of Things (IoT) market. With its powerful processing capab ......

The Bells are Ringing UVA-12119

已知M 为T1,T2,T3 的LCM 输出满足 Ti-Tj<=25 的所有可能情况 #include<iostream> #include<cmath> #include<algorithm> #include<cstring> using namespace std; const int N= 1 ......
Ringing Bells 12119 The are

java调用GDAL,接口运行一次出现A fatal error has been detected by the Java Runtime Environment,需要手动释放指针对象(DataSource)

参考文章:https://www.jianshu.com/p/4bffe29e3a02 问题描述:通过调用GDAL写的SpringBoot接口,第一次访问成功,第二次报错,显示报错的位置为gdal库。 尝试了很多方法https://www.cnblogs.com/jokingremarks/p/15 ......

check_crystal_oscillator_size_in_the_code

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CF1819B The Butcher

题意:有一个未知大小的矩形,每次横着或者竖着剪成两块,将其中一块放入盒子里,继续对另一块进行操作,最后把剩余的也放进盒子里,现在已知盒子内的所有矩形的长和宽,问原来可能的矩形长和宽是多少(矩形没有进行旋转) Solution 比较容易想到把所有的矩形面积和加起来就是原矩形的面积了,然后找到矩形中最大 ......
Butcher 1819B 1819 The CF

C# Mysql The given key '12599' was not present in the dictionary.

如果查询语句没有问题数据库连接字符串也没有问题,可能是Mysql.Data引用与当前安装的Mysql数据库版本不兼容的问题。 我本地安装的mysql版本是8.30,在VS里使用Nuget程序包下载的Mysql.Data引用是其他更低的版本,将程序里用的Mysql.Data也更新到8.30就好了。 版 ......
dictionary present Mysql 12599 given

java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''',b_5='17',b_6='' wher

java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right s ......

Unlock the Power of High-Performance Networking with the IPQ9554

Unlock the Power of High-Performance Networking with the IPQ9554 In today's world, reliable and high-speed internet connectivity is essential for ever ......

Ray Tracing: The Next Week

2. Motion Blur 在前面,反走样是通过像素内取多个路径实现的,此外多条路径的选择也跟后面的漫反射、模糊反射、散焦模糊等一系列随机过程有关,如果继续暴力解法,也可以实现运动模糊。 在真实的相机中,照片的形成是对一段时间内光线的记录,与快门有关,因此,为了模拟摄影,加入运动模糊。 首先运动模 ......
Tracing Next Week Ray The

[ARC138D] Differ by K bits 题解

小清新构造题。 首先 $K=1$ 的情况是 trival 的,直接格雷码即可。 对于 $K>1$,我们发现题目的约束相当于 $\operatorname{popcount}(P_i\oplus P_{(i+1)\bmod 2^N})=K$,考虑 $P_i$ 的差分序列 $D_i$,那么 $D_i$ ......
题解 Differ 138D bits ARC

The 1st Universal Cup. Stage 12: Ōokayama

G 容斥完之后发现要求一个m次多项式的n次方,并且得到$n\times m$项。 原本很sb地直接套了个多项式LnExp上去(即使知道大概率过不了),然后狂TLE。。。 其实但凡从常数的角度分析,Exp的常数有14倍,已经比$log(m)$大了,所以不如写快速幂,然后写着就会发现卷积的长度总和其实是 ......
Universal okayama Stage The 1st