increasing decreasing 1864a and

CF1592F Alice and Recoloring

CF1592F1 Alice and Recoloring 1 CF1592F2 Alice and Recoloring 2 Part1 很容易发现,其实二和三操作是没有用的. 对于二操作,可以用一操作进行类似于求二维前缀和的方式实现,需要进行一操作至多 \(2\) 次,花费为 \(1+1=2\) ......
Recoloring 1592F Alice 1592 and

Water Pollution: The defination, types, causes, effects and meatures.

What is water pollution? Water pollution can be defined in many ways. Usually, it means one or more substances have built up in water to such an exten ......
defination Pollution meatures effects causes

BWT and FM-index

目录概Burrows-Wheler Transform (BWT)编码性质解码FM-index直观但简陋的方式更高效的方式代码 Langmead B. Burrows-Wheeler transform and FM Index. burning-BWT算法浅析-(一) 概 有趣的编解码. Burr ......
FM-index index BWT and FM

3 ways light pollution harms the planet - and what we can do about it

Light pollution not only impacts the environment, but our health too. ·Global light pollution has increased by 49% over 25 years to 2017, new research ......
pollution planet light harms about

Indoor air pollution: What causes it and how to tackle it

Most people think of air pollution as something that comes from factories or motor vehicles. However, did you know that the air inside your home or pl ......
pollution Indoor causes tackle What

VS and C++ Versions

VS版本 VC版本 ToolSet 版本 MSC版本 Visual Studio 6 6 1200 Visual Studio 2003 7 1300 Visual Studio 2005 8 80 1400 Visual Studio 2008 9 90 1500 Visual Studio 20 ......
Versions and VS

Commands and Queries 设计模式详解

在Angular应用开发领域,Commands and Queries 设计模式是一个关键的概念,它有助于有效地管理应用程序的状态和与后端的交互。本文将深入探讨这一设计模式的核心要点,并通过实际示例来加以说明。 基本概念 命令 (Commands) 命令代表了一项能够改变系统状态的操作,通常通过向后 ......
设计模式 Commands Queries 模式 and

CF375E Red and Black Tree

看错题看成只能交换相邻节点颜色了/fn 每次操作交换两个节点颜色,可以转化为统计最终合法颜色序列相比开始,最少有多少个红点变成黑点。 可以考虑一个类似树形 dp 的过程,对于每个节点我们钦定下它会被哪个节点“笼罩”,同时由于黑点数量有限,我们还需要记录下子树内已经用了多少个黑点。 设“笼罩”节点 \ ......
Black 375E Tree 375 Red

Asya And Kittens

prologue 大水题 analysis 我们要维护连通块,题目给的样例解释也很清楚,就是让我们将两个连通块合并。 我们之后只需要用一个链表来维护头尾就好了。 这个过程直接用并查集维护就好了。 code time #include <bits/stdc++.h> using namespace s ......
Kittens Asya And

Chromium Trace and Perfetto使用详解

1. Trace chromium 在 base 库中提供了 base::trace_event::TraceLog 类,该类是 TRACE_EVENT* , TRACE_COUNTER* 等宏的底层实现,关于这些宏定义见 base/trace_event/common/trace_event_co ......
Chromium Perfetto Trace and

【论文阅读笔记】【Referring & Grounding】 Ferret: Refer and Ground Anything Anywhere at Any Granularity

读论文思考的问题 论文试图解决什么问题? referring 和 grounding 是图片空间信息理解的两大方面,而以往的模型通常只关注于其中的一个方面 能否根据人类理解图片的能力,将 referring 和 grounding 的能力统一到一个模型中? 如何联合这两个任务?它们能相互促进吗? 如 ......

CF596B Wilbur and Array题解

同步发布与洛谷(太懒了不想写东西直接搬过来了(((逃 ) 原题链接 简单贪心。 题意 求一个起始全为 \(0\) 的数列 \(a_1,a_2 \cdots a_n\) 每次可以选择一个数 \(i\) 使 \(a_i \cdots a_n\) 都加上或减去 \(1\),求修改成给定的序列 \(b_1, ......
题解 Wilbur Array 596B 596

SAP: 1、Large time difference between application server and database. 求解决

1、Large time difference between application server and database. 请解决 环境: WIN2003(X64) + SQL SERVER2008 + SAP ECC6 EHP7 ......

