directory validhome selected the

could not chdir to home directory /home/user:permission denied /bin/bash:Permiss 的原因和解决方法

今天在vm上登录一个user 的时候,发现正确输入用户名和密码后弹出了这样的信息,登陆不上. 发现给出的信息中,permission denied 而 bin permiss; 这种情况表明自己给该用户赋予的权限不足导致问题 通过在/home 目录下用ll检查到该用户的user权限是 通过chmod ......
home permission directory 原因 Permiss

[LeetCode] 1356. Sort Integers by The Number of 1 Bits 根据数字二进制下1 的数目排序

You are given an integer array arr. Sort the integers in the array in ascending order by the number of 1's in their binary representation and in case ......
二进制 数目 LeetCode Integers 数字

E: The repository 'xxx' is not signed.

在ubuntu上安装了google chrome, 运行时有问题,删除了之后再次运行 sudp apt update 会报错 E: The repository 'http://dl.google.com/linux/chrome/deb stable InRelease' is not signe ......
repository signed 39 The not

Codeforces Round 855 (Div. 3) C. Powering the Hero

有 \(n\) 张卡的卡堆,你可以自顶向下抽卡。装备卡显示数值为 \(a_i(a_i>0)\) ,英雄卡显示数值为 \(a_i = 0\) 。 如果是装备卡,你可以将卡抽出放在装备堆。如果是英雄卡,你可以将装备堆顶端的一张数值为 \(x\) 的装备卡装备给英雄,英雄数值 \(+ x\) 。无论是否装 ......
Codeforces Powering Round Hero 855

救济金发放(The Dole Queue, UVa 133)

#include<stdio.h> #include<string.h> #define maxn 100 int n,k,m,a[25]; int left, chance; int win, lose; char s[maxn], s2[maxn]; int go(int p, int d, i ......
救济金 Queue Dole The 133

The 2021 CCPC Guangzhou Onsite

Preface 逆天PKU,出的什么寄吧东西,做题全靠打表找规律,一场比赛全是\(\bmod 998244353\) 4题成功从金到铜完美区分,我们队VP的时候两个半小时就下班了,看祁神写了3h的大几何题L 虽然徐神开场一眼看出了F是个诈骗题,但推了1h无果还是要上机打表找规律才发现式子 最后和徐神 ......
Guangzhou Onsite 2021 CCPC The

The 2021 CCPC Guilin Onsite (XXII Open Cup, Grand Prix of EDG)

Preface 昨天下午16:30~21:30刚打完CCPC2021的广州,今天早上九点又开始打这场桂林,压力拉满了属于是 这场比起昨天那场良心太多了,开场还挺顺(虽然因为写Dijkstra偷懒TLE了四发),但开题啥的都是见一个会一个 中期虽然有点卡但因为祁神会了几何所以没有空机,然后再点完外卖后 ......
Guilin Onsite Grand 2021 CCPC

Unexpected character '=' (code 61); expected a semi-colon after the reference for entity 'useSSL' at [row,col,system-id]: [8,75,"file:/usr/bigdata/hive-3.1.3/conf/hive-site.xml"]

在初始化hive时报错,出现如下问题: 错误原因:hive-site.xml 配置文件中,数据库的地址带有 & 符号。 将数据库地址中的 & 符号调整为 &amp;,详情如下: 再次初始化hive,执行结果如下: ......
39 hive quot Unexpected semi-colon

The innodb_system data file 'ibdata1' must be writable

MySQL无法启动 Active: deactivating (stop-sigterm) (Result: exit-code) 查看配置文件中的日志存储位置: view /etc/my.cnf 查看日志存储文件位置:/var/log/mysqld.log 文件错误提示:The innodb_sy ......
innodb_system writable ibdata1 innodb ibdata

The JSON value of length n is too large and not supported

https://github.com/dotnet/runtime/issues/39953 I'm referring to this issue #30746 that was closed with limit of 125MB staying fixed opposed to being c ......
supported length value large JSON

Docker启动失败,报错Cannot connect to the Docker daemon at unix:///var/run/docker 完美解决方案

问题描述: Cannot connect to the Docker daemon at unix:///var/run/docker.sock. Is the docker daemon running? 首次安装docker后,服务没有自启动 解决方案: 查看docker状态 1 service ......
Docker 解决方案 connect 方案 Cannot

Docker启动报错:Cannot connect to the Docker daemon at unix:///var/run/docker.sock. Is the docker daemon running?

问题描述: Docker启动报错:Cannot connect to the Docker daemon at unix:///var/run/docker.sock. Is the docker daemon running? Cannot connect to the Docker daemon ......
Docker daemon docker the connect

【MacOs】 env: node\r: No such file or directory

报错的原因: 执行具有 Windows 样式行结尾的 js 文件,主要发生在 Mac/Linux 操作系统中。 行结尾更改为 CRLF(Windows 样式)而不是 LS (Unix),因此解析器由于该字符“\ R”而将换行符作为路径的一部分。 通常来自具有 js 文件的第三方 npm 包。 解决方 ......
directory MacOs node file such

sonarqube启动报错:You must address the points described in the following [2] lines before starting Elasticsearch.bootstrap check XXXmax numberXXXfor user[sonar] is too low .XXX check the logs at XXX/.log

You must address the points described in the following [2] lines before starting Elasticsearch.bootstrap check failure [1] of [2]: max number of threa ......

