certificate chain trust of
The subtleties of proper B+Tree implementation
Ref https://ayende.com/blog/198241-B/the-subtleties-of-proper-b-tree-implementation ......
C. Removal of Unattractive Pairs
这道题很考验思维。 这道题目我们只需要考虑出现次数最多的字符的个数，分两种情况讨论。 1、如果该字符出现次数超过n/2（这里设为x），那么其他字符和该字符凑成一对进行消除，即剩下的长度为2x-n。 2、如果该字符出现次数低于n/2，那么对于任意字符都有足够的其余字符和他凑成一对进行消除，那么就变成了 ......
20.Explain how the following reasoning fails to address the complexity of the issue involved, and rebut it. “Sanya is warm all year round and has beautiful beaches,
Round 1: Identifying the Failure in Reasoning Speaker 1 (Student A): Hello, everyone! Let's kick off our discussion by examining the reasoning: "Sanya ......
15.Please retell the parable of The Blind men and An Elephant. What is the moral of the parable? What can we learn from the parable when it comes to critical thinking?
Round 1: Retelling the Parable and Extracting the Moral Speaker 1 (Student A): Hey everyone! So, let's dive into the parable of "The Blind Men and the ......
16.What are the basic elements of an argument according to Toulmin Model? How do you evaluate evidences with the intellectual standards?
Round 1: Understanding the Basic Elements of Toulmin Model Speaker 1 (Student A): Hello, everyone! Let's start by discussing the basic elements of the ......
12.How do you understand the three “C”s（Concise，Clear & Coherent）in an academic Abstract writing？Why are they so important and worthy of a careful study？
Round 1: Understanding the Three "C"s in Academic Abstract Writing Speaker 1 (Researcher A): Greetings, everyone. Today, we're delving into the signif ......
Continuous-Time Markov Chain
1. Definitions Definition 1. We say the process \(\{X(t),t\ge0\}\) is a continuous-time Markov chain if for all \(s,t\ge0\) and nonnegative integers ......
A sample of JSON RPC service
This is a sample service program which show how to implement a JSON RPC. The RPC service included two functions which used for RSA sign and verify. If ......
CF1894E Freedom of Choice
CF1894E 数据范围多少有点诈骗 首先考虑 \(m=1\) 的情况 容易发现这个 \(l_i,r_i\leq 10^{17}\) 不是很对劲，因为直觉上感觉如果区间可取范围过大答案就是 \(0\) 我们可以取一个不是那么严格的限制条件来约束他，当 \(r-l>n\) 时，答案肯定是 \(0\)。 ......
Redis报错：WARNING: The TCP backlog setting of 511 cannot be enforced because /proc/sys/net/core/somaxconn is set to the lower value of 128
报错内容： 1:C 08 Dec 2023 05:47:33.348 # oO0OoO0OoO0Oo Redis is starting oO0OoO0OoO0Oo 1:C 08 Dec 2023 05:47:33.348 # Redis version=7.0.5, bits=64, commit ......
Calculate the geometric mean of inputs a and b. The geometric mean of two numbers is the square root of a * b.
计算输入a和b的几何平均值。两个数字的几何平均值是a * b的平方根。 import java.util.*; import java.io.*; import java.math.*; /** * Auto-generated code below aims at helping you pars ......
How to connect two pairs of AirPods to one phone simultaneously
Tech Streaming Home Kitchen Health Style Beauty Gifts Deals More REVIEWS TECH How to connect two pairs of AirPods to one phone simultaneously Written ......
Overview of Machine Learning Methods for Genome-Wide Association Analysis
Overview of Machine Learning Methods for Genome-Wide Association Analysis BIBE2021: The Fifth International Conference on Biological Information and B ......
LOEUF (the loss-of-function observed/expected upper bound fraction) 和 pLI (probability of being Loss-of-function Intoleran)
LOEUF (the loss-of-function observed/expected upper bound fraction): LOEUF is a conservative estimate of evolutionary selection against disease-causin ......
