tenzing 1842f tree and
Signals and systems(1)
LEC 1 Introduction Signals Continuous signals EX1.Sound signals \(y = x(t)\) Continuous Time signal() One dimension signal(only have one variable time ......
LuoguCF362B Petya and Staircases 题解
分析 简单排序题。 首先 Petya 可以通过跨过一个台阶和两个台阶保证不经过脏台阶,但是不可以通过跨过三个台阶来保证不经过脏台阶,所以只要看有没有连续的三个脏台阶即可。 同时,如果第一个台阶和最后一个台阶至少一个是脏台阶那么就不可以达成。 Accepted Code /*Code By Manip ......
[题解]CF1881G Anya and the Mysterious String
思路 发现如果一个字符串中有长度大于等于 \(2\) 回文子串,必定有长度为 \(2\) 的回文子串或长度为 \(3\) 的回文子串,并且形如:aa 和 aba。 所以考虑用线段树这两种情况。维护一段区间的最左、次左、最右、次右的元素,同时用两个标记变量 \(f_1,f_2\) 分别表示这个区间中是 ......
[ABC207F] Tree Patrolling 题解
[ABC207F] Tree Patrolling 弱智 DP 题,设 \(f(i,j,0/1/2)\) 表示在点 \(i\),子树中有 \(j\) 个点被覆盖,且 \(i\) 点自身状态是未被覆盖/被自身覆盖/被某个儿子覆盖,然后树上背包更新就行了。 代码: #include<bits/stdc+ ......
AT_tdpc_tree 木 题解
木 弱智 DP 题,直接设 \(f_i\) 表示 \(i\) 子树内染色的方案数,然后每次合并一个点与它的儿子即可(具体而言,因为儿子间独立,所以方案数就是二项式系数)。 需要注意的是因为第一条边可以在任意位置,所以要以每个点为根各 DP 一次。但是这样每条边会被算两次,所以乘以 2 的逆元即可。 ......
Huffman Tree in C
// // main.c // HuffmanTree // // Created by steve xiaohu zhao on 2023/10/18. // #include <stdio.h> #include <stdlib.h> // 定义一个 Huffman Tree 的节点 struc ......
论文阅读 Generalized Focal Loss: Learning Qualified and Distributed Bounding Boxes for Dense Object Detection
原始题目:Generalized Focal Loss: Learning Qualified and Distributed Bounding Boxes for Dense Object Detection 中文翻译:Generalized Focal Loss:学习用于密集目标检测的 Qual ......
CF557D D. Vitaly and Cycle
小清新分类讨论题 首先不难发现这题加边的上界就是\(3\),并且只有当图中一条边没有时才会取得,方案数就是\(C_n^3\) 而一条边不加的情况也很容易,可以先跑个染色看下有没有奇环,如果有的话就直接输出即可 而加两条边的情况也比较简单,当图中都是孤立边和孤立点时(即所有点度数均\(\le 1\)) ......
vue双端算法代码分析、数组转树(tree)结构
let oldArray = [1, 2, 3, 4, 5]; let newArray = [1, 2, 6, 4, 5]; function patch(oldArr, newArr) { let oldStart = 0; let oldEnd = oldArr.length - 1; let ......
Expression #3 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'jira.ji.ID' which is not functionally dependent on columns in GROUP BY clause;only_full_group_by
这个报错的完整信息 Expression #3 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'jira.ji.ID' which is not functionally dependent on ......
Go - Setting Up and Tearing Down Before and After Tests
Problem: You want to set up data and an environment for testing and tear it down after the test is run. Solution: You can create helper functions or u ......
3D Math for Graphics and Game笔记
这个机器人的原点在世界坐标系下的(4.5,1.5),而她右肩膀上的那个灯的模型坐标系为(-1,5),怎样计算这个灯的世界坐标呢? 开始: 获取原点,这个原点为(4.5,1.5) 向右移动一个位置,机器人的"左边"是[0.87,0.50],这样得到的位置为(4,5,1.5) + (-1)X[0.87, ......
ORA-01078: failure in processing system parameters ORA-00093: pga_aggregate_limit must be between 2048M and 100000G
在启动数据库实例时报错: ORA-01078: failure in processing system parametersORA-00093: pga_aggregate_limit must be between 2048M and 100000G 原因: 该报错是由于设置的pga_aggre ......
[题解] CF1790E - XOR Tree
CF1790E - XOR Tree 题意 给定一颗无根树,在可以改变任意一个点的点权操作基础上,让树上任意简单路径的异或和不为 \(0\) ,问最少需要多少次操作。 思路 假设某个点为根,设 \(pre_x\) 为 \(x\) 点到根的树上前缀异或和, \(a_x\) 为 \(x\) 的点权,则 ......
