average keep high the

2023-10-24 Too many re-renders. React limits the number of renders to prevent an infinite loop. ==》组件在渲染过程中执行了任务导致状态更新,从而触发了无限循环

React报错: Too many re-renders. React limits the number of renders to prevent an infinite loop. 重新渲染过多。React限制渲染次数,以防止出现无限循环。 解决方案:查看你最近写的代码,比如我写了一个函数组件 ......
renders re-renders 组件 infinite 状态

[VM] The JavaScript Virtual Machine

Table of Content Introudction to VMs CPU - Understanding the Pysical Machine VMs - Arrays, Objects, functions, prototype chains DepotExplorer: collect ......
JavaScript Machine Virtual The VM

Maven打包报错问题的解决-- No goals have been specified for this build. You must specify a valid lifecycle phase or a goal in the format

问题描述 在使用maven执行打包操作时,出现了这样的错误: 上面的图片是网上的图,我的图片忘记截图了; 问题解决 在我们创建的项目里面的pom.xml文件里面的dependencies标签后面,新建一个build标签, 并在build标签里面放上这句代码: <defaultGoal>compile ......
specified lifecycle specify format 问题

[925] GDA2020_MGA and change the spatial reference in ArcGIS Pro

ZONE50: 114.0 120.0 - arcpy.mp.spatialReference("GDA2020_MGA_Zone_50") ZONE51: 120.0 126.0 - arcpy.mp.spatialReference("GDA2020_MGA_Zone_51") ZONE52: ......
reference spatial ArcGIS change 2020

The 2nd Universal Cup. Stage 6: Warsaw L.Spectacle (思维)

大致题意: 给定n个玩家,每个玩家有一个战力值,安排 x (1 <= x <= n/2(向下取整))场游戏,每场游戏安排x对玩家对战,对于每一场游戏每个玩家只能参加一次对战,要求对于每x场玩家对战的两个玩家rating差的最大值尽可能小。 例如给定6个玩家战力值为10 13 14 20 100 10 ......
Spectacle Universal 思维 Warsaw Stage

OGG-03542 Failed to connect to the database

GGSCI (dwdb01) 4> dblogin userid GOLDENGATE@cnlionrdb,password ******* 2023-10-23 17:11:26 INFO OGG-03542 Failed to connect to the database. Verify th ......
database connect Failed 03542 to

The 2018 ACM-ICPC Asia Qingdao Regional Contest, Online (The 2nd Universal Cup. Stage 1: Qingdao)

Preface 好以后我就是SUA铁粉了,每次打SUA出的题感觉都很好,全程有事情干并且中档题很多很适合我们队这种比上不足的队伍打 不过yysy这场题目偏数据结构和图论方面比较重,而数学方向则不多,刚好撞上了我们队熟悉的地方,因此最后卡着时间过了9题 而且最近CF评测机不知道咋了,这场好多题光读入用 ......
Qingdao The Universal ACM-ICPC Regional

CF1479B1 Painting the Array I

如果两种方案末尾两数有一数相同,那么答案较大的方案不劣于答案较小的方案。答案较大的方案只需\textbf{模仿}答案较小的方案即可,在状态变成相同之前答案最多只会少 \(1\)。 所以只需要考虑末尾两数 \(a,b\) 与新进来的数 \(c\) 各不相同时该替换哪个。 假设 \(a\) 下次出现的位 ......
Painting 1479B Array 1479 the

【译】A unit of profiling makes the allocations go away

在 Visual Studio 17.8 Preview 2 中,我们更新了单元测试分析,允许你在性能分析器中使用任何可用的工具——而不仅仅是仪表工具。有了这个更改,可以很容易地快速分析孤立的小工作单元,进行更改,然后重新度量和验证更改的影响。 ......
allocations profiling makes unit away

CF1886D Monocarp and the Set

Link 此题目可以从两个方向考虑,正着和倒着,倒着考虑比较容易,首先把所有的数放到一块,如果是'<'或者'>',就是去掉最左边或者最右边的数,这样显然只有一种可能,答案不变。 如果是'?',那么显然可以去掉中间的任意一个,所以答案就是\(\times l-2\),那么对于\(s_n-i\)位置的\ ......
Monocarp 1886D 1886 and Set

npm安装datav-vue3(一个大屏边框和装饰组件)后报错Failed to resolve entry for package "@dataview/datav-vue3". The package may have incorrect main/module/exports specified in its package.json.

