majority 134c arc the

AtCoder Regular Contest 169 (ARC169)

怎么有人 ARC A 卡了半天的? A. Please Sign 考虑 \(i\) 位置上的数,下次它被加到 \(P_i\),再下次被加到 \(P_{P_i}\),因为这个序列有性质 \(P_i<i\),这样加若干轮一定会到达 \(1\)。 令所有的 \(i\) 向 \(P_i\) 连边,则这是一棵 ......
169 AtCoder Regular Contest ARC

"firmwarepasswd": MacOS Firmware Password Management: CHECK and DELETE Macbook Pro Firmware Password from the command line.

Abaels-MacBook-Pro:~ abaelhe$ su Password: bash-3.2# firmwarepasswd -check Password Enabled: Yes bash-3.2# firmwarepasswd -delete Delete Firmware Pass ......

20.Explain how the following reasoning fails to address the complexity of the issue involved, and rebut it. “Sanya is warm all year round and has beautiful beaches,

Round 1: Identifying the Failure in Reasoning Speaker 1 (Student A): Hello, everyone! Let's kick off our discussion by examining the reasoning: "Sanya ......
the complexity following and beautiful

19.Some people say:Face-to-face classes are a better option for college students than online classes. Present possible counterarguments to the claim, rebut it and reaffirm the argument.

Round 1: Presenting Possible Counterarguments Speaker 1 (Student A): Hello, everyone! The claim that face-to-face classes are a better option than onl ......

18.In the academic world, there is a popular phrase "publish or perish." Academics, therefore, always work hard to keep themselves academically alive through publications.

Round 1: Expressing Initial Opinions on "Publish or Perish" Speaker 1 (Student A): Hello, everyone! The phrase "publish or perish" is quite intense, i ......

15.Please retell the parable of The Blind men and An Elephant. What is the moral of the parable? What can we learn from the parable when it comes to critical thinking?

Round 1: Retelling the Parable and Extracting the Moral Speaker 1 (Student A): Hey everyone! So, let's dive into the parable of "The Blind Men and the ......
parable the What Elephant critical

16.What are the basic elements of an argument according to Toulmin Model? How do you evaluate evidences with the intellectual standards?

Round 1: Understanding the Basic Elements of Toulmin Model Speaker 1 (Student A): Hello, everyone! Let's start by discussing the basic elements of the ......

13.How do you understand the statement: Clear thinking is the key to clear writing? 你如何理解这句话:清晰的思维是清晰写作的关键?

Round 1: Interpreting "Clear Thinking is the Key to Clear Writing" Speaker 1 (Analyst A): Greetings, everyone. Our topic today is the statement, "Clea ......
understand the statement thinking 这句话

11.Demonstrate the essentials concerning "Abstract" in research papers,such as features, types, and components.

11.Demonstrate the essentials concerning "Abstract" in research papers,such as features, types, and components. 演示研究论文中关于“摘要”的要点,如特点、类型和组成部分。 Round 1: ......

12.How do you understand the three “C”s(Concise,Clear & Coherent)in an academic Abstract writing?Why are they so important and worthy of a careful study?

Round 1: Understanding the Three "C"s in Academic Abstract Writing Speaker 1 (Researcher A): Greetings, everyone. Today, we're delving into the signif ......

ARC169 B Subsegments with Small Sums 题解

Link ARC169 B Subsegments with Small Sums Question \(x\) 是一个序列,定义 \(f(x)\) 为把序列 \(x\) 切成几段,每段的和不能超过 \(S\) 的最小段数 给出序列 \(A=(A_1,A_2,\cdots,A_N)\) 求: \[\ ......
题解 Subsegments Small with Sums

ARC169 A Please Sign

Link ARC169 A Please Sign Question 给出 长度为 \(n\) 的数组 \(A\),以及长度为 \(n-1\) 的数组 \(P\),满足 \(P_i<i\),\(P\) 标号为 \(2\sim n\) 每一轮操作为 \(A_{P_i} \leftarrow A_i+A ......
Please Sign ARC 169

The 2nd Universal Cup Stage 13: Shenyang A

赛时没有过又为队友拖后腿了。 考虑原限制具有什么性质,可以发现 \(j\) 能接到 \(i\) 后面仅当 \(\text{max}_{S_{i}} \leqslant \text{max}_{S_{j}}\),而当 \(\text{max}_{S_{i}} = \text{max}_{S_{j}}\ ......
Universal Shenyang Stage The 2nd

Play a Melody using the tone() function

原文:Play a Melody using the tone() function | Arduino Documentation Play a melody with a Piezo speaker. LAST REVISION:2023/12/05 22:33 This example sho ......
function Melody using Play tone

ARC169

A 我们定义 \(dp_{dep}\) 为第 \(dep\) 层会对上一层产生多少的影响。 如果有一层的影响大于 \(0\),在足够次计算后那么肯定是正号。如果小于零那就一定是负号。 由于越久影响到的,对答案的贡献就越大。 所以层数倒叙枚举即可。 code ......
ARC 169

初中英语优秀范文100篇-021Sophia the Robot-机器人索菲亚

PDF格式公众号回复关键字:SHCZFW021 记忆树 1 When it comes to AI , Sophia the robot is mentioned again and again. 翻译 说到人工智能,总是会反复提到机器人索菲亚。 简化记忆 反复 句子结构 句子结构分析: 主句:So ......
机器人 范文 初中 机器 Sophia

[ARC164E] Segment-Tree Optimization 题解

题目链接 题目链接 题目解法 一个自认为比较自然的解法 这种一段序列切成两部分的问题首先考虑区间 \(dp\) 令 \(f_{l,r}\) 为 \([l,r]\) 能构成的最小深度,\(g_{l,r}\) 为在 \(f_{l,r}\) 最小的情况下最少的最大深度的点的个数 转移枚举 \(k\) 即可 ......

ICBCB 生物信息学与计算生物学国际会议(The 10th International Conference on Bioinformatics and Computational Biology,ICBCB 2022)

十届生物信息学与计算生物学国际会议(ICBCB 2022)成功举办 编辑:张谊 来源:生命科学学院 时间:2022年05月20日 访问次数:2197 2022年5月13-15日,由浙江大学生命科学学院主办的第十届生物信息学与计算生物学国际会议(The 10th International Confe ......

ARC121D 1 or 2

题意 你有 \(n\) 个糖果,第 \(i\) 个的价值为 \(a_i\)。 每次操作可以选 \(1\) 或 \(2\) 个糖果。 问在所有的方案中,\(1\) 个或 \(2\) 个糖果的价值之和的最大值和最小值之差最小是多少。 Sol 很有趣的诈骗题。 首先套路的,考虑将选一个的情况变为选一个 \ ......
121D ARC 121 or

Redis报错:(error) DENIED Redis is running in protected mode because protected mode is enabled and no password is set for the default user

一、报错内容 (error) DENIED Redis is running in protected mode because protected mode is enabled and no password is set for the default user. In this mode c ......
protected Redis mode is password

Redis报错:WARNING: The TCP backlog setting of 511 cannot be enforced because /proc/sys/net/core/somaxconn is set to the lower value of 128

报错内容: 1:C 08 Dec 2023 05:47:33.348 # oO0OoO0OoO0Oo Redis is starting oO0OoO0OoO0Oo 1:C 08 Dec 2023 05:47:33.348 # Redis version=7.0.5, bits=64, commit ......
somaxconn enforced WARNING backlog setting

Calculate the geometric mean of inputs a and b. The geometric mean of two numbers is the square root of a * b.

计算输入a和b的几何平均值。两个数字的几何平均值是a * b的平方根。 import java.util.*; import java.io.*; import java.math.*; /** * Auto-generated code below aims at helping you pars ......
geometric mean Calculate the of

[ARC165E] Random Isolation 题解

题目链接 点击打开链接 题目解法 略有些套路的概率题,不过中间的把操作序列看成排列的操作还是很妙的 首先套路的考虑期望的线性性,有两个方式:把贡献放在点上或点集上,这里采用后面的方式做 对于每一个树上的集合 \(S\),假设大小为 \(n\),相邻的点为 \(m\) 考虑这个集合独立的限制为:相邻的 ......
题解 Isolation Random 165E ARC

Atcoder-ARC165F-Make Adjacent

ARC 165 - F - Make Adjacent Statement 给定一个长度为 \(2n\) 的数列 \(a\) ,其中对于每个数 \(i \in [1,n]\),恰好在 \(a\) 中出现两次。每次可以将两个相邻的数交换。最后要求 \(\forall i \in [1,n] : a_{ ......
Atcoder-ARC Adjacent Atcoder F-Make Make

The kexec-based Crash Dumping Solution (翻译 by chatgpt)

原文:https://www.kernel.org/doc/html/latest/admin-guide/kdump/kdump.html 这份文档包括概述、设置、安装和分析信息。 概述 Kdump 使用 kexec 快速引导到一个转储捕获内核,每当需要对系统内核的内存进行转储(例如系统发生崩溃) ......
kexec-based Solution Dumping chatgpt Crash

ARC076D Yakiniku Restaurants

题意 有 \(n\) 个商店。每个商店有 \(m\) 个物品。每个物品的价值为 \(b_{i, j}\)。每种物品只能被购买一次。 你可以选择一个起点,在任意商店结束购买。获得的价值为 \(m\) 个物品之和减去路程。 求最大可获得的价值。 \(n \le 5e3, m \le 200\) Sol ......
Restaurants Yakiniku 076D ARC 076

LOEUF (the loss-of-function observed/expected upper bound fraction) 和 pLI (probability of being Loss-of-function Intoleran)

LOEUF (the loss-of-function observed/expected upper bound fraction): LOEUF is a conservative estimate of evolutionary selection against disease-causin ......

The Main Idea of Basic Dynamic Programming Side A

Front 对 zjk 的 Basic Dynamic Programming Side A 的补充、总结以及 Code。 Side A: DP 状态设计。 常见的 DP 状态 树 树上 DP 常见的状态是考虑子树内的情况,然后通过子树的状态向上合并。复杂度一般是 \(O(n^3)\) ,一些特殊的 ......
Programming Dynamic Basic Main Idea

ARC121E Directed Tree

ARC121E Directed Tree 有意思的容斥加树 dp。 思路 \(a_i\) 可以是除去 \(i\) 祖先之外的所有点,考虑 \(a_i\) 的逆排列。 每一个 \(i\) 在正排列里都可以被不是自己子树内的点选择,那么逆排列里 \(i\) 不可以放自己子树内的点(不包括自己)。 现在 ......
Directed 121E Tree ARC 121