B. Chips on the Board

B. Chips on the Board 题意:保证在n*n的棋盘上对于每一个点的列或者行都有一个筹码,也可以两个都有,问最小筹码:对于每一个筹码计算:a[i]+b[i]; 要使每个点都满足,最少的筹码的个数应该为n 1.对于行来看,如果每一行都有一个筹码,那么列就可以随便填:直接全选择最小的列 ......
Chips Board the on

Vivado生成bitstream时报错[Opt 31-67] Problem: A LUT3 cell in the design is missing a connection on input pin I1, which is used by the LUT equation

这个原因主要是因为有一个引脚没有用到,解决方法。 1、打开Schematic。 2、根据提示的模块去找,比如说我的报错。 [Opt 31-67] Problem: A LUT3 cell in the design is missing a connection on input pin I1, w ......
connection LUT bitstream the equation

Mysql:5.7.38的mysqldump备份所依赖的必要权限:select, show view, event:注意这个event

特别注意这个 event 权限,只有具有event权限,才能导出 procedure、function对象! 另外,如果指定dump-slave,则必须具有 super 权限才行,因为mysqldump需要启停 slave sql thread! ......
event 备份 mysqldump 权限 select

[922] Implementation of zooming to selected features by Python

ref: ArcPy.mp Get Selected Features Extent ref: Python/ArcPy classes/Geometry # Set the path to your project file (.aprx) project_file = r"Map 1.3 Her ......

[918] Copy the formatting from one cell in a table of a Word document to another cell in Python

To copy the formatting from one cell in a table of a Word document to another cell, you can use the python-docx library in Python. Here's a step-by-st ......
cell formatting document another Python

[919] Change the horizontal alignment of a cell to center within a table of a Word document using Python

To change the horizontal alignment of a cell to center within a table of a Word document using Python and the python-docx library, you can set the ali ......
horizontal alignment document Change Python

[920] Copy the font style from one cell in a table of a Word document to another cell using Python

To copy the font style from one cell in a table of a Word document to another cell using Python and the python-docx library, you can access the font p ......
cell document another Python style

Paper Reading: Sample and feature selecting based ensemble learning for imbalanced problems

为了克服现有集成方法的缺点,本文提出一种新的混合集成策略——样本和特征选择混合集成学习 SFSHEL。SFSHEL 考虑基于聚类的分层对大多数样本进行欠采样,并采用滑动窗口机制同时生成多样性的特征子集。然后将经过验证训练的权重分配给不同的基学习器,最后 SFSHEL 通过加权投票进行预测。SFSHE... ......

Codeforces Round 872 (Div. 2) B. LuoTianyi and the Table

给一个 \(n \times m\) 的矩阵和 \(n \times m\) 个数,你需要把这些数填入矩阵。保证 \[\sum_{i=1}^n \sum_{j=1}^m \left ( \mathop{max}\limits_{1 \leq x \leq i, 1 \leq y \leq j} a_ ......
Codeforces LuoTianyi Round Table 872

CF367C Sereja and the Arrangement of Numbers

这题首先上来会发现题目中的很多信息都是假的,核心就是问要构造一个\(x\)个点的完全图至少要多长的序列 我们把序列中相邻的两个元素看作图上的一条边,则可以把问题转化为:给一个\(x\)个点的完全图,问至少要走多长的路径才可以遍历图中的所有边至少一次 简单讨论下会发现当\(x\)为奇数时,此时图中每个 ......
Arrangement Numbers Sereja 367C 367

[题解]CF1881G Anya and the Mysterious String

思路 发现如果一个字符串中有长度大于等于 \(2\) 回文子串,必定有长度为 \(2\) 的回文子串或长度为 \(3\) 的回文子串,并且形如:aa 和 aba。 所以考虑用线段树这两种情况。维护一段区间的最左、次左、最右、次右的元素,同时用两个标记变量 \(f_1,f_2\) 分别表示这个区间中是 ......
题解 Mysterious String 1881G 1881

PAT_A 1038 Recover the Smallest Number

Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given { 32, 321, 3214, 0229, 87 }, we c ......
Smallest Recover Number PAT_A 1038

How to get macOS CPU details information in the command line All In One

How to get macOS CPU details information in the command line All In One 如何通过命令行获取 macOS CPU 的详细信息 ......
information details command macOS line

[QOJ6555] The 2nd Universal Cup. Stage 5. J : Sets May Be Good

先给 EI 磕三个 首先考虑用 \(n\) 个变量 \(x_1,x_2,\cdots,x_n\in\{0,1\}\) 表示第 \(i\) 个点选不选,那么导出子图的边数的奇偶性就是 \[f(x_1,x_2,\cdots,x_n)=\left(\sum_{(i,j)\in E}x_ix_j\right ......
Universal Stage 6555 Good Sets

asp.net core signalr 客户端调用服务端方法报:Error:Failed to invoke 'adduserToConnection' due to an error on the server

TS端调用方法为: connection.start() .then(() => { connection.invoke("adduserToConnection",account,connection.connectionId); }) .catch((err) => { console.erro ......

CF1257E The Contest

用桶存,做一遍前缀和,令 \(b_{x,y}\) 表示序列 \(x\) 包含 \(1\sim y\) 的数字个数。考虑枚举第一个序列保留的前缀 \(1\sim i\),对于第三个序列,如果其保留了后缀 \(j\sim n(i<j)\),考虑哪些数需要被移掉,那么答案就是: \[b_{1,n}-b_{ ......
Contest 1257E 1257 The CF