programming provincial collegiate sponsored
Dynamic Programming
目录热身198. 打家劫舍62. 不同路径63. 不同路径 II213. 打家劫舍 II337. 打家劫舍 III 参考：https://cloud.tencent.com/developer/article/1692068 热身 斐波那契数列 递归求解 自顶向下，存在大量的重复计算 动态规划 保存 ......
Programming Abstractions in C阅读笔记：p196
《Programming Abstractions in C》学习第63天，p196总结。涉及到编程之外的知识，依然是读起来很费劲，需要了解作者在书中提到的人物(Edouard Lucas)、地点(Benares)、神话传说(Brahma)等等。虽然深知自己做不到对人文知识，历史知识精通，但也希望能 ......
mount: /home/vi/book: wrong fs type, bad option, bad superblock on /dev/sdd1, missing codepage or helper program, or other error.
mount: /home/vi/book: wrong fs type, bad option, bad superblock on /dev/sdd1, missing codepage or helper program, or other error. 解决方法： sudo mount -t ......
Toyota Programming Contest 2023#7（AtCoder Beginner Contest 328）
Toyota Programming Contest 2023#7（AtCoder Beginner Contest 328） A. Not Too Hard 题意： 将给定的数列\(a\)中数值小于\(x\)的数累加。 解题思路: 模拟。 代码: #include<bits/stdc++.h> u ......
The 10th Jimei University Programming Contest
外校打星队伍，排名22/450，还算凑合吧。 A. A+B问题 直接枚举进制 #include <bits/stdc++.h> using namespace std; using vi = vector<int>; void solve() { string str; vi a, b, s; ci ......
2017 China Collegiate Programming Contest Final (CCPC-Final 2017)
目录写在前面EACKJGI写在最后 写在前面 比赛地址：https://codeforces.com/gym/104207。 以下按照个人向难度排序。 妈的怎么感觉有八十万件杂七杂八的事要做。 受不了了，真想直接消失。 这比大学是一秒也不想上了。 E 签到题，看都没看。 code by dztlb: ......
Programming abstractions in C阅读笔记：p184-p195
《Programming Abstractions In C》学习第61天，p184-p195总结。 一、技术总结 1.mutual recursion 2.natural number (1)定义 p184, If you limit the domain of possible values t ......
Japan Registry Services (JPRS) Programming Contest 2023 (AtCoder Beginner Contest 324) 赛后总结
Japan Registry Services (JPRS) Programming Contest 2023 (AtCoder Beginner Contest 324) 赛后总结 可悲的是：我没来得及写题解。 Task A Same 秒切。 直接输入排一遍序再遍历即可。 #include <bi ......
HHKB Programming Contest 2023(AtCoder Beginner Contest 327) 赛后总结
HHKB Programming Contest 2023(AtCoder Beginner Contest 327) 赛后总结 又没来得及写题解。。。 赛时 A - ab 查找 ab 和 ba，只要其中一者存在就行。 #include <bits/stdc++.h> using namespace ......
HHKB Programming Contest 2023(AtCoder Beginner Contest 327)
HHKB Programming Contest 2023(AtCoder Beginner Contest 327) A - ab int main() { IOS; string s; cin >> n >> s; bool f = false; for (int i = 1; i < n; + ......
HHKB Programming Contest 2023(AtCoder Beginner Contest 327)
HHKB Programming Contest 2023(AtCoder Beginner Contest 327) A. ab 解题思路: 模拟即可。 代码: #include <bits/stdc++.h> using namespace std; using ll = long long; ......
"Grain for Green" program: turn sand into green
"Grain for Green" program: turn sand into green One specific measure that has been effective in tackling desertification is the "Grain for Green" prog ......
[935] Python Programming in QGIS3
ref: Getting Started With Python Programming (QGIS3) ref: 1.4.1. Using PyQGIS in standalone scripts ......
【算法笔记】动态规划Dynamic Programming
参考视频：5 Simple Steps for Solving Dynamic Programming Problems 引子：最长递增子串（Longest Increasing Subsequence，LIS） LIS([3 1 8 2 5]) = len([1 2 5]) = 3 LIS([5 ......
Python:重装Python后，在pycharm运行报错——Cannot run program "C:\Users\*****\Python36\python.exe" (in directory "E:\www\python_tony\spider"): CreateProcess error=2, 系统找不到指定的文件。
电脑重装Python后，重新打开Pycharm执行python，发现报错：Cannot run program "C:\Users\***\Python36\python.exe" (in directory "E:\www\python_tony\spider"): CreateProcess e ......
