majority 134c arc the

APP - Appium-Inspector连接报错Failed to create session, The requested resource could not be found

APP - Appium-Inspector连接报错Failed to create session, The requested resource could not be found appium版本:Appium-Server-GUI-windows-1.22.3-4 Appium-Inspe ......

[ARC150F] Constant Sum Subsequence

Problem StatementWe have a sequence of positive integers of length $N^2$, $A=(A_1,\ A_2,\ \dots,\ A_{N^2})$, and a positive integer $S$. For this sequ ......
Subsequence Constant 150F ARC 150

RuntimeWarning: More than 20 figures have been opened. Figures created through the pyplot interface

问题描述 使用 matplotlib 绘制多幅图出现如下问题 RuntimeWarning: More than 20 figures have been opened. Figures created through the pyplot interface (matplotlib.pyplot. ......

How to Restore ASM Based OCR After Complete Loss of the CRS Diskgroup on Linux/Unix Systems (Doc ID 1062983.1)

In this Document Goal Solution References APPLIES TO: Oracle Database - Enterprise Edition - Version 11.2.0.1.0 and later Oracle Database Cloud Schema ......
1062983.1 Diskgroup Complete 1062983 Restore

题解 P2903 【[USACO08MAR]The Loathesome Hay Baler S】

posted on 2021-05-03 20:50:49 | under 题解 | [source](https://www.luogu.com.cn/blog/_post/331434) 首先输入,记录一下哪个齿轮的位置在 $(0,0)$,哪个在 $(x_t,y_t)$。 接着,为了避免多次判断 ......
题解 Loathesome P2903 Baler USACO

CF1466I The Riddle of the Sphinx

### 基本思路 明示了在二进制下考虑问题,我们大体的思路就是从高往低依次确定最大的数二进制下每一位上的值。 以下所述的「前缀」均指一个二进制数从高位到低位的一部分,一个元素的「前 $k$ 位」表示二进制从高位到低位的前 $k$ 位,$res$ 表示当前记录的最大前缀的长度。 先看看操作能干嘛,一是 ......
Riddle Sphinx 1466I 1466 The

what is the embeddings in AI?

What are embeddings? Text embeddings are a natural language processing (NLP) technique that converts text into numerical vectors. Embeddings capture s ......
embeddings what the is AI

CodeForces 1810G The Maximum Prefix

[洛谷传送门](https://www.luogu.com.cn/problem/CF1810G "洛谷传送门") [CF 传送门](https://codeforces.com/problemset/problem/1810/G "CF 传送门") 感觉是比较 educational 的题。 拿到 ......
CodeForces Maximum Prefix 1810G 1810

SPOJ 2878 KNIGHTS - Knights of the Round Table

## [SPOJ 2878 KNIGHTS - Knights of the Round Table](https://www.spoj.com/problems/KNIGHTS/) > **注**:本题大多数网上题解是写的洛谷的链接,但洛谷现在无法做判题操作,提示`Unkwon Error`,只好 ......
KNIGHTS Knights Round Table SPOJ

The Take-out Management Platform

# The Take-out Management Platform ## 1.Project Introduction Before we start develop this project: ​ As a software engineer ,we should know: 1. The pr ......
Management Take-out Platform Take The

Atcoder ARC058E Iroha and Haiku

题目中的式子转化一下即存在一位 $i$ 使得到 $i$ 时的后缀和存在 $X + Y + Z, Y + Z, Z$,再发现 $X + Y + Z\le 17$,考虑状压。 设 $f_{i, j}$ 为填了 $i$ 个数当前后缀和中存在的数的状态为 $j$(只存 $0\sim X + Y + Z$ 的 ......
Atcoder Iroha Haiku 058E ARC

Impact of SBS/HVA/CRM Modified Asphalt on the Moisture Stability of Recycled Hot-mix Asphalt Mixtures

SBS/HVA/CRM改性沥青对再生沥青混合料水稳定性的影响 Impact of SBS/HVA/CRM Modified Asphalt on the Moisture Stability of Recycled Hot-mix Asphalt Mixtures 武汉工程大学 土木工程与建筑学院 ......
Asphalt Stability Modified Mixtures Moisture

How to Delete a User from the Command Line

How to Delete a User from the Command Line Steven Vona, March 22, 2019 When running a Linux system it is always best practice to delete unnecessary us ......
Command Delete User Line from

ARC134F Flipping Coins

pb 讲课没讲的题,感觉很牛逼啊!但不是牛逼在多项式,因为多项式大家应该都会。 考虑从前往后扫的过程,只要有正面就翻成反面,所以最后只有可能是当 $p_i #define int long long using namespace std; namespace vbzIO { char ibuf[( ......
Flipping Coins 134F ARC 134

Atcoder ARC058B Iroha and a Grid

考虑从第 $b$ 列与第 $b + 1$ 之间分开这个矩阵,钦定 $(i, b)$ 下一步必须走到 $(i, b + 1)$,可以发现这样是不会漏算或算重的。 于是就可以用乘法原理算出这个 $i$ 的贡献:$\binom{(i - 1) + (b - 1)}{i - 1}\times \binom{ ......
Atcoder Iroha 058B Grid ARC

ARC125F Tree Degree Subset Sum

感觉挺不错的一道题,不过课上 pb 好像没有讲。 显然树的具体形态对题目影响不大,那么我们知道 $\sum\limits_{i=1}^nd_i=2n-2$ 即可扔掉树的条件。即: > 给定 $n$ 个 $d_i$,和为 $2n-2$,求 $(x,y)$ 满足 $0\le x\le n$ 且 $\ex ......
Degree Subset 125F Tree ARC

