average keep high the

[题解]CF1881G Anya and the Mysterious String

思路 发现如果一个字符串中有长度大于等于 \(2\) 回文子串,必定有长度为 \(2\) 的回文子串或长度为 \(3\) 的回文子串,并且形如:aa 和 aba。 所以考虑用线段树这两种情况。维护一段区间的最左、次左、最右、次右的元素,同时用两个标记变量 \(f_1,f_2\) 分别表示这个区间中是 ......
题解 Mysterious String 1881G 1881

PAT_A 1038 Recover the Smallest Number

Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given { 32, 321, 3214, 0229, 87 }, we c ......
Smallest Recover Number PAT_A 1038

How to get macOS CPU details information in the command line All In One

How to get macOS CPU details information in the command line All In One 如何通过命令行获取 macOS CPU 的详细信息 ......
information details command macOS line

[QOJ6555] The 2nd Universal Cup. Stage 5. J : Sets May Be Good

先给 EI 磕三个 首先考虑用 \(n\) 个变量 \(x_1,x_2,\cdots,x_n\in\{0,1\}\) 表示第 \(i\) 个点选不选,那么导出子图的边数的奇偶性就是 \[f(x_1,x_2,\cdots,x_n)=\left(\sum_{(i,j)\in E}x_ix_j\right ......
Universal Stage 6555 Good Sets

asp.net core signalr 客户端调用服务端方法报:Error:Failed to invoke 'adduserToConnection' due to an error on the server

TS端调用方法为: connection.start() .then(() => { connection.invoke("adduserToConnection",account,connection.connectionId); }) .catch((err) => { console.erro ......

CF1257E The Contest

用桶存,做一遍前缀和,令 \(b_{x,y}\) 表示序列 \(x\) 包含 \(1\sim y\) 的数字个数。考虑枚举第一个序列保留的前缀 \(1\sim i\),对于第三个序列,如果其保留了后缀 \(j\sim n(i<j)\),考虑哪些数需要被移掉,那么答案就是: \[b_{1,n}-b_{ ......
Contest 1257E 1257 The CF

The 2nd Universal Cup. Stage 5: Northern J Sets May Be Good

题解 我们考虑计算 \(\sum_{S\subseteq\{1,2,3,\cdots,n\}} (-1)^{cnt(S)}\),这里 \(cnt(S)\) 表示 \(S\) 集合的导出子图的边数。 我们记 \(x_i=[i\in S]\)。 我们考虑删掉 \(n\) 号点。 注意到如果 \(x_i\ ......
Universal Northern Stage Good Sets

Educational Codeforces Round 150 (Rated for Div. 2) B. Keep it Beautiful

数组 \(a = [a_1, a_2, \cdots, a_n]\) 被称为是美丽的,如果可以将 \([1, x]\) 段移到 \([x + 1, n]\) 段后面,\(x \geq 0\) ,数组可以构成非降序。 现在有一个数组 \(a\) (一开始为空)和 \(q\) 个询问,第 \(i\) 个 ......
Educational Codeforces Beautiful Round Rated

【题解 CF840C & P4448】 On the Bench & 球球的排列

On the Bench 题面翻译 给定一个序列 \(a(a_i\le 10^9)\),长度为 \(n(n\le 300)\)。 试求有多少 \(1\) 到 \(n\) 的排列 \(p_i\),满足对于任意的 \(2\le i\le n\) 有 \(a_{p_{i-1}}\times a_{p_i} ......
题解 amp Bench P4448 4448

Go - Changing the Timing for Running Performance Tests

Problem: You want to run performance tests for a specific duration or a specific number of iterations. Solution: You can increase the minimum duration ......
Performance Changing Running Timing Tests

论文阅读:Knowledge Distillation via the Target-aware Transformer

摘要 Knowledge distillation becomes a de facto standard to improve the performance of small neural networks. 知识蒸馏成为提高小型神经网络性能的事实上的标准。 Most of the previo ......

Nginx配置错误:connect() failed (10061: No connection could be made because the target machine actively refused it) while connecting to upstream

问题描述 今天本打算学一下Nginx反向代理发送请求到OpenResty(其实也就是个Nginx,可以把它理解成Anaconda中的python版本),再通过OpenResty使用Lua脚本向Redis或数据库查找缓存来着,在配环境的时候报了个502错误。 我把我的环境描述下,这样如果有遇到这个问题 ......

ERROR: The Python ssl extension was not compiled. Missing the OpenSSL lib?

CentOS7 pyenv安装Python 3.10.13 报错 yum install -y openssl-devel openssl11-devel openssl11-lib CPPFLAGS="-I/usr/include/openssl11" LDFLAGS="-L/usr/lib64/ ......
extension compiled Missing OpenSSL Python

[914] In Python's datetime library, you can format dates using the strftime() method

In Python's datetime library, you can format dates using the strftime() method. This method allows you to create a formatted string representation of ......
datetime strftime library Python format

[911] Read Data from Google Sheets into Pandas without the Google Sheets API (.gsheet)

ref: Read Data from Google Sheets into Pandas without the Google Sheets API import pandas as pd sheet_id = "1XqOtPkiE_Q0dfGSoyxrH730RkwrTczcRbDeJJpqRB ......
Google Sheets without Pandas gsheet

definition of the convex optimization

A convex optimization problem is one in which the objective and constraint functions are convex, which means they satisfy the inequality \(f_i(\alpha ......
optimization definition convex the of

