discovery presents channel contest

AtCoder Beginner Contest 288 - C Don't be cycle 删除图中最少的边使得图中无环

# [C - Don't be cycle](https://atcoder.jp/contests/abc288/tasks/abc288_c) **题意** 给定一个 n 个顶点,m 条边的无向图,你需要删除图中的一些边使得图中不存在环 问你需要删除的最少边数? **思路** 考虑连通块的生成树 ......
Beginner AtCoder Contest cycle 288

The 2022 ICPC Asia Regionals Online Contest (II) EJFB

# [The 2022 ICPC Asia Regionals Online Contest (II)](https://pintia.cn/market/item/1571156622976593920) ## E An Interesting Sequence 232323232323 3232 ......
Regionals Contest Online 2022 ICPC

SMU Summer 2023 Contest Round 15

# [SMU Summer 2023 Contest Round 15](https://codeforces.com/group/L9GOcnr1dm/contest/467333) ## [A. AB Balance](https://codeforces.com/group/L9GOcnr1d ......
Contest Summer Round 2023 SMU

SMU Summer 2023 Contest Round 14

# [SMU Summer 2023 Contest Round 14](https://codeforces.com/group/L9GOcnr1dm/contest/467332) ## [A. Potion-making](https://codeforces.com/group/L9GOcn ......
Contest Summer Round 2023 SMU

SMU Summer 2023 Contest Round 13

# [SMU Summer 2023 Contest Round 13](https://codeforces.com/group/L9GOcnr1dm/contest/467330) ## [A. Review Site](https://codeforces.com/group/L9GOcnr1 ......
Contest Summer Round 2023 SMU

SMU Summer 2023 Contest Round 12

# [SMU Summer 2023 Contest Round 12](https://codeforces.com/group/L9GOcnr1dm/contest/467329) ## [A. K-divisible Sum](https://codeforces.com/group/L9GO ......
Contest Summer Round 2023 SMU

AtCoder Beginner Contest 311 - D(思维题)

[toc] ABC 简单题 D 思维题 # [D - Grid Ice Floor](https://atcoder.jp/contests/abc311/tasks/abc311_d) **题意** 给定一个 $n \times m$ 的矩阵,矩阵每个位置上的字符要么是 '.' 要么是 '#',保 ......
Beginner 思维 AtCoder Contest 311

The 13th Northeast Collegiate Programming Contest

## **Problem B. Balanced Diet** 其实就是对每种糖果从大到小的排序后,计算前缀和后再 $O(n)$ 处理,由于最多只有 $n$ 个糖果,所以最大复杂度是 $O(nlogn)$。对于题目给的每种糖果的限制 $limit$ ,就把当前小于 $limit$ 的贡献加到 $ma ......
Programming Collegiate Northeast Contest The

The 2022 ICPC Asia Regionals Online Contest (I) C L A

# [The 2022 ICPC Asia Regionals Online Contest (I)](https://pintia.cn/market/item/1571156622976593920) ## C 统计度的大小,算贡献,特判 $n = 1$ ```c++ #include usin ......
Regionals Contest Online 2022 ICPC

文件解压 //problem/2928 or /contest/1709/problem/3

字符串套 递归 #include<bits/stdc++.h> using namespace std; char s[1005]; int n,i; string work(){ string p; int t = 0; while(++i <= n){ if(s[i] >= '0' && s[i ......
problem contest 文件 2928 1709

AtCoder Beginner Contest 314

# [AtCoder Beginner Contest 314 - AtCoder](https://atcoder.jp/contests/abc314) ## [A - 3.14 (atcoder.jp)](https://atcoder.jp/contests/abc314/tasks/abc ......
Beginner AtCoder Contest 314

AtCoder Beginner Contest 314

# [AtCoder Beginner Contest 314 - AtCoder](https://atcoder.jp/contests/abc314) ## A 3.14 ```c++ void solve() { string s = "3.1415926535897932384626433 ......
Beginner AtCoder Contest 314

AtCoder Beginner Contest 314 A - Ex题解

# AtCoder Beginner Contest 314 ## A - 3.14 嗯,你可以用string 存小数点后的... ## B - Roulette 对于每一个金额,用个vector存 pair 存一个人赌了多少,以及是哪一个人 。 ## C - Rotate Colored Subs ......
题解 Beginner AtCoder Contest 314

Atcoder Beginner Contest 314

# 比赛情况 A 题直接按照题意用字符串输出就行了,很快切掉。 B 题按照题意模拟,但是各种 WA,吃了三发没过先去看 C。 C 题依然是模拟,这道题比较好写一次就过了,回去调 B。 B 题再吃了 3 发罚时终于过了。 先是没有特判输出 0 导致 `vector` 为空 WA/RE。 然后没有注意要 ......
Beginner Atcoder Contest 314

Go - What's the point of one-way channels in Go?