Secure Code Warrior C# Basic OWASP Web Top 10 2017 8: Insecure deserialization, 9: Using Components with Known Vulnerabilities, 10: Insufficient Logging and Monitoring
Last but not least. These set challenges consist of 8: Insecure deserialization, 9: Using Components with Known Vulnerabilities, 10: Insufficient Logg ......
Codeforces Round 892 (Div. 2) B. Olya and Game with Arrays
一系列 \(n\) 个数组,第 \(i\) 个数组的大小 \(m_i \geq 2\) 。第 \(i\) 个数组为 \(a_{m_1}, a_{m_2}, \cdots, a_{m_i}\) 。 对于每个数组,你可以移动最多一个元素到另一个数组。 一系列 \(n\) 个数组的 \(beauty\) ......
[CF1168C] And Reachability
And Reachability 题面翻译 题目描述 Toad Pimple 有一个整数数组 \(a_1,\dots,a_n\)。 当 \(x < y\) 且存在 \(x = p_1 < \dots < p_k = y\) 的数列 \(p\) 满足 \(a_{p_i} \& a_{p_{i+1}} ......
[题解]CF514D R2D2 and Droid Army
思路 首先,可以转化题意,找到一个极长的区间 \([l,r]\) 使得(其中 \(mx_i\) 表示 \([l,r]\) 区间中属性 \(i\) 的最大值): \[\sum_{i = 1}^{m}mx_i \leq k \]显然对于这个东西当 \(l,r\) 发生移动时,是极其好维护的,所以想到双指 ......
Secure Code Warrior C# Basic OWASP Web Top 10 2017 5: Broken Access Control, 6: Security Misconfiguration and 7: XSS vulnerabilities
Learn the ropes or hone your skills in secure programming here. These challenges will give you an understanding of 5: Broken Access Control, 6: Securi ......
Secure Code Warrior C# Basic OWASP Web Top 10 2017 1: Injection Flaws and 2: Broken Authentication vulnerabilities 3: Sensitive Data Exposure and 4: XXE vulnerabilities
Let's continue with some other very common application weaknesses. This set of levels will focus on 3: Sensitive Data Exposure and 4: XXE vulnerabilit ......
Secure Code Warrior C# Basic OWASP Web Top 10 2017 1: Injection Flaws and 2: Broken Authentication vulnerabilities
Let's start with the most critical application weaknesses. These challenges get you the foundations of 1: Injection Flaws and 2: Broken Authentication ......
D. Monocarp and the Set
D. Monocarp and the Set Monocarp has $n$ numbers $1, 2, \dots, n$ and a set (initially empty). He adds his numbers to this set $n$ times in some order ......
Django中出现报错:TypeError: unsupported operand type(s) for /: 'str' and 'str' 时的解决办法
如果遇到上述报错情况 解决办法: 1、点击报错路径,进入源码 2、将' / '替换为' , ' 3、再次运行Django 问题解决。 ......
CF1168C And Reachability
CF1168C And Reachability And Reachability - 洛谷 | 计算机科学教育新生态 (luogu.com.cn) 目录CF1168C And Reachability题目大意思路code 题目大意 给定一个长度为 \(n\) 的数组 \(a\) 。 你可以选择一个 ......
CF1548E Gregor and the Two Painters
Day \(\text{叁拾肆}\)。 DS 写不动了,标题也取不动了www。 类似 Day 1 CF1270H Number of Components,每个连通块中选出一个代表的点。令一个连通块内所有点按照 \(v_{i,j}=\{a_i+b_j,i,j\}\) 排序,对最小的 \(v_{i,j ......
[论文阅读] Exact Feature Distribution Matching for Arbitrary Style Transfer and Domain Generalization
Exact Feature Distribution Matching for Arbitrary Style Transfer and Domain Generalization 论文源码:https://github.com/YBZh/EFDM 1. Introduction 传统的特征分布匹配 ......
Codeforces Round 895 (Div. 3) B. The Corridor or There and Back Again
你在一个向右延申的无限坐标轴上,且你初始在坐标 \(1\) 。有 \(n\) 个陷阱在坐标轴上,第 \(i\) 个陷阱坐标为 \(d_i\) ,且会在你踩上这个陷阱的 \(s_i\) 秒过后发动。这时候你不能进入坐标 \(d_i\) 或者走出坐标 \(d_i\) 。 你需要确定最远的 \(k\) , ......
CF1119F Niyaz and Small Degrees 题解
原题 翻译 首先 \(O(n^2 \log n)\) 的 dp 是 simple 的,我们设 \(dp_{i,0/1}\) 表示以 \(i\) 为根, \(i\) 到 \(fa_i\) 这条边删/不删的最小权值和。转移是一个非常 trick 的问题,只需要假设所有都选 \(dp_{i,0}\) ,然 ......
Secure Code Warrior OWASP Web Top 10 2021 A1-A2 1: Broken Access Control and 2: Cryptographic Failures
Let’s start with the most critical application weaknesses. These challenges get you the foundations of 1: Broken Access Control and 2: Cryptographic F ......