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PANDACU: second hand luxury bag and wallet bags designer used leather branded bags wholesale

PANDACU is a reputable wholesale supplier specializing in second-hand luxury bags and wallets. They offer a wide selection of designer used leather ba ......
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CF519E A and B and Lecture Rooms

[题目链接](https://codeforces.com/problemset/problem/519/E) # 题目 见链接。 # 题解 **知识点:倍增,LCA,树型dp。** 要找到距离两点 $u,v$ 相同的点个数,我可以分类讨论: 1. $u,v$ 是同一个点,那么全部点都可以。 2. ......
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C:\Windows\WinSxS 目录是 Windows 操作系统中一个重要的系统目录,它包含了组件存储和组件映像服务(Component Store and Component Based Servicing)的相关文件

C:\Windows\WinSxS 目录是 Windows 操作系统中一个重要的系统目录,它包含了组件存储和组件映像服务(Component Store and Component Based Servicing)的相关文件。 WinSxS 目录主要用于存储操作系统及其组件的多个版本和配置文件。它的 ......
组件 Component Windows 目录 系统

Probabilistic and Geometric Depth: Detecting Objects in Perspective(1)

作者认为单目3D目标检测可以简化为深度估计问题,深度估计不准确限制了检测的性能.已有的算法直接使用孤立实例或者像素估计深度,没有考虑目标之间的集合关系,因此提出了构建预测的目标之间的几何关系图,来促进深度预测. 将深度值划分成若干个区间,然后通过分布的期望来计算深度值,在精度和速度上都取得了不错的性 ......

「解题报告」CF1621G Weighted Increasing Subsequences

比较套路的拆贡献题。 考虑直接枚举那个 $j$,求有多少包含 $j$ 的上升子序列满足这个子序列最后一个数的后面有大于 $a_j$ 的数。 首先对于 $j$ 前面的选择方案是没有影响的,可以直接拿树状数组 DP 一遍得到。后面的过程我们可以找到从后往前第一个大于 $a_j$ 的数的位置 $x$,那么 ......

TransformersandNLPforVideoUnderstanding

[toc] 《Transformers and NLP for Video Understanding》 ## 1. 引言 视频理解和自然语言处理 (NLP) 是人工智能领域的重要方向之一,两者的交叉点也更加明显。近年来,深度学习技术的快速发展为视频理解和 NLP 提供了强大的技术支持。在这篇文章中 ......

Delete vector contents and free up memory in C++

Delete vector contents and free up memory in C++ This post will discuss how to delete the vector’s contents and free up the memory allocated by the ve ......
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"Regexp AND LIKE"优化方法

与大多数数据库一样,MariaDB允许在WHERE子句中使用正则表达式进行查询。虽然这功能很强大,但在数据库中使用regexp的一个问题是它无法利用索引。原因很简单:查询优化器无法理解正则表达式,也无法对它们的返回值做出假设。 这篇文章提出了一个微不足道但反直觉的优化,有时可以解决这个限制。 对于下 ......
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What are the differences between in vivo and in vitro testing of drugs for toxicology Studies?

Toxicology is the science of studying the harmful effects of chemical, physical, biological, and other exogenous factors on biological systems. It can... ......

python: Reading and Writing JSON to a File

#import json jsondata = { 'sqlserver': [ { "server": "DESKTOP-NQK85G5\GEOVIN2008", "useid": "sa", "password": "geovindu", "database": "Student" } ], ' ......
Reading Writing python JSON File

Binomial Theorem and Generating Functions

# Binomial Theorem Let $n$ be a nonnegative integer. Then $$ \sum_{k=0}^n 2^k\left(\begin{array}{l} n \\ k \end{array}\right)=3^n $$ Proof: We recogni ......
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CF1515G Phoenix and Odometers

有点神仙的。 ## 题意 给定一张 $n$ 个点 $m$ 条边的有向图,有边权,进行 $q$ 次询问($n,m,q\le 2\times 10^5$,边权为不超过 $10^9$ 的正整数)。 每次询问给定三个参数 $v,s,t(0\le s using namespace std; using LL ......
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CF794F. Leha and security system

比较水的 *2800,但是考察对标记的理解。 有一个比较原始的思路:因为需要让所有数码为 $x$ 的改成 $y$,我们不难想到这样一个做法:对十进制下第 $1,2,3\ldots$ 位各开一棵线段树,每个节点存区间内每种数码的出现次数 $cnt_i$ ,最后用位值原理合并得到答案。 对于区间修改操作 ......
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CF261E Maxim and Calculator 题解

## 题面翻译 二元组$ (a,b)$,可以变成$ (a,b+1)$或$ (ab,b)$ 你有初始二元组$ (1,0)$,给你区间$ [l,r]$,和一个整数$ p$,在区间内选一个数$ x$,使$ (1,0)$在不超过$ p$步变化后,第一维的值变成$ x$,求$ x$的个数$ (2 #defin ......
题解 Calculator Maxim 261E 261

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## Abstract 背景: 1. decompilers难以恢复注释、variable names, custom variable types 本文: 工具:DIRTY((DecompIled variable ReTYper) 方法: postprocesses decompiled fil ......

dup2 and dup修改和恢复进程的标准输入

`dup2(oldfd, newfd)`. 旧的文件描述符,和新的文件描述符指向同一个文件。 `int ans = dup(oldfd);` 返回值文件描述符和旧的文件描述符指向同一个文件。 通过dup/dup2,可以将多个文件描述符指向同一个文件实体,它们都可以等效得访问同一个文件。 dup2的操 ......
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[20230616]One Deadlock of 'row cache lock' and 'library cache lock'.txt

[20230616]One Deadlock of 'row cache lock' and 'library cache lock'.txt--//链接http://ksun-oracle.blogspot.com/2023/06/one-deadlock-of-row-cache-lock-an ......
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WABCO DIAGNOSTIC KIT (WDI) WABCO Trailer and Truck Diagnostic Interface

Wabco Diagnostic Kit is a universal diagnostic tool designed for maintenance of trailers, trucks and buses. Wabco Diagnostic tool supports most popula ......

Understanding JavaScript Garbage Collection: Dive into Reference Counting and Mark-and-Sweep Algorithms

JavaScript, the programming language of the web, is often praised for its ability to handle memory management automatically. The JavaScript engine's g ......

php解决 mysql_connect(): The mysql extension is deprecated and will be removed in the future: use mysq

The mysql extension is deprecated and will be removed in the future: use mysq 翻译: mysql_connect这个模块将在未来弃用,请你使用mysqli或者PDO来替代。 解决方法: 打开php.ini 配置文件把 di ......

Counting principle and Program Testing

# Reference https://www.shuxuele.com/data/basic-counting-principle.html # 基本计数原理 若有m个方法去做一件事,及n个方法去做另一件事, 则有m×n个方法去做这两件事。 # 应用场景 这个原理只适合在所有选择都是独立时才适用。 ......
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An Introduction to Linux Automation, Tools and Techniques

An Introduction to Linux Automation, Tools and Techniques https://linuxconfig.org/an-introduction-to-linux-automation-tools-and-techniques In the fast ......

CF1770F Koxia and Sequence

一步都没想到,一定是状态不好吧,一定吧一定吧? 加训数数! ## 题意 给定 $n, x, y$,定义好的序列 $\{a_i\}_{i = 1}^n$ 满足 $\sum\limits_{i = 1}^na_i = x, \operatorname{OR}\limits_{i = 1}^na_i = ......
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MATH is the LOGIC OF CERTAINTY and STATISTICS is the LOGIC OF UNCERTAINTIES

Statistics 110 of Harvard University: Math is the logic of certainty, Statistics is the logic of uncertainty. Strategic practice: Clarity; Honesty ......
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python: encode and decode

import binascii geovin=b"geovindu" adu=base64.b64encode(geovin) #加密码 print(adu) edu=base64.b64decode(adu) #解密 print(edu) s=["医疗",400,1] column=('Insur ......
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【题解】CF754D Fedor and coupons(优先队列)

# 【题解】CF754D Fedor and coupons ## 题目链接 [CF754D Fedor and coupons](https://www.luogu.com.cn/problem/CF754D) [CF1029C Maximal Intersection](https://www. ......
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Fourier Analysis and Nonlinear Partial Differential Equations 阅读笔记 (第一章)

# 实分析基础 ## Holder与卷积不等式 首先从经典的Holder不等式入手. **命题: 经典情况下的Holder不等式** >设$(X,\mu)$是测度空间, $(p,q,r)\in[1,\infty]^3$满足 >$$\frac{1}{p}+\frac{1}{q}=\frac{1}{r} ......

csIAHDFPM and csILBFGS

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[数论]Divisor and Gcd

## Divisor and Gcd ### 1、算术基本定理:n的质因数分解唯一 一些常见结论: 1.素数无限 2.$\lim_{n\rightarrow+\infty}n\prod\dfrac{n}{\frac{n}{\ln{n}}}$(Π(n)表示 ab|c$ 3.$a|bc,(a,b) = ......
数论 Divisor and Gcd