The Main Idea of Basic Dynamic Programming Side A
Front 对 zjk 的 Basic Dynamic Programming Side A 的补充、总结以及 Code。 Side A: DP 状态设计。 常见的 DP 状态 树 树上 DP 常见的状态是考虑子树内的情况，然后通过子树的状态向上合并。复杂度一般是 \(O(n^3)\) ，一些特殊的 ......
cannot find package "fmt" in any of
先说问题，可以创建GO文件，可以运行，但bulid的时候，显示cannot find package "fmt" in any of 问题分析 fmt是go自带的库,不可能找不到啊,那就是路径不对呗,看着网上教程,让配GOROOT为自建了一个文件,在环境变量改了,也生效了,但是 build的时候,会 ......
Illegal mix of collations (utf8mb4_0900_ai_ci,IMPLICIT) MySql字符集及校对规则不一致问题
查询时报错 -- 用于解决报错 > 1267 - Illegal mix of collations (utf8mb4_0900_ai_ci,IMPLICIT) and (utf8mb4_general_ci,IMPLICIT) for operation '=' 这个错误是由于在进行比较操作时涉及 ......
DeepWalk Online Learning of Social Representations
目录概符号说明DeepWalk代码 Perozzi B., AI-Rfou R. and Skiena S. DeepWalk: Online learning of social representations. KDD, 2014. 概 经典的 graph embedding 学习方法. 符号说 ......
kettle从入门到精通 第二十三课 kettle carte 错误（java.lang.OutOfMemoryError: GC overhead limit exceeded，Could not emit buffer due to lack of requests，java heap space）分析
1、Could not emit buffer due to lack of requests（无法发出缓冲区，因为请求不足。） 原因有两点：1）消费者处理数据能力较弱，如表输出步骤。2）消费者没有处理数据，如传递的数据中有字段type=1的数据，这种情况没有处理。 解放方案：针对 1）采用多线程处 ......
selenium.common.exceptions.SessionNotCreatedException: Message: session not created: This version of ChromeDriver only supports Chrome version 103 Current browser version is 106.0.5239.0
pyhon 调selenium报： selenium.common.exceptions.SessionNotCreatedException: Message: session not created: This version of ChromeDriver only supports Chro ......
C. Removal of Unattractive Pairs
原题链接 不知道这个思想叫什么，应该叫结果思想 导论 如果存在一个最长的字符串，我又没有可能把他消掉？ 答案是，只要其他字符的长度大于等于最长字符串的长度，就一定能把他消掉。 所以我们不考虑字符串是怎么消除的，直接看结果。 原因解释如下 1.该最长字符串一定和其他字符相连，则消除操作显然。 2.如果 ......
delphi 提示 Access violation at address 014CA924 in module 'EBD.exe'. Read of address 0D1A0000排查
通过类似 Access violation at address 014CA924 in module 'EBD.exe'. Read of address 0D1A0000 提示查看代码出错的行。 1、开启map project -> options -> Linker -> Map file 选 ......
[LeetCode] 1688. Count of Matches in Tournament
You are given an integer n, the number of teams in a tournament that has strange rules: If the current number of teams is even, each team gets paired ......
Go - two bcrypt hashes of the same password are NOT equal
package main import ( "fmt" "golang.org/x/crypto/bcrypt" ) func main() { password := "abcdef" hashedPassword1, _ := bcrypt.GenerateFromPassword([]byte ......
TypeError: Cannot read properties of undefined (reading 'tapPromise')
TypeError: Cannot read properties of undefined (reading 'tapPromise') 这个是当前的webpack版本不合适 尝试给devDependencies添加一个特定的webpack版本然后执行安装在启动就好了 devDependencie ......
B - Buy One Carton of Milk
B - Buy One Carton of Milk https://atcoder.jp/contests/abc331/tasks/abc331_b 思路 dfs递归搜索， 按照依此按照三种策略： 6个一打 - cost S 8个一打 - cost M 12个一打 - cost L 递归到叶子节 ......
C - Sum of Numbers Greater Than Me
C - Sum of Numbers Greater Than Me https://atcoder.jp/contests/abc331/tasks/abc331_c 思路 由于 值 可以是重复的， 需要记录每出现的值 对应的位置 ， 记录在 map<int, vector<int>> valpo ......
Theory Of Computation
LN1 Alphabets and Strings An alphabet is a set of symbols String: a sequence of symbols from some alphabet Language: a set of strings Unary numbers al ......