原因:个人认为应该是npm上的版本比较低,因为弄好后装饰只能用到第8个,后面的都没有,查看package.json里它的版本为^0.0.0-test.1672506674342,也就是说还没有正式版,在官方的说明里也有体现 [目前还处于 Alpha 阶段,所有的 API 及 Props 都可能在后续 ......
package datav-vue datav 大屏 边框

[LeetCode] 1356. Sort Integers by The Number of 1 Bits 根据数字二进制下1 的数目排序

You are given an integer array arr. Sort the integers in the array in ascending order by the number of 1's in their binary representation and in case ......
二进制 数目 LeetCode Integers 数字

E: The repository 'xxx' is not signed.

在ubuntu上安装了google chrome, 运行时有问题,删除了之后再次运行 sudp apt update 会报错 E: The repository 'http://dl.google.com/linux/chrome/deb stable InRelease' is not signe ......
repository signed 39 The not

Codeforces Round 855 (Div. 3) C. Powering the Hero

有 \(n\) 张卡的卡堆,你可以自顶向下抽卡。装备卡显示数值为 \(a_i(a_i>0)\) ,英雄卡显示数值为 \(a_i = 0\) 。 如果是装备卡,你可以将卡抽出放在装备堆。如果是英雄卡,你可以将装备堆顶端的一张数值为 \(x\) 的装备卡装备给英雄,英雄数值 \(+ x\) 。无论是否装 ......
Codeforces Powering Round Hero 855

救济金发放(The Dole Queue, UVa 133)

#include<stdio.h> #include<string.h> #define maxn 100 int n,k,m,a[25]; int left, chance; int win, lose; char s[maxn], s2[maxn]; int go(int p, int d, i ......
救济金 Queue Dole The 133

The 2021 CCPC Guangzhou Onsite

Preface 逆天PKU,出的什么寄吧东西,做题全靠打表找规律,一场比赛全是\(\bmod 998244353\) 4题成功从金到铜完美区分,我们队VP的时候两个半小时就下班了,看祁神写了3h的大几何题L 虽然徐神开场一眼看出了F是个诈骗题,但推了1h无果还是要上机打表找规律才发现式子 最后和徐神 ......
Guangzhou Onsite 2021 CCPC The

The 2021 CCPC Guilin Onsite (XXII Open Cup, Grand Prix of EDG)

Preface 昨天下午16:30~21:30刚打完CCPC2021的广州,今天早上九点又开始打这场桂林,压力拉满了属于是 这场比起昨天那场良心太多了,开场还挺顺(虽然因为写Dijkstra偷懒TLE了四发),但开题啥的都是见一个会一个 中期虽然有点卡但因为祁神会了几何所以没有空机,然后再点完外卖后 ......
Guilin Onsite Grand 2021 CCPC

Unexpected character '=' (code 61); expected a semi-colon after the reference for entity 'useSSL' at [row,col,system-id]: [8,75,"file:/usr/bigdata/hive-3.1.3/conf/hive-site.xml"]

在初始化hive时报错,出现如下问题: 错误原因:hive-site.xml 配置文件中,数据库的地址带有 & 符号。 将数据库地址中的 & 符号调整为 &amp;,详情如下: 再次初始化hive,执行结果如下: ......
39 hive quot Unexpected semi-colon