[UVA12683] Odd and Even Zeroes

Description 给出 \(n\),求出 \(0!, 1!, 2! \ldots, n!\) 中有几个末尾有偶数个 \(0\)。 \(1\le n\le 10^{18}\)。 Solution 根据基本结论,一个数末尾 \(0\) 的个数等于该数有几个因数 \(5\)。而一个数的阶乘末尾有几个 ......
Zeroes 12683 Even UVA Odd

CF868E Policeman and a Tree

感觉,好自然啊! 想法 dp,想办法分解这个博弈的过程。发现警察会从一片叶子到另一片叶子,在叶子抓住小偷时所有小偷可以全树乱走。因此 dp:\(f_{u, i}\) 表示警察位于 \(u\),全树剩余 \(i\) 个小偷时的答案。 因为两边都绝对理性,小偷在警察离开叶子后不会移动并位于多片叶子上。考 ......
Policeman 868E Tree 868 and

QOJ # 4424. Babushka and her pierogi

有 $n$ 个数 $a_i$,要换成 $b_i$,保证 $a$ 中数互不相同且 $a,b$ 数集相同。交换 $a_x,a_y$ 的费用是 $|a_x-a_y|+C$,$C$ 是常数。求将 $a$ 变换成 $b$ 的最小费用。$n\leq 2\times 10^5$。 ......
Babushka pierogi 4424 QOJ and

Practice Assessment for Exam AZ-400: Designing and Implementing Microsoft DevOps Solution

https://learn.microsoft.com/en-us/credentials/certifications/exams/az-400/practice/assessment?assessment-type=practice&assessmentId=56 The most secure ......

kernel function: the difference beween cdev_add and device_create

To use a character driver, first you should register it with the system. Then you should expose it to the user space. 1. cdev_init and cdev_add functi ......

A piece of code for loading and caching Skeleton Animation in IO task [Cocos2dx.3.17.2]

/**************************************************************************** Copyright (c) 2017-2018 Xiamen Yaji Software Co., Ltd. http://www.cocos2 ......
Animation Skeleton Cocos2dx caching loading

GraphPrompt: Unifying Pre-Training and Downstream Tasks for Graph Neural Networks

目录概符号说明GraphPrompt代码 Liu Z., Yu X., Fang Y. and Zhang X. GraphPrompt: Unifying pre-training and downstream tasks for graph neural networks. WWW, 2023. ......

[925] GDA2020_MGA and change the spatial reference in ArcGIS Pro

ZONE50: 114.0 120.0 - arcpy.mp.spatialReference("GDA2020_MGA_Zone_50") ZONE51: 120.0 126.0 - arcpy.mp.spatialReference("GDA2020_MGA_Zone_51") ZONE52: ......
reference spatial ArcGIS change 2020

How To Clear Quick Access And Recent File And Folders In Windows 10

How To Clear Quick Access And Recent File And Folders In Windows 10 Here are the instructions to clear the Quick Access and Recent Files and Folders c ......
And Folders Windows Access Recent

CF1886D Monocarp and the Set

Link 此题目可以从两个方向考虑,正着和倒着,倒着考虑比较容易,首先把所有的数放到一块,如果是'<'或者'>',就是去掉最左边或者最右边的数,这样显然只有一种可能,答案不变。 如果是'?',那么显然可以去掉中间的任意一个,所以答案就是\(\times l-2\),那么对于\(s_n-i\)位置的\ ......
Monocarp 1886D 1886 and Set

UniKGQA Unified Retrieval and Reasoning for Solving Multi-hop Question Answering Over Knowledge Graph

目录概主要内容代码 Jiang J., Zhou K., Zhao W. and Wen J. UniKGQA: Unified retrieval and reasoning for solving multi-hop question answering over knowledge graph ......

Open Domain Question Answering Using Early Fusion of Knowledge Bases and Text

目录概主要内容代码 Sun H., Dhingra B., Zaheer M., Mazaitis K., Salakhutdinov R. and Cohen W. W. Open domain question answering using early fusion of knowledge ......
Answering Knowledge Question Domain Fusion

论文阅读:Unifying Large Language Model and Knowledge Graph:A RoadMap

1 Introduction 大模型和知识图谱结合的综述。 简单介绍一下大模型和知识图谱的优缺点: 如上所示。 本文主要划分为三个模块,分别为: KG-enhanced LLMs LLM-augmented KGs Synergized LLM + KG 2 Background 主要介绍了LLM和 ......
Knowledge Unifying Language RoadMap 论文

The JSON value of length n is too large and not supported

https://github.com/dotnet/runtime/issues/39953 I'm referring to this issue #30746 that was closed with limit of 125MB staying fixed opposed to being c ......
supported length value large JSON

Diagnostic Port on Electronic Engine and Transmission

Diagnostic ConnectorTest the Connection to the ECM using cat et diagnostic kit ToolkitDeutsch Connectors (6/9-Pin)NOTE: On the Deutsch 9-pin SAE Stand ......

npm ERROR. node-sass and python

当前 install package 出现以下错误时 node-sass check python checking for Python executable "python2" in the PATH 建议安装 python@2 和 node@14 后再 install package. 下载 ......
node-sass python ERROR node sass

CF1100E Andrew and Taxi

套路题又来咯,最大值最小先直接上个二分答案\(lim\) 对于图中的边,若它的权值\(>lim\)的话这条边的方向就确定了,那么直接把这些边连出来跑个拓扑排序看看有没有环即可 如果有环则当前答案一定不合法,否则我们总存在如下的构造方法: 先把权值\(>lim\)的边得到的图的拓扑序搞出来,对于所有权 ......
Andrew 1100E 1100 Taxi and