economist from the to

Step by step guide to becoming a C++ developer in 2023

https://roadmap.sh/cpp https://roadmap.sh/backend ......
developer becoming guide Step 2023

QT在debug环境下的异常报错 This application failed to start because no Qt platform plugin could be initialized. Reinstalling the application may fix this problem.

查看错误信息:试试Release 检查 控制台 (/SUBSYSTEM:CONSOLE) 输入错误信息,修改全部报错信息后再试试Debug模式可不可以运行。 方案一:高级系统设置-环境变量- QT_QPA_PLATFORM_PLUGIN_PATH C:\Qt\Qt5.12.12\5.12.12\ms ......

nas硬件选择笔记from天马

硬件选择和Nas系统的选择 系统 收费 厂商 厂商价格系统预估价格优势 群晖 (3289 418PALY) 2389 优化多,适合小白 威联通 (1399TR-004) 499 易用性弱于群晖,性价比高 铁威马 (1033 F4-210) 133 免费 品牌问题 FreeNAS 1.缺少定制app ......
硬件 笔记 from nas

Converting Virtual Addresses to Physical Addresses

Converting Virtual Addresses to Physical Addresses Most debugger commands use virtual addresses, not physical addresses, as their input and output. Ho ......
Addresses Converting Physical Virtual to

‘Proof of the pudding’: Global variables and PAGE_EXECUTE_WRITECOPY

‘Proof of the pudding’: Global variables and PAGE_EXECUTE_WRITECOPY UNCATEGORIZED PRODUCTION DEBUGGING, WINDBG LEAVE A COMMENT Today I was teaching a ......

Androidstudio中 unable to execute Clang-tidy clazy-standalone is not found or cannot be exexute

这个问题可能是因为Android Studio不支持clazy,但是在设置菜单中仍然提供了这个选项,并且在这种情况下,它似乎被启用了¹。当通过clangd启用clang-tidy时,没有什么需要做的。当通过clangd禁用clang-tidy时,如果启用了clazy,就会出现这个错误¹。 要解决这个 ......

【NIPS2021】Twins: Revisiting the Design of Spatial Attention in Vision Transformers

来自美团技术团队♪(^∀^●)ノシ 论文地址:https://arxiv.org/abs/2104.13840 代码地址:https://git.io/Twins 一、写在前面 本文提出了两种视觉转换器架构,即Twins-PCPVT和Twins-SVT。 Twins-PCPVT 将金字塔 Trans ......

Paper Reading: Learning from Weak-Label Data: A Deep Forest Expedition

目录研究动机文章贡献本文方法标签补码结构标签频率估计与补码标志机制LCForest 整体框架实验结果实验设置基因功能分析任务实验文本分类任务实验场景分类任务实验医学自然语言处理实验优点和创新点 Paper Reading 是从个人角度进行的一些总结分享,受到个人关注点的侧重和实力所限,可能有理解不到 ......

smb this client does not support the negotiated dialect

global添加以下配置信息 [global] min protocol = LANMAN2 min protocol = SMB2 max protocol = SMB2 client min protocol = SMB2 client max protocol = SMB2 ......
negotiated dialect support client does

F. Lisa and the Martians

F. Lisa and the Martians 问题求y =(a[i] ^ x)& (a[j] ^ x)最大,可知x可自由选择,那么我们就考虑y怎么取最大值 1.根据&,可知a[i]a[j]1时,二进制该位置为1,若x可使得俩位置为1,那么就转换成最多的a[i]==a[j]的位置,也就是a[i]^ ......
Martians Lisa and the

yisa_get_msg_from_kafka_per_pn.py

#!/usr/bin/python #-*- coding: utf-8 -*- # 抽取kafka数据到redis_mq模块 # 作者:王成 # 日期:2017-04-14 import MySQLdb import time import sys import redis import requ ......

Exception in thread "main" java.lang.UnsupportedClassVersionError: org/example/JobMain has been compiled by a more recent version of the Java Runtime (class file version 61.0), 问题的解决(未解决)

问题描述 使用hadoop在虚拟机里面运行打包的程序出错: 问题解决 真的服了,貌似是jdk的版本啥的问题,搜了好多,就是解决不了,求助求助啊! ......

The 2021 ICPC Asia Macau Regional Contest

A. So I'll Max Out My Constructive Algorithm Skills 首先一行正一行反的把所有的行拼到一起,然后判断一下正着走时候合法不合法就反过来走就好。 #include <bits/stdc++.h> using namespace std; #define ......
Regional Contest Macau 2021 ICPC

The 2022 ICPC Asia Jinan Regional Contest

A. Tower 首先用了 dp 验证出把一个数字变成另一个数字的最优解一定是能除就先进行除法,然后再使用加一减一。 这样我们就有\(O(\log n)\)的复杂度求出把一个数变成另一个数的最小代价。 然后就是猜测最终的目标一定是某个数除了若干次二得到的。所以就枚举一下目标即可。 #include ......
Regional Contest Jinan 2022 ICPC

to String、equal、clone() 方法

字符串表示形式如图: 1、toString 存在是为了让子类去重写,以返回对象的内容(a、鼠标右键点生成可以找到toString b、直接输入toS,按回车,接续按回车,就重写好了) 2、equals 默认判断两个对象的地址是否相等,重写是为了比较对象的内容是否一样 3、(了解)clone() 方法 ......
方法 String equal clone to