A channel can be made read-only to whoever receives it, while the sender still has a two-way channel to which they can write. For example: func F() <- ......
channels one-way point Go What

AtCoder Beginner Contest 214

AtCoder Beginner Contest 214 - AtCoder [ABC214D] Sum of Maximum Weights ( 典 ) 题意:给出一颗 N - 1 条边的树,求树上任意两点间路径上的最大值的和 这种问题考虑每条边单独看贡献,但是刚开始没太想明白怎么计算贡献,后面看 ......
Beginner AtCoder Contest 214

SMU Summer 2023 Contest Round 11(2022-2023 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2022))

# [SMU Summer 2023 Contest Round 11](https://codeforces.com/group/L9GOcnr1dm/contest/466605)(2022-2023 ACM-ICPC Nordic Collegiate Programming Contest ......
Contest 2023 2022 Programming Collegiate

Scientific discovery in the age of artificial intelligence翻译

==**本文全部由ChatGpt翻译,仅供参考**== # Scientific discovery in the age of artificial intelligence 人工智能(AI)正日益融入科学发现中,以增强和加速研究,帮助科学家生成假设、设计实验、收集和解释大规模数据集,并获得可能仅 ......

MuMu模拟器运行一段时间后Device.Present耗时突然上升

1)MuMu模拟器运行一段时间后Device.Present耗时突然上升2)​如何在运行过程中获得温度信息3)Input System鼠标更换主按键的Bug4)如何禁止Unity向https://config.uca.cloud.unity3d.com发送设备信息 这是第347篇UWA技术知识分享的 ......
模拟器 Present 时间 Device MuMu

UESTC 2023 Summer Training #23 for div2/2022-2023 ACM-ICPC Latin American Regional Programming Contest

# Preface 今天这场签到巨多,和昨天那场形成了鲜明的对比 但可惜后盘的时候我划了太久的水,最后接了B题然后没调出来成为战俘 最气的是赛后发现原来是没注意输出格式,本来可以说一遍过的题结果没写过,属实可惜,就当长教训了 **以后一定要尤其注意输入输出格式** # A. Asking for M ......
2023 Programming ACM-ICPC American Regional

AtCoder Beginner Contest 313

AtCoder Beginner Contest 313 A - To Be Saikyo 思路:找到最大的,和第一个比较 #include<bits/stdc++.h> using namespace std; #define int long long //#define int __int12 ......
Beginner AtCoder Contest 313

AtCoder Beginner Contest 313

# [AtCoder Beginner Contest 313 - AtCoder](https://atcoder.jp/contests/abc313) ## [A - To Be Saikyo (atcoder.jp)](https://atcoder.jp/contests/abc313/t ......
Beginner AtCoder Contest 313

Atcoder Grand Contest 058 F - Authentic Tree DP

考虑给 $f(T)$ 赋予组合意义。一个直观的想法是,在每条边中间新建一个节点,然后每次选择一条边对应的点,然后把它删掉,递归剩余的两个部分,但是你会发现这样分母不对,应该是 $n$ 但在这个模型里只有 $n-1$。 考虑魔改这个模型。我们在每个边对应的点下面添加 $998244352$ 个点,你发 ......
Authentic Atcoder Contest Grand Tree

【Rabbitmq】报错:ERROR CachingConnectionFactory Channel shutdown: channel error

[toc] `原文链接:` [【Rabbitmq】报错:ERROR CachingConnectionFactory Channel shutdown: channel error](https://blog.csdn.net/qq_32117641/article/details/13189744 ......

Atcoder Beginner Contest 313

## [C](https://atcoder.jp/contests/abc313/tasks/abc313_c) > ## [D](https://atcoder.jp/contests/abc313/tasks/abc313_d) ## [E](https://atcoder.jp/contes ......
Beginner Atcoder Contest 313

AtCoder Beginner Contest 313

# A - To Be Saikyo ```cpp #include using namespace std; int main(){ ios::sync_with_stdio(0),cin.tie(0); int n; cin >> n; vector a(n); for( auto & i : ......
Beginner AtCoder Contest 313

「解题报告」AtCoder Beginner Contest 313

比赛地址:[AtCoder Beginner Contest 313 - AtCoder](https://atcoder.jp/contests/abc313) 后记:**请正确理解题意后再做题!!!** ## A - To Be Saikyo [A - To Be Saikyo (atcoder ......
Beginner AtCoder Contest 报告 313

AtCoder Beginner Contest (ABC) 313 D-E

Tasks - AtCoder Beginner Contest 313 PS:当时看到D过的比E多就一直在考虑D,但还没做出来,其实个人感觉E比D简单。 D - Odd or Even 交互题。有n个数,最多可以询问n次然后要求判断出这n个数的奇偶性。每次可以询问数组里任意k个元素的和是不是奇数 ......
Beginner AtCoder Contest ABC 313

AtCoder Beginner Contest 313

# AtCoder Beginner Contest 313 ## G - Redistribution of Piles ### 题意翻译: 给定一个数列$a_i(a_i>0, i\in[1,n])$,和一个数$s$(初值为0),有两种操作 - A - 全局非零数减一,减去的和加到$s$ - B ......
Beginner AtCoder Contest 313

AtCoder Beginner Contest 313 A-E Code

比赛链接:AtCoder Beginner Contest 313 - AtCoder A: #include <bits/stdc++.h> using namespace std; int main() { cin.tie(0); ios::sync_with_stdio(false); int ......
Beginner AtCoder Contest Code 313