低水平特征(low-level)高水平特征(high-level),傅里叶光谱高频低频

图像的频率:灰度值变化剧烈程度的指标,是灰度在平面空间上的梯度。 (1)什么是低频? 低频就是颜色缓慢地变化,也就是灰度缓慢地变化,就代表着那是连续渐变的一块区域,这部分就是低频. 对于一幅图像来说,也就是边缘以内的内容为低频,而边缘内的内容就是图像的大部分信息,即图像的大致概貌和轮廓,是图像的近似 ......
特征 水平 level 光谱 high-level

The solution of P9194

10黑寄。 problem & blog 考虑到处理加边并不简单,所以我们可以考虑一个黑点 \(p\),连边\((u,p)(p,v)\)。 考虑在现在这棵树上连个点在原图中有变相连相当于有一个公共的 \(p\) 是它们的邻居。 于是删边操作等价于将一个点的儿子黑点并到父亲黑点上。 为了统计答案我们设 ......
solution P9194 9194 The of

CF837G Functions On The Segments

CF837G Functions On The Segments Functions On The Segments - 洛谷 | 计算机科学教育新生态 (luogu.com.cn) 目录CF837G Functions On The Segments题目大意思路code 题目大意 你有 \(n\) ......
Functions Segments 837G 837 The

D. Monocarp and the Set

D. Monocarp and the Set Monocarp has $n$ numbers $1, 2, \dots, n$ and a set (initially empty). He adds his numbers to this set $n$ times in some order ......
Monocarp and Set the

[908] Implementation of the progress bar in Python

You can implement a progress bar in Python to visually represent the progress of a task using various libraries. One commonly used library for this pu ......
Implementation progress Python 908 bar

[905] The replace() method in Pandas

In Pandas, the replace() method is used to replace values in a DataFrame or Series. You can use this method to replace one or more specified values wi ......
replace Pandas method 905 The

【转载】How to solve the problem that getting timestamp from Mysql database is 8 hours earlier than the normal time

This article introduces the relevant knowledge of "how to solve the problem of obtaining timestamp from Mysql database 8 hours earlier than the normal ......
the timestamp database problem getting

Paper Reading: Drag Your GAN: Interactive Point-based Manipulation on the Generative Image Manifold

为了实现基于 GAN 的交互式的基于点的操作,本文提出了 DragGAN,它解决了监督手柄点向目标移动和跟踪手柄点两个子问题,以便在每个编辑步骤中知道它们的位置。本文模型是建立在 GAN 的特征空间具有足够的区分力以实现运动监督和精确点跟踪的特性之上的,运动监督通过优化潜在代码的移位特征损失来实现的... ......

keep-alive实现tab标签页缓存

标签页缓存 实现效果: 已经打开的tab页签,再次访问不重新加载;关闭tab页签后再次访问,则重新加载 实现技术: keep-alive组件的include属性指定页面缓存 一、修改Main.vue 1、 代码: <keep-alive :include="cachPage"> <router-vi ......
缓存 keep-alive 标签 alive keep

CF1548E Gregor and the Two Painters

Day \(\text{叁拾肆}\)。 DS 写不动了,标题也取不动了www。 类似 Day 1 CF1270H Number of Components,每个连通块中选出一个代表的点。令一个连通块内所有点按照 \(v_{i,j}=\{a_i+b_j,i,j\}\) 排序,对最小的 \(v_{i,j ......
Painters Gregor 1548E 1548 and

Educational Codeforces Round 155 (Rated for Div. 2) B. Chips on the Board

给一个 \(n \times n\) 的棋盘,和两个大小为 \(n\) 的 \(a\) \(b\) 数组。\(a_i\) 代表第 \(i\) 列的权值,\(b_i\) 代表第 \(i\) 列的权值。坐标 \((i, j)\) 的权值为 \(a_i + b_j\) 。 现在需要放若干个芯片和到棋盘上, ......
Educational Codeforces Chips Board Round

Codeforces Round 895 (Div. 3) B. The Corridor or There and Back Again

你在一个向右延申的无限坐标轴上,且你初始在坐标 \(1\) 。有 \(n\) 个陷阱在坐标轴上,第 \(i\) 个陷阱坐标为 \(d_i\) ,且会在你踩上这个陷阱的 \(s_i\) 秒过后发动。这时候你不能进入坐标 \(d_i\) 或者走出坐标 \(d_i\) 。 你需要确定最远的 \(k\) , ......
Codeforces Corridor Again Round There

《Mastering the FreeRTOS Real Time Kernel》读书笔记(7)事件组

FreeRTOS事件组,总而言之就是很多个二进制信号量的集合,通过使用掩码的方式提取每一位,使多个任务共同合作实现比较复杂的功能。 ......
Mastering FreeRTOS 事件 笔记 Kernel

《Mastering the FreeRTOS Real Time Kernel》读书笔记(6)资源管理

7.资源管理(互斥量) 在多任务系统中,如果一个任务开始访问资源,但在从运行状态转换出来之前没有完成访问,则可能会出现错误。如果任务使资源处于不一致状态,则任何其他任务或中断对同一资源的访问都可能导致数据损坏或其他类似问题。 这里的资源管理,应该是指计算机的外设资源,比如LCD显示器,寄存器,内存中 ......