the series find sum
AtCoder World Tour 2022 B The Greatest Two
原题面：https://atcoder.jp/contests/wtf22-day2/tasks/wtf22_day2_b 题面翻译： 一个长度为 \(n\) 的排列 \(p\)，每次可以把一个长 \(k\) 区间的最大与次大值交换，问操作任意次数后可以得到的排列数量对 \(998244353\) ......
Introducing the incident management
Forward Today, we talk about the significance of incident management. Firstly, we start it by some simple concepts. What exactly the incident is? Or w ......
A connection was successfully established with the server but then an error
在使用EFCore生成数据库的时候，报上面的错误！ 解决方法： 加（Encrypt=True;TrustServerCertificate=True;）即可： "ConnectionStrings": { "DefaultConnection": "Data Source=LAPTOP;Initia ......
find
find用法 在指定目录下查找文件 补充说明 find命令 用来在指定目录下查找文件。任何位于参数之前的字符串都将被视为欲查找的目录名。如果使用该命令时，不设置任何参数，则find命令将在当前目录下查找子目录与文件。并且将查找到的子目录和文件全部进行显示。 语法 find(选项)(参数) 选项 -e ......
An improved LSTM-based model for identifying high working intensity load segments of the tractor load spectrum
一区top Computers and Electronics in Agriculture 题目： “基于改进 lstm 的拖拉机载荷谱高工作强度载荷段识别模型” (pdf) “An improved LSTM-based model for identifying high working in ......
web项目启动时dubbo报错： No provider available for the service com.davidhu.shopguide.api.service.UserEventService from the url zookeeper ://localhost:2181/org.apache.du
Caused by: java.lang.IllegalStateException: Failed to check the status of the service com.davidhu.shopguide.api.service.UserEventService. No provider ......
初中英语优秀范文100篇-056I have the courage to accept the challenge-我有勇气接受挑战
PDF格式公众号回复关键字:SHCZFW056 记忆树 1 Every year there is a singing competition in our school. 翻译 每一年，我们学校都会举行一场歌唱比赛。 简化记忆 比赛 句子结构 主语 ("Every year")：表示时间状语的短语 ......
org.springframework.kafka.listener.ListenerExecutionFailedException: Listener method could not be invoked with the incoming message
问题描述 kafka在yml文件中未开启批量消费时，程序正常运行；但一开启正常消费后，就直接报错；排查问题的过程中一直觉得是配置文件里的问题，最后发现是消费者接受的参数类型错误 问题本质 消费者开启批量消费数据后，不能用单个实体类接收参数，而应该用list 解决方法 修改消费者函数参数类型 ......
redis报错MISCONF Errors writing to the AOF file: No space left on device，磁盘满无法写入数据报错
查询报错远程调用接口异常，F12查看网络和标投和预览到是mgr的接口此错误#根据报错提示：Error in execution; nested excepti on is io.lettuce.core.RedisCommandExecutionException: MISCONF Errors w ......
find命令的时间参数
find命令可以按照时间条件查找文件。 find {path} -newermt {time}其实find -newermt的真正形式是find -newerXY {variable}，旨在找到一些X属性比variable的Y属性更早的文件。其中X指代find的目标文件属性，Y代表参照属性。X可选a ......
[linux kernel] struct pid && the way the kernel used to cast uint32_t pid to struct task_struct
摘抄内容引用自linux kernel document description pre the initialization and the manage of the struct pid is use IDR.(implement by hash table->(why not array?- ......
[Linux] 常用命令之【md5sum(MD5校验)】
0 序 本文主要参考自: Linux命令之MD5校验md5sum 1 命令概述 1.1 用途 md5sum : 用于计算和校验文件的MD5值。 $ echo "hello world" | md5sum.ex 6f5902ac237024bdd0c176cb93063dc4 *- md5sum 常常 ......
LLM series: Transformer
🥥 Homepage Dataset, DataLoader, and Transforms Model Traning Model 🥑 Get Started! Import libraries: import torch import torch.nn as nn import torch. ......
Redis - (error) WRONGTYPE Operation against a key holding the wrong kind of value
zzh@ZZHPC:~$ docker exec -it redis redis-cli 127.0.0.1:6379> SET bike:1 "Process 134" OK 127.0.0.1:6379> GET bike:1 "Process 134" 127.0.0.1:6379> HSET ......
The Acdamic Guideline
How to write your papers？ Introduction Problem Methods Results Simulation How to start your research？ Observation Problem Reserach Hypothesis Experime ......
解决前后端的跨域问题：Access to XMLHttpRequest at '**' from origin '**' has been blocked by CORS policy: No 'Access-Control-Allow-Origin' header is present on the requested resource.
报错信息： Access to XMLHttpRequest at 'http://localhost:8182/cooperationRequest/getList' from origin 'http://localhost:3004' has been blocked by CORS poli ......
android编译kanzi 问题 (1) Caused by: java.io.FileNotFoundException: Error: Could not find or access Kanzi's Android libraries directory: C:\XXXXXXX
问题原因: 当前的安卓工程找不到kanzi 的android库库目录。大多数的android工程里都会带有一个kanzi_home的路径，这个和本机不匹配就会有该问题。 解决办法： android_gradle 下的local.properties 改下kanzi home 路径，跟自己本机电脑的环 ......
Understanding the linux kernel Chapter2 Memory Addressing
Physical Memory Layout unavailable address for kernel either because they map hardware devices’ I/O shared memory or because the corresponding page fr ......
并行 sha256sum 命令
之前为文件夹里的文件生成 SHA-256 摘要时，我使用的是 sha256sum *.mp4 *.xml *.jpg > sha256sums.txt 这个命令是逐个生成哈希值的，在计算完成 1.mp4 之前并不会开始计算 2.mp4，不能很好得利用多核性能。 解决办法也很简单，利用“百闻不如一见” ......
No 'Access-Control-Allow-Origin' header is present on the requested resource'， 跨域访问的解决方法
https://blog.csdn.net/dear_little_bear/article/details/83999391 1. 当请求不在同一域名下的资源文件（ip地址+端口号）时，会报如下错误：“No ‘Access-Control-Allow-Origin’ header is prese ......
Unlocking the Road to Success: The Benefits of Online Driver's Education
In the fast-paced world we live in, online education has become a staple for acquiring new skills and knowledge. This trend extends to driver's educat ......
The Evolution of Smart Car Technology: A Glimpse into the Future of Mobility
In the last decade, the automotive industry has witnessed a transformative shift towards smart car technology. Once a futuristic concept, smart cars a ......
vue报错：You may use special comments to disable some warnings. Use // eslint-disable-next-line to ignore the next line. Use /* eslint-disable */ to ignore all warnings in a file.
报错信息： 解决方法： ESLint 语法错误，那就取消ESLint验证规则 然后重启即可 ......
CF Beta Round 93-D.Fibonacci Sums-齐肯多夫分解、DP
CF Beta Round 93-D.Fibonacci Sums-齐肯多夫分解、DP https://codeforces.com/contest/126/problem/D 定义Fibonacci序列：\(F_1=1,F_2=2,F_k=F_{k-1}+F_{k-2}(\forall k\geq ......
the ObjectARX system dynamic linker object
ObjectARX Reference Guide > Macros > AcRx Macros > acrxDynamicLinker Macro acrxDynamicLinkerC++ define acrxDynamicLinker \ AcRxDynamicLinker::cast(acr ......
MySQL Ignoring the redo log due to missing MLOG_CHECKPOINT between the checkpoint
错误信息： 2023-12-12T09:32:31.383149Z 0 [ERROR] InnoDB: Ignoring the redo log due to missing MLOG_CHECKPOINT between the checkpoint 5777611209 and the end ......
CF1523H Hopping Around the Array
首先考虑 \(k = 0\) 的情况。 贪心，最后一步之前每个 \(i\) 只会跳到 \(j \in [i, i + a_i]\) 且 \(j + a_j\) 最大的点 \(j\)，这个信息或许可以线性处理？但是我没脑子，我用线段树维护，时间复杂度 \(\mathcal O(n \log n)\)。 ......
CF1886E I Wanna be the Team Leader 题解
Problem - E - Codeforces I Wanna be the Team Leader - 洛谷 差一点就想到了/ll 遇到困难？排序肯定不会变差！ 性质：每个项目分配的程序员肯定是一段（显然） \(m\) 很小？考虑设 \(dp_{i,S}\) 表示考虑前 \(i\) 个人选项目集 ......
6 Fear of the Dark
题目是一定有答案的，说明所有的情况都是可行的，那么就会有两种情况 1 两个圆都包括了起点和终点 2 一个原包括了起点，另一个原包括了终点（圆一定是相交的） #include<bits/stdc++.h> using namespace std; double dx(int x1,int y1,int ......