【倍增】P3422 [POI2005]LOT-A Journey to Mars 题解

P3422 一道有点意思的题。 看到是一个环,先破环为链,即 \(a_{n+i}=a_i, b_{n+i}=b_i\),此时就只需要跳到 \(x+n\) 而无需判环了。 如果顺时针走: 令 \(sum_i = \sum\limits_{j=1}^{i}{a_j-b_j}\),当能从 \(x\) 跳到 ......
题解 Journey P3422 LOT-A 3422

nvidia-smi指令报错:Failed to initialize NVML: Driver/library version mismatch NVML library version: 535.113解决

nvidia-smi指令报错:Failed to initialize NVML: Driver/library version mismatch NVML library version: 535.113 我是刚开始没有nvidia-smi命令,输入后,提示我安装。 apt install nvi ......
library version NVML 指令 nvidia-smi

报错AttributeError: Attempted to set WANDB to False, but CfgNode is immutable

问题 今天在跑代码的时候,使用到了wandb记录训练数据。 我在23服务器上跑的好好的,但将环境迁移到80服务器上重新开始跑时,却遇到了如下报错 看这个报错信息是由于wandb没有apis这个属性,于是我定位到具体的报错代码 😯原来程序在import wandb时就抛出异常了。 解决方法 我尝试验 ......

CF1249(Div. 3) 题解(A to D)

\(\texttt{E F}\) 忘(不)记(会)写了。 A Yet Another Dividing into Teams 题解 题目大意 有一个长度为 \(n\) 的序列 \(a_1,a_2,\cdots,a_n\),将他们分为若干组,使得每一组没有两个数的差为 \(1\),使分的组数尽可能少。 ......
题解 1249 Div CF to

C error:deprecated conversion from string constant to 'char*' [-Wwrite-strings]

问题描述 解决C++中[Warning] deprecated conversion from string constant to 'char*' [-Wwrite-strings] char *string= "aaabbbcc"; //warning的原因是字符串常量存放在const内存区.. ......

asp.net mvc Core 网页错误提示:An unhandled exception occurred while processing the request.处理请求时发生未处理的异常。

网页错误提示: An unhandled exception occurred while processing the request. InvalidOperationException: The entity type 'IdentityUserLogin<string>' requires ......

The 2018 ACM-ICPC Asia Qingdao Regional Contest, Online (The 2nd Universal Cup

The 2018 ACM-ICPC Asia Qingdao Regional Contest, Online (The 2nd Universal Cup. Stage 1: Qingdao) J - Press the Button \(1 \leq a, b, c, d \leq 10^6\) ......
The Universal ACM-ICPC Regional Contest

vue-router.esm.js:2065 Uncaught (in promise) Error: Redirected when going from "/login?redirect=%2Fhome" to "/home" via a navigation guard.

原因: vue-router路由版本更新产生的问题,导致路由跳转失败抛出该错误; 真正的原因是由于返回了一个Promise对象, 正常的跳转由then方法执行 当正常的路由跳转, 被"路由导航守卫"拦截并重新指定路由时, 由于 this.$router.push() 返回的是Promise对象, 此 ......

Go - Decoding Data with a Customized Binary Format to Structs

Problem: You want to decode the customized binary format back to structs. Solution: Use the encoding/binary package to take data from the binary forma ......
Customized Decoding Structs Binary Format

Go - Encoding Data to a Customized Binary Format

Problem: You want to encode struct data to a customized binary format. Solution: Design your customized format and use the encoding/binary package to ......
Customized Encoding Binary Format Data

Go - Decoding gob Format Data to Structs

Problem: You want to decode gob format data back to structs. Solution: Use the encoding/gob package to decode the gob format data back to structs. fun ......
Decoding Structs Format Data gob

Go - Encoding Data to gob Format Data

Problem: You want to encode structs into binary gob format. Solution: Use the encoding/gob package to encode the structs into bytes that can be stored ......
Data Encoding Format gob Go

The 2023 CCPC Online Contest (The 2nd Universal Cup, Stage 3: Binjiang)

题解: https://files.cnblogs.com/files/clrs97/CCPC-Online-2023-%E9%A2%98%E8%A7%A3.pdf Code: A. Almost Prefix Concatenation #include<cstdio> #include<cstr ......
The Universal Binjiang Contest Online

The 20th Zhejiang Provincial Collegiate Programming Contest Sponsored by TuSimple

题解: https://files.cnblogs.com/files/clrs97/2023_ZJCPC_Tutorial.pdf Code: A. Look and Say #include<bits/stdc++.h> using namespace std; int main() { ios ......

The 2023 ICPC Asia EC Regionals Online Contest (I) - Problem C. Multiply Then Plus

离线询问,建立时间线段树,那么每条直线存在的时间是一个区间,对应时间线段树上$\mathcal{O}(\log n)$个节点,每个询问对应时间线段树上某个叶子到根的$\mathcal{O}(\log n)$ 个节点。 对于时间线段树中的某个节点,它代表的直线集合是静态的,问题转化为静态区间查询。对于 ......
Regionals Multiply Contest Problem Online