The innodb_system data file 'ibdata1' must be writable

MySQL无法启动 Active: deactivating (stop-sigterm) (Result: exit-code) 查看配置文件中的日志存储位置: view /etc/my.cnf 查看日志存储文件位置:/var/log/mysqld.log 文件错误提示:The innodb_sy ......
innodb_system writable ibdata1 innodb ibdata

The JSON value of length n is too large and not supported

https://github.com/dotnet/runtime/issues/39953 I'm referring to this issue #30746 that was closed with limit of 125MB staying fixed opposed to being c ......
supported length value large JSON

Docker启动失败,报错Cannot connect to the Docker daemon at unix:///var/run/docker 完美解决方案

问题描述: Cannot connect to the Docker daemon at unix:///var/run/docker.sock. Is the docker daemon running? 首次安装docker后,服务没有自启动 解决方案: 查看docker状态 1 service ......
Docker 解决方案 connect 方案 Cannot

Docker启动报错:Cannot connect to the Docker daemon at unix:///var/run/docker.sock. Is the docker daemon running?

问题描述: Docker启动报错:Cannot connect to the Docker daemon at unix:///var/run/docker.sock. Is the docker daemon running? Cannot connect to the Docker daemon ......
Docker daemon docker the connect

sonarqube启动报错:You must address the points described in the following [2] lines before starting Elasticsearch.bootstrap check XXXmax numberXXXfor user[sonar] is too low .XXX check the logs at XXX/.log

You must address the points described in the following [2] lines before starting Elasticsearch.bootstrap check failure [1] of [2]: max number of threa ......

B. Chips on the Board

B. Chips on the Board 题意:保证在n*n的棋盘上对于每一个点的列或者行都有一个筹码,也可以两个都有,问最小筹码:对于每一个筹码计算:a[i]+b[i]; 要使每个点都满足,最少的筹码的个数应该为n 1.对于行来看,如果每一行都有一个筹码,那么列就可以随便填:直接全选择最小的列 ......
Chips Board the on

Vivado生成bitstream时报错[Opt 31-67] Problem: A LUT3 cell in the design is missing a connection on input pin I1, which is used by the LUT equation

这个原因主要是因为有一个引脚没有用到,解决方法。 1、打开Schematic。 2、根据提示的模块去找,比如说我的报错。 [Opt 31-67] Problem: A LUT3 cell in the design is missing a connection on input pin I1, w ......
connection LUT bitstream the equation

[918] Copy the formatting from one cell in a table of a Word document to another cell in Python

To copy the formatting from one cell in a table of a Word document to another cell, you can use the python-docx library in Python. Here's a step-by-st ......
cell formatting document another Python

[919] Change the horizontal alignment of a cell to center within a table of a Word document using Python

To change the horizontal alignment of a cell to center within a table of a Word document using Python and the python-docx library, you can set the ali ......
horizontal alignment document Change Python

[920] Copy the font style from one cell in a table of a Word document to another cell using Python

To copy the font style from one cell in a table of a Word document to another cell using Python and the python-docx library, you can access the font p ......
cell document another Python style

Codeforces Round 872 (Div. 2) B. LuoTianyi and the Table

给一个 \(n \times m\) 的矩阵和 \(n \times m\) 个数,你需要把这些数填入矩阵。保证 \[\sum_{i=1}^n \sum_{j=1}^m \left ( \mathop{max}\limits_{1 \leq x \leq i, 1 \leq y \leq j} a_ ......
Codeforces LuoTianyi Round Table 872

CF367C Sereja and the Arrangement of Numbers

这题首先上来会发现题目中的很多信息都是假的,核心就是问要构造一个\(x\)个点的完全图至少要多长的序列 我们把序列中相邻的两个元素看作图上的一条边,则可以把问题转化为:给一个\(x\)个点的完全图,问至少要走多长的路径才可以遍历图中的所有边至少一次 简单讨论下会发现当\(x\)为奇数时,此时图中每个 ......
Arrangement Numbers Sereja 367C 367