NOMURA Programming Competition 2020 D Urban Planning
考虑排列 \(P_i\) 已经固定了的情况，那么连边 \(i\to P_i\) 形成有向图 \(G\)，最小连边数就是 \(N\) 减去弱连通块数。善良的出题人已经告诉你连边方案就是 \((N-1)^K\)，所以答案就是 \(N(N-1)^K\) 减去所有连边方案中弱连通块数量总和。于是只需要考虑所 ......
容器报错 Error response from daemon: driver failed programming external connectivity on endpoint
在启动容器时的容器时，会出现报错：Error response from daemon: driver failed programming external connectivity on endpoint XXX（端口映射或启动容器时报错） 如下： 原因：在我们启动了Docker后，我们再对防火 ......
[Compose] Concurrency + Channel and Reactive programming for JS
Concurrency + Channel (CSP): Concurrency is a way to run operation in isolated thread, a way to better utilize the CPU resources and handle multi simu ......
MIGO Runtime Errors MESSAGE_TYPE_X program SAPLCKM4 in PERIODENART_BESTIMMEN
用户在测试环境执行MIGO，系统dump 检查系统后，发现是物料账期错误 修改账期，系统正常 ......
Error: EPERM: operation not permitted, mkdir 'C:\Program Files\nodejs\cache\_cacache\index-v5\00\c2'
使用下面命令创建react项目爆出的错误 npx create-react-app react-basic 显示nodejs里面的文件权限不够，需要进行文件夹的权限更改，改为完全控制就可以了。 ......
Programming abstractions in C阅读笔记：p181-p183
《Programming Abstractions In C》学习第61天，p181-p183总结。 一、技术总结 1.linear search algorithm 2.lexicographic order(字典顺序) 3.binary search algorithm(二分查找算法) /* * ......
distributed-programming-in-java
WEEK 1 1 MAP-REDUCE HADOOP K-V pair Spark Resilient distributed dataset Page Rank Rank(B) = sum (Rank(A) / DEST_COUNT(A)) Week2 Socket JVM_A -> JVM_B ......
Dynamic programming basic principle
There is a confusing question, i.e. the name of this method is dynamic programming, how can we understand it ? The dynamic programming in chinese is " ......
课程二第三周：Hyperparameter tuning, Batch Normalization and Programming Frameworks
Hyperparameter tuning Tuning process 到目前为止，接触到的超参数有： 学习效率learning-rate：\(\alpha\) Momentum算法的参数：\(\beta\) 加权平均的参数 Adam算法的参数：\(\beta_1、\beta_2、\epsilon ......
[Compose] Async programming: Thunks
Thunks Sync thunk: A blocker of code which has everything ready and can return the value directly. function add(x, y) { return x + y } const thunk = f ......
Program does not contain a static 'Main' method suitable for an entry point
http://www.kangry.net/blog/?article_id=391&type=article 修改办法，对着项目右键-》属性-》application-》output type设为Class Library即可。 ......
Japan Registry Services (JPRS) Programming Contest 2023 (AtCoder Beginner Contest 324) 赛后总结
Japan Registry Services (JPRS) Programming Contest 2023 (AtCoder Beginner Contest 324) 赛后总结 可悲的是：我没来得及写题解。 T1 Same 秒切。 直接输入排一遍序再遍历即可。 #include <bits/s ......
比赛总结：Japan Registry Services (JPRS) Programming Contest 2023 (AtCoder Beginner Contest 324)
比赛：Japan Registry Services (JPRS) Programming Contest 2023 (AtCoder Beginner Contest 324) A-same 1.常规方法 int main() { int n; cin >> n; vector<int> s(n) ......
[Compose] Callback is not suitable for Async programming
An example of callback implemnetation for handling async flow: function fakeAjax(url, cb) { var fake_responses = { file1: "The first text", file2: "Th ......
2019-2020 ICPC Northwestern European Regional Programming Contest (NWERC 2019)
\(A. Average Rank\) 将每个人的排名看作是前面一个人的贡献，然后采用类似懒标记的形式优化复杂度。 int sum[N],point[N],cnt[N],pre[N],laz[N]; void solve(){ int n=read(),w=read(); laz[0]=w; cnt ......