The 2023 Guangdong Provincial Collegiate Programming Contest(2023广东省赛)

链接:[https://codeforces.com/gym/104369](https://codeforces.com/gym/104369) ## A. Programming Contest C++ Code ```cpp #include "bits/stdc++.h" using nam ......

map.xml文件报The content of element type "mapper" must match "(cache-ref|cache|resultMap*|parameterMap*

出现这个问题 是因为 <insert></insert> <delete></delete> <update></update> <select></select> 等标签写的不完整 或者写错位置了 比如<insert></insert>只写了一个,没有写结尾</insert> 或者<insert> ......
quot cache parameterMap cache-ref resultMap

【大联盟】20230701 传送(b) QOJ1878 【No Rest for the Wicked】

## 题目描述 [here](https://qoj.ac/problem/1878)。 ## 题解 考虑一条路径上只有 $a$ 的前缀 $\max$ 才是有用的,不妨考虑按照前缀 $\max$ 来划分。可以发现,这些连续段直接存在单向边连接。 现在,我们考虑如何求出这些连续段。一个点 $i$ 可以 ......
大联盟 20230701 Wicked 1878 Rest

[ABC310G] Takahashi And Pass-The-Ball Game

Problem StatementThere are $N$ Takahashi. The $i$-th Takahashi has an integer $A_i$ and $B_i$ balls. An integer $x$ between $1$ and $K$, inclusive, wi ......
Pass-The-Ball Takahashi 310G Pass Ball

ERROR 1709 (HY000): Index column size too large. The maximum column size is 767 bytes.

MySQL版本5.6.35 在一个长度为512字符的字段上创建unique key报错 CREATE DATABASE dpcs_metadata DEFAULT CHARACTER SET utf8; select * from information_schema.SCHEMATA; + + + ......
column size maximum ERROR Index

LLM is all you need for the backend

一、LLM给软件开发范式带来了什么改变? 人们一直在说Github Copilot将取代程序员。我们认为这是错误的。我们已经有了类似GPT-4这种强大的LLM模型,却还要把自己限制在编写传统代码上吗?不!所有代码都有bug! 代码不是对业务逻辑进行编码的理想方式,代码必须经过审查,并且它按照程序员的 ......
backend need LLM all for

what is the retrievers in LangChain?

see: Retrievers | 🦜️🔗 Langchain https://blog.langchain.dev/retrieval/ 按文档说的Retriever就是一个接口,可以把和query相关的文档都查询出来,而vectorDB是否成retriever的关键组件之一。 ......
retrievers LangChain what the is

Measuring and Narrowing the Compositionality Gap in Language Models

[TOC] > [Press O., Zhang M., Min S., Schmidt L., Smith N. A. and Lewis M. Measuring and narrowing the compositionality gap in language models. arXiv p ......

Kingbase8: was aborted: ERROR: sorry, too many global temporary relations in backend already. Call getNextException to see other errors in the batch.

==额....今天踩了一个坑,找个半天找到的解决方法== 设置一个会话内最多允许的全局临时表数据和索引的最大文件数量,默认值为32,最小值为1,最大值为1024。这个文件数量并不是实际磁盘看到的文件数目,而是一些依附于这个表的扩展关系文件,比如索引、大对象等。一般情况下,一个全局临时表只会占用参数中 ......

C# 使用EPPlus 操作excel The given key '8' was not present in the dictionary.

使用EPPlus 删除excel中某一个sheet中的几列的时候,出现了The given key '8' was not present in the dictionary.的报错; 最开始的写法,是从前往后删除,出现错误//ExcelWorksheet sheet = package.Workb ......
dictionary present EPPlus excel given

AT_arc101_d [ARC101F] Robots and Exits 题解--zhengjun

思路不错。 首先考虑把每个机器人转化为 $(a_i,b_i)$ 两个参数。 表示向左 $a_i$ 步会进入左边的出口,向右 $b_i$ 会进入右边的出口。 > 注:此时其他只能进入唯一的出口的机器人不影响答案,不考虑。 记 $c_i=0/1$ 表示 $i$ 号机器人是进入左边还是右边出口。 然后考虑 ......
题解 101 zhengjun AT_arc Robots

安装 MySQL for Windows 时报错 The configuration for MySQL Server 8.0.34 has failed. You can find more information about the failures in the 'Log' tab. 解决方法

今天在安装 MySQL for Windows 时报错 ```txt The configuration for MySQL Server 8.0.34 has failed. You can find more information about the failures in the 'Log' ......
MySQL configuration information for the

解决./composer.json" does not match the expected JSON schema

如果执行composer install的时候报错 "./composer.json" does not match the expected JSON schema: - name : Does not match the regex pattern ^[a-z0-9]([_.-]?[a-z0-9 ......
composer expected schema match JSON

ARC163D Sum of SCC

### Description 给定 $N,M$,求对于所有 $N$ 个点的,满足恰有 $M$ 条从小连向大的边,即 $\sum\limits_{(u,v)\in E}[u 给竞赛图每个 SCC (强连通分量)缩点后,剩下的是由一条**极长**的链与某些前向边组成的图。 于是 SCC 的数量能够转换 ......
163D ARC 163 Sum SCC