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salesforce零基础学习(一百三十四)State And Country/Territory Picklists启用后的趣事
本篇参考: https://help.salesforce.com/s/articleView?id=sf.admin_state_country_picklists_overview.htm&type=5 背景:提起 State And Country/Territory Picklist这个功能 ......
[AGC052C] Nondivisible Prefix Sums 题解
题目链接 点击打开链接 题目解法 好题! 一个序列是不合法的,必定满足某些结论,我们不妨猜测一下 首先如果和为 \(P\) 的倍数,必定不合法 然后手玩几个可以发现,最极限的情况是 \(P-1\) 个 \(1\;+\;\) \(b_i\; + \;\) \(P-b_i\) 如果在这个情况下再加一个 ......
深圳大学数据库实验一Database Command and SQL
一、实验目的: 了解DBMS系统的功能、软件组成; 2、掌握利用SQL语句定义、操纵数据库的方法。 二、实验要求: 1、在课外安装相关软件并浏览软件自带的帮助文件和功能菜单,了解DBMS的功能、结构; 2、创建一个有两个关系表的数据库; 3、数据库、关系表定义; 4、学习定义关系表的约束(主键、外键 ......
[LeetCode] 1685. Sum of Absolute Differences in a Sorted Array
You are given an integer array nums sorted in non-decreasing order. Build and return an integer array result with the same length as nums such that re ......
CF1846E2 Rudolf and Snowflakes (hard version) 题解
题意: \(T\) \((\)\(1\) \(\le\) \(T\) \(\le\) \(10^4\)\()\) 组询问:是否存在一个满 \(k\) (\(k\) \(\ge\) \(2\)\()\) 叉树节点数恰好为 \(n\) \((\)\(1\) \(\le\) \(n\) \(\le\) \ ......
dns and forward proxy
forward proxy & reverse proxy https://zhuanlan.zhihu.com/p/163948996 https://netnut.io/forward-proxy-server/ Definition of a Forward Proxy Server One ......
Codeforces Round 829 (Div. 1)A1. Make Nonzero Sum (easy version)(思维找规律)
先考虑无解的情况:当n为奇数时无解 相邻的两个元素一定可以变成0 \[a[i] != a[i + 1]时, 分成[i, i], 和[i + 1, i + 1] \]\[a[i] = a[i + 1]时, 分成[i, i + 1] \]这两种情况对答案的贡献都是0,当n为奇数时我们总会有一个没办法凑成 ......
Problem: A. Tricky Sum
A: 做法: 数据比较小,用求和公式(n+1)*n/2,减去所有2的幂即可 点击查看代码 // Problem: A. Tricky Sum // Contest: Codeforces - Educational Codeforces Round 1 // URL: https://codefor ......
✂️ Copy and Paste Emoji Emoji 表情符号大全
✂️ Copy and 📋 Paste Emoji 👍 Emoji 表情符号大全 搬运自 https://getemoji.com/ 表情符号支持iOS, Android, macOS, Windows, Linux和ChromeOS。复制和粘贴表情符号Twitter, Facebook, Sl ......
llama-factory fine-tuning-3 (conception and technologies explanation)
train method supervised fine-tuning Reward Modeling PPO training DPO training full-parameter partial-parameter LoRA QLoRA command parameter fp16 gradi ......
Mysql - Error 1055: Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'user.nickname' which is not functionally dependent on columns in GROUP BY clause
编写SQL时需要如下错误,即出现错误 ERROR 1055,SELECT列表不在GROUP BY语句内且存在不函数依赖GROUP BY语句的非聚合字段'edusassvc.u.nickname',这是和sql_mode=only_full_group_by不兼容的(即不支持)。 分析问题 1)原理层 ......
神经网络入门篇之深层神经网络:详解前向传播和反向传播(Forward and backward propagation)
深层神经网络(Deep L-layer neural network) 复习下前面的内容: 1.逻辑回归,结构如下图左边。一个隐藏层的神经网络,结构下图右边: 注意,神经网络的层数是这么定义的:从左到右,由0开始定义,比如上边右图,\({x}_{1}\)、\({x}_{2}\)、\({x}_{3}\ ......
SQL中累计求和与滑动求和函数sum() over()用法
sum()函数的升级用法,开窗函数(也叫分析函数)sum() over()一般有三种用法: a、分组求和 b、累计求和 c、滑动求和 我们以一个案例分别看下三种求和场景的SQL代码写法: 一、数据样本 我们的数据样本为一个名叫dws_js_team_gmv的底表,2个表字段依次为team_name( ......
论文:Multistep ahead prediction of temperature and humidity in solar greenhouse based on FAM-LSTM model
Multistep ahead prediction of temperature and humidity in solar greenhouse based on FAM-LSTM model 基于 FAM-LSTM 模型的日光温室温湿度多步提前预测 题目:“Multistep ahead pr ......
CF992E Nastya and King-Shamans
题意 给定一个序列 \(s\),记其前缀和序列为 \(g_i\),\(q\) 次修改。 每次修改后输出任意满足 \(s_i = g_{i - 1}\) 的解。 Sol 前缀和数组,每次答案使 \(s_i \times 2\)。 也就是答案的个数不会超过 \(log\)。 再想,\(s_i - g_{ ......
Computer vision: models, learning and inference
http://www.computervisionmodels.com/ 13.2.3 SIFT detector SIFT 尺度不变特征转换 s a second method for identifying interest points 一个尺度和对应兴趣点定位 14 15 16 ......
activation functions summary and comparision
written in the foreword Any nonlinear function that has good derivative properties has the potential to become an activation function. So here, we wil ......
Drawdown——A New Way of Thinking About and Acting on Global Warming in Mexico
小组成员:张怡婷、郑乔鸿、饶佳欣、程小英 小组分工:集中讨论,共同完成 Introduction In the face of global climate change, countries around the world are confronted with similar challeng ......
CF1901 B Chip and Ribbon 题解
Link CF1901 B Chip and Ribbon Qustion 初始有 \(n\) 个格子,刚开始每个格子都是 \(0\) ,Monocarp 刚开始在一号格子中,并使得 \(a[1]+1\),每一轮,Monocarp 可以进行两个操作 操作 1 ,Monocarp 移动到下一个格子, ......
ABC330 E Mex and Update 题解
Link ABC330 E Mex and Update Question 给一个数组 \(a\),有 \(Q\) 次修改 每次把 \(a_i\) 改成 \(x\) 问每次修改后,不在 \(a\) 数组中的最小非负数时多少 Solution 记录每个 \(a_i\) 出现的次数 \(num\) 每个 ......
2023/11/27,新尝试,try and gain back,happy ,
如图所示,可以安心去上一段时间了哈哈哈,晚饭又没吃,, 自律,吃饭,作息,运动,身体的弹性是有限度的? 哈哈哈,但是尝试有正反馈很开心,虽然可能很小白, 之前一致纠结要不要save这一步,搞得不大清楚,但也能先跑起来试试,哈哈哈 ......
CF1900 B Laura and Operations 题解
Link CF1900 B Laura and Operations Question 给出 \(1,2,3\) 的个数 \(a,b,c\) 可以分别减少两个不同的数,增加一个与两个数都不同的数 问,是否能经过一些操作使得 就剩下 \(1\) 或 \(2\) 或 \(3\) Solution 先考虑 ......
D. Ones and Twos
D. Ones and Twos You are given a $1$-indexed array $a$ of length $n$ where each element is $1$ or $2$. Process $q$ queries of the following two types: ......
Xcode 15 and iOS 17 - Error: DT_TOOLCHAIN_DIR cannot be used to evaluate LIBRARY_SEARCH_PATHS, use TOOLCHAIN_DIR instead
热烈欢迎,请直接点击!!! 进入博主App Store主页,下载使用各个作品!!! 注:博主将坚持每月上线一个新app!! # post install post_install do |installer| # fix xcode 15 DT_TOOLCHAIN_DIR - remove afte ......
Reference and inspiration from China's strategy for addressing water pollution issues in Africa
According to China's three line one permit measures, we believe that this has a certain reference value for water pollution issues in Africa. The "thr ......
AtCoder 330. E Mex and Update (关于Mex的总结 + TreeSet和优先队列的性能问题
package AtCoder.begin330; import java.util.*; class Main5 { /** * 总结 : mex的取值范围跟数据长度有关, 而跟元素取值范围无关 * * 思路 : 首先我们只需要用TreeSet维护0 -> N就好了, 我们答案一定在0 -> N中 ......
CaltechCS122 笔记:Assignment 2: SQL Translation and Joins
Assignment 2: SQL Translation and Joins Translation and join PlanNode 及其子类,如图所示: ......
[ARC168E] Subsegments with Large Sums
题目链接 看到严格选 \(k\) 个,不难想到 WQS二分。定义 \(f(x)\) 为分成 \(x\) 段,最多有多少个超过 \(S\) 的。然后你会发现他不是凸的。因为他有很多平段,比如把两个很小的合并不改变答案。 换个方向? 考虑定义 \(f(x)\) 为有 \(x\) 个超过 \(S